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An old method of measuring the current flowing in a circuit was to use a "silver coulometer." The current passed first through a solution of \(\mathrm{Ag}^{+}(\mathrm{aq})\) and then into another solution containing an electroactive species. The amount of silver metal deposited at the cathode was weighed. From the mass of silver, the number of atoms of silver was calculated. since the reduction of a silver ion requires one electron, this value equalled the number of electrons passing through the circuit. If the time was noted, the average current could be calculated. If, in such an experiment, \(0.052 \mathrm{g}\) of \(\mathrm{Ag}\) is deposited during \(450 \mathrm{s}\), what was the current flowing in the circuit?

Short Answer

Expert verified
The current flowing in the circuit was approximately 0.103 A.

Step by step solution

01

Determine Moles of Silver Deposited

First, calculate the number of moles of silver deposited. Use the relation \( \text{moles} = \frac{\text{mass}}{\text{molar mass}} \). The molar mass of silver (Ag) is approximately 107.87 g/mol. Therefore, the moles of Ag deposited are: \( \frac{0.052 \text{ g}}{107.87 \text{ g/mol}} = 4.82 \times 10^{-4} \text{ mol} \).
02

Calculate Number of Electrons Passed Through the Circuit

Since the reduction of one silver ion \((\mathrm{Ag}^+)\) to silver metal \((\mathrm{Ag})\) requires one electron, the number of moles of electrons is equal to the moles of silver deposited. Thus, \( 4.82 \times 10^{-4} \text{ mol} \) of electrons have passed through the circuit.
03

Convert Moles of Electrons to Charge (Coulombs)

Use Faraday's constant, which is approximately 96,485 C/mol, to convert the moles of electrons to total charge. The total charge is \( 4.82 \times 10^{-4} \text{ mol} \times 96485 \text{ C/mol} = 46.5 \text{ C} \).
04

Calculate the Current

Current \( I \) is defined as the charge \( Q \) flowing through the circuit per unit time \( t \). Use the formula \( I = \frac{Q}{t} \), where \( Q = 46.5 \text{ C} \) and \( t = 450 \text{ s} \). Thus, \( I = \frac{46.5 \text{ C}}{450 \text{ s}} = 0.103 \text{ A} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Silver Coulometer
A silver coulometer is a classic device used in electrochemistry to measure the current flowing through an electrical circuit. It operates by depositing a specific metal, in this case, silver, onto an electrode, which is usually the cathode. As electrons flow through the circuit, silver ions in solution gain these electrons and form metallic silver. The amount of silver deposited directly relates to the number of electrons that have passed through the circuit. This number of electrons can be quantified by weighing the deposited silver. This concept utilizes the principle that a precise number of electrons corresponds to a specific amount of a substance, as dictated by Faraday's laws of electrolysis. This method is particularly beneficial for understanding the underlying mechanics of electrochemical reactions, which are crucial in battery technology and other fields of electrochemistry.
Current Calculation
Calculating the current in a circuit involves understanding how charge and time relate. Current, often denoted by the symbol 'I', represents the flow of electric charge over a given period of time, and it is measured in amperes (A). The foundational formula for current is \( I = \frac{Q}{t} \), where \(Q\) represents the total charge in coulombs and \(t\) is time in seconds.
In the context of a silver coulometer, the charge is determined by the amount of silver deposited. First, you calculate the moles of silver, then use Faraday's constant to convert these moles into coulombs of charge. After the total charge is found, it is divided by the total time during which the deposition occurred to find the average current. This method not only gives insight into the electrical properties of the circuit but also enhances our understanding of electrochemical processes.
Electrochemistry
Electrochemistry is a branch of chemistry that focuses on the relationship between electrical energy and chemical changes. It involves the study of reactions where electrons are transferred between molecules, often with the use of an external circuit. Key topics in electrochemistry include:
  • Electrode reactions - where oxidation and reduction occur.
  • Electrolytes - substances that conduct electricity when dissolved in water.
  • Electroplating - the process of depositing a metal onto a surface using an electric current.
  • Batteries - devices that convert stored chemical energy into electrical energy.
Overall, understanding these concepts is essential not only for academics studying chemical processes but also for industries working with batteries, corrosion prevention, and electrolysis.
Faraday's Constant
Faraday's constant is a vital number in electrochemistry that relates the amount of charge carried by one mole of electrons. Its approximate value is 96,485 coulombs per mole (C/mol). This constant allows chemists to convert between moles of electrons and the charge in coulombs. For instance, in a silver coulometer experiment, to find out how many coulombs correspond to a certain mass of deposited silver, Faraday's constant is used. You multiply the number of moles of electrons by 96,485 C/mol to obtain the charge in coulombs.
Faraday's constant is named after Michael Faraday, a pioneering scientist in the field of electromagnetism and electrochemistry, and it remains a cornerstone for calculating and understanding the quantitative aspects of electrochemical reactions.

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Most popular questions from this chapter

voltaic cell is constructed using the reaction \(\mathrm{Mg}(\mathrm{s})+2 \mathrm{H}^{+}(\mathrm{aq}) \longrightarrow \mathrm{Mg}^{2+}(\mathrm{aq})+\mathrm{H}_{2}(\mathrm{g})\) (a) Write equations for the oxidation and reduction halfreactions. (b) Which half-reaction occurs in the anode compartment and which occurs in the cathode compartment? (c) Complete the following sentences: Electrons in the external circuit flow from the ___ electrode to the ___ electrode. Negative ions move in the salt bridge from the ___ half-cell to the ___ half-cell. The half-reaction at the anode is ___ and that at the cathode is ___.

Which product, Ca or \(\mathrm{H}_{2}\), is more likely to form at the cathode in the electrolysis of \(\mathrm{CaCl}_{2} ?\) Explain your reasoning.

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A hydrogen-oxygen fuel cell operates on the simple reaction $$\mathbf{H}_{2}(\mathrm{g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{g}) \longrightarrow \mathrm{H}_{2} \mathrm{O}(\ell)$$ If the cell is designed to produce 1.5 A of current, and if the hydrogen is contained in a 1.0 -L tank at \(200 .\) atm pressure at \(25^{\circ} \mathrm{C},\) how long can the fuel cell operate before the hydrogen runs out? (Assume there is an unlimited supply of \(\left.\mathbf{O}_{2 \cdot}\right)\)

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