Chapter 3: Problem 26
Consider the two ionic compounds NaCl and CaO. In which compound are the cation-anion attractive forces stronger? Explain your answer.
Short Answer
Expert verified
CaO has stronger cation-anion attractive forces than NaCl due to its ions with higher charges.
Step by step solution
01
Identify the Ions
Identify the ions present in each compound.
In NaCl (Sodium Chloride), the ions are sodium (Na⁺) and chloride (Cl⁻).
In CaO (Calcium Oxide), the ions are calcium (Ca²⁺) and oxide (O²⁻).
02
Understand Charge Impact
The strength of ionic bonds is greatly influenced by the charge of the ions. Generally, the greater the charge on the ions, the stronger the ionic bond will be.
In NaCl, the ions carry charges of +1 and -1 (Na⁺ and Cl⁻).
In CaO, the ions carry charges of +2 and -2 (Ca²⁺ and O²⁻).
03
Compare Ionic Charges
Compare the charges of the ions in both compounds.
NaCl: The charges are +1 and -1.
CaO: The charges are +2 and -2.
Since CaO has ions with greater charges, its ionic bonds are stronger than those in NaCl.
04
Apply Coulomb's Law
According to Coulomb's Law, the force of attraction between two oppositely charged ions is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
The larger the product of the ion charges, the stronger the force of attraction.
Hence, the Ca²⁺ and O²⁻ ions will experience a stronger attractive force compared to the Na⁺ and Cl⁻ ions due to their higher charges.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cation-Anion Interaction
In ionic compounds, the cation-anion interaction is the foundation of ionic bonding. This type of interaction occurs between positively charged ions called cations and negatively charged ions known as anions.
- The cations and anions are held together by electrostatic forces of attraction.
- This bond forms the ionic lattice in solid-state compounds.
Coulomb's Law
Coulomb's Law is fundamental to understanding ionic bonding and the strength of the electrostatic interactions between ions. It provides a way to calculate the force (\[ F \] ) of interaction between two charges. According to Coulomb's Law:\[ F = k \frac{{|q_1 \, q_2|}}{{r^2}} \] * Here, \( F \) is the force of attraction or repulsion. * \( k \) is Coulomb's constant. * \( q_1 \) and \( q_2 \) are the magnitudes of the charges involved. * \( r \) is the distance between the centers of the two charges.The implication is that the larger the product of the charges \( q_1 \) and \( q_2 \), the stronger the force of attraction between the ions. Additionally, the closer the ions are to each other, the stronger the attraction. In the case of CaO versus NaCl, CaO has a higher product of charges (\(+2\) and \(-2\)) compared to NaCl (\(+1\) and \(-1\)), resulting in a stronger bond strength as predicted by Coulomb's Law.
Charge of Ions
The charge of ions plays a crucial role in determining the strength of ionic bonds.
- Cations have a positive charge, having lost electrons.
- Anions have a negative charge, having gained electrons.