Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A drop of water has a volume of about \(0.05 \mathrm{mL}\). How many molecules of water are in a drop of water? (Assume water has a density of \(1.00 \mathrm{g} / \mathrm{cm}^{3} .\) )

Short Answer

Expert verified
There are approximately \(1.67 \times 10^{21}\) molecules in a drop of water.

Step by step solution

01

Convert volume to mass

First, convert the volume of water from milliliters (mL) to grams (g) using the density of water. Since the density of water is given as \(1.00 \text{ g/cm}^{3}\), the mass of water is equal to its volume in grams:\(\text{mass} = 0.05 \text{ mL} \times 1.00 \text{ g/cm}^{3} = 0.05 \text{ g}\)
02

Convert mass to moles

Now, convert the mass of water to moles. Use the molar mass of water, which is approximately \(18.02 \text{ g/mol}\):\(\text{moles of water} = \frac{0.05 \text{ g}}{18.02 \text{ g/mol}} \approx 0.00278 \text{ mol}\)
03

Convert moles to molecules

Finally, calculate the number of water molecules by using Avogadro's number, which is \(6.022 \times 10^{23} \text{ molecules/mol}\):\(\text{number of molecules} = 0.00278 \text{ mol} \times 6.022 \times 10^{23} \text{ molecules/mol} = 1.67 \times 10^{21} \text{ molecules}\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Water Density
Water density is a crucial factor when dealing with the properties of water, such as its mass at a given volume. In the metric system, water density is commonly approximated to be \(1.00 \text{ g/cm}^3\). This means that 1 cubic centimeter (or 1 milliliter) of water has a mass of 1 gram.
This simplification makes it very easy to convert between the volume and mass of water without needing complex calculations. For example, if you have a volume of 0.05 mL of water, like in the exercise, this means you have 0.05 grams of water.
This conversion is particularly handy when dealing with various chemical computations, as it allows you to translate a liquid measurement into a measurable mass amount. This characteristic of water is unique and is tied intimately to its molecular structure and the hydrogen bonding between molecules.
Molar Mass
The concept of molar mass acts as a bridge between the mass of a substance and the amount of substance present.
Molar mass is defined as the mass of one mole of any given substance. For water (\(\text{H}_2\text{O}\)), it is approximately \(18.02 \text{ g/mol}\). This means that one mole of water weighs 18.02 grams.
  • The molar mass is calculated from the atomic masses of the atoms that form the compound.
  • For water, it is the sum of the masses of 2 hydrogen atoms (approximately 1.01 g/mol each) and 1 oxygen atom (approximately 16.00 g/mol).
Understanding molar mass is critical because it allows us to convert grams into moles, which can then be used to relate to numbers of molecules, especially when using Avogadro's number. This is what we need to solve the given problem.
Avogadro's Number
Avogadro's number is fundamental in chemistry, providing the link between the macroscopic world of grams and moles and the microscopic world of atoms and molecules. It tells us that one mole of any substance contains \(6.022 \times 10^{23}\) entities, be they atoms, molecules, or ions.
This constant allows chemists to convert the amount of a substance in moles to the number of molecules, making it possible to quantitatively describe chemical reactions at the molecular level.
  • In the exercise, this number is crucial for determining the number of molecules in a given amount of water (measured in moles).
  • Thanks to Avogadro's number, even very small masses can be easily related to an enormous number of molecules, such as \(1.67 \times 10^{21}\) molecules in a single drop of water.
Thus, Avogadro's number is not just a large number but a key unit conversion factor that bridges different scales in chemical equations and reactions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which of the following pairs of elements are likely to form ionic compounds when allowed to react with each other? Write appropriate formulas for the ionic compounds you expect to form, and give the name of each. (a) chlorine and bromine (b) phosphorus and bromine (c) lithium and sulfur (d) indium and oxygen (e) sodium and argon (f) sulfur and bromine (g) calcium and fluorine

Which of the following compounds (NO, CO, MgO, or CaO) has the highest weight percent of oxygen?

Name each of the following binary, nonionic compounds: (a) \(\mathrm{NF}_{3}\) (b) HI (c) \(\mathrm{BI}_{3}\) (d) \(\mathrm{PF}_{5}\)

A piece of nickel foil, \(0.550 \mathrm{mm}\) thick and \(1.25 \mathrm{cm}\) square, is allowed to react with fluorine, \(\mathrm{F}_{2},\) to give a nickel fluoride. (a) How many moles of nickel foil were used? (The density of nickel is \(8.902 \mathrm{g} / \mathrm{cm}^{3} .\) ) (b) If you isolate 1.261 g of the nickel fluoride, what is its formula? (c) What is its complete name?

Uranium is used as a fuel, primarily in the form of uranium(IV) oxide, in nuclear power plants. This question considers some uranium chemistry. (a) A small sample of uranium metal \((0.169 \mathrm{g})\) is heated to between 800 and \(900^{\circ} \mathrm{C}\) in air to give \(0.199 \mathrm{g}\) of a dark green oxide, \(\mathrm{U}_{x} \mathrm{O}_{y}\). How many moles of uranium metal were used? What is the empirical formula of the oxide, \(\mathrm{U}_{x} \mathrm{O}_{y} ?\) What is the name of the oxide? How many moles of \(\mathrm{U}_{x} \mathrm{O}_{y}\) must have been obtained? (b) The naturally occurring isotopes of uranium are \(^{234} \mathrm{U}\) " \(^{235} \mathrm{U},\) and \(^{238} \mathrm{U} .\) Knowing that uranium's atomic weight is \(238.02 \mathrm{g} / \mathrm{mol},\) which isotope must be the most abundant? (c) If the hydrated compound \(\mathrm{UO}_{2}\left(\mathrm{NO}_{3}\right)_{2} \cdot z \mathrm{H}_{2} \mathrm{O}\) is heated gently, the water of hydration is lost. If you have \(0.865 \mathrm{g}\) of the hydrated compound and obtain \(0.679 \mathrm{g}\) of \(\mathrm{UO}_{2}\left(\mathrm{NO}_{3}\right)_{2}\) on heating, how many molecules of water of hydration are in each formula unit of the original compound? (The oxide \(\mathrm{U}_{x} \mathrm{O}_{y}\) is obtained if the hydrate is heated to temperatures over \(800^{\circ} \mathrm{C}\) in the air.)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free