Chapter 20: Problem 73
A "silver coulometer" (Study Question 72) was used in the past to measure the current flowing in an electrochemical cell. Suppose you found that the current flowing through an electrolysis cell deposited \(0.089 \mathrm{g}\) of \(\mathrm{Ag}\) metal at the cathode after exactly 10 min. If this same current then passed through a cell containing gold(III) ion in the form of \(\left(\mathrm{AuCl}_{4}\right)^{-}\), how much gold was deposited at the cathode in that electrolysis cell?
Short Answer
Step by step solution
Calculate Moles of Silver Deposited
Determine Charge Passed Through the Cell
Current Through the Cell
Calculate Moles of Gold Deposited
Convert Moles of Gold to Grams
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Faraday's Law
This law can be expressed mathematically as \( Q = n \times F \), where \( Q \) is the charge in coulombs, \( n \) represents the moles of electrons involved, and \( F \) is Faraday's constant, approximately 96485 C/mol.
- This relationship helps us calculate the amount of metal deposited in an electrolytic process by relating it to the charge that flows through the system.
- For example, in the case of silver deposition, Faraday's Law allows us to determine the charge based on the known mass and molar mass of silver.
- This understanding is crucial for predicting how much of a substance will accumulate during electrolysis.
Electrolysis
During electrolysis, an electric current is passed through an electrolyte, causing ions to move toward their respective electrodes and redox reactions to occur.
- At the cathode, reduction takes place where cations gain electrons and get deposited as metal.
- At the anode, oxidation may result, often involving the loss of electrons from anions.
The exercise involving the deposition of silver and gold ions showcases these principles by illustrating the conversion of metallic ions to their solid metal forms at the cathode.
Coulometer
Coulometers help ensure accuracy by providing precise measurements of the total amount of charge that has passed through a system.
- In the original exercise, the silver coulometer was used to verify the current in an electrochemical cell based on the mass of silver deposited.
- This method relies on the predetermined relationship between charge and mass, where a specific amount of charge results in a predictable amount of material deposition.
- This tool is critical for labs and industries where precise electrochemical calculations are necessary.
Valency
For instance, silver (\(Ag\)) has a valency of +1, meaning each atom requires one electron for reduction. In contrast, gold ions (\((AuCl_4)^-\)) have a valency linked to gold being in the +3 oxidation state, as they require three electrons to be reduced to metallic gold.
When calculating deposition amounts during electrolysis, knowing valency helps determine the required charge and electrons per atom or molecule.
This is key in the original problem, where calculations hinge on the fact that gold ions require more electrons for reduction due to their higher valency relative to silver.
Current Calculation
The current can be calculated using the formula \( I = \frac{Q}{t} \), where \( Q \) is the charge in coulombs and \( t \) is time in seconds. In the given problem, the current was found by measuring the mass of deposited metal and calculating the charge involved.
- A precise understanding of current is essential for predicting the deposition rate and understanding the overall energy consumption of the process.
- In electrochemical cells, maintaining a steady current ensures a consistent output of the deposition process.