Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Acetone, \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\), is quite soluble in water. Explain why this should be so. (EQUATION CAN'T COPY)

Short Answer

Expert verified
Acetone is soluble in water due to hydrogen bonding between its polar carbonyl group and water molecules.

Step by step solution

01

Identify Acetone's Structure

Acetone (\( \mathrm{CH}_3 \mathrm{COCH}_3 \)) is a simple ketone, with the structural formula of \( (\mathrm{CH}_3)_2\mathrm{CO} \). It consists of a central carbonyl group (\( \mathrm{C} = \mathrm{O} \)) bonded to two methyl groups (\( \mathrm{CH}_3 \)).
02

Consider Intermolecular Forces

Water is a polar molecule, known for its hydrogen bonding capabilities. Acetone's carbonyl group is very polar due to the oxygen's high electronegativity, which can form dipole-dipole interactions with water's hydrogen atoms.
03

Describe Solubility Mechanism

The polar interaction between water and acetone is significant. The carbonyl oxygen in acetone can attract the hydrogen in water molecules, leading to hydrogen bonding, a strong intermolecular force contributing to acetone's solubility in water.
04

Assess Solubility in Polar Solvents

Since acetone can hydrogen bond with water, a highly polar solvent, it is soluble due to effective interaction between acetone's polar groups and water molecules, aligning with the principle that 'like dissolves like'.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Intermolecular Forces
Intermolecular forces are the forces of attraction or repulsion between molecules. They are crucial in determining how substances interact and stick together. There are several types of intermolecular forces, but three commonly discussed ones are London dispersion forces, dipole-dipole interactions, and hydrogen bonding. Each type holds molecules together with varying strength.
Water and acetone interact primarily through dipole-dipole interactions and hydrogen bonding. Dipole-dipole interactions occur when the positive end of a polar molecule is attracted to the negative end of another. Acetone, with its polar carbonyl group, can align its negative dipole (oxygen) towards the positive dipole (hydrogen) in water.
These interactions are stronger than London dispersion forces, which occur even between nonpolar molecules, and they are particularly significant in helping acetone to dissolve in water.
Hydrogen Bonding
Hydrogen bonding is a specific and particularly strong type of dipole-dipole interaction that occurs when hydrogen is bonded to highly electronegative atoms like oxygen, nitrogen, or fluorine. This makes hydrogen bonding especially important in substances like water, which is a prime example of extensive hydrogen bonding;
it is responsible for many of water's unique properties, such as high surface tension and boiling point.
  • In the case of acetone interacting with water, the carbonyl oxygen in acetone can act as a hydrogen bond acceptor.
  • Water's hydrogen atoms, being very partially positive, are attracted and can form bonds with the electron-rich oxygen in acetone.
  • This hydrogen bonding is stronger than typical dipole-dipole interactions, significantly enhancing acetone's solubility in water.
Hydrogen bonds involve partial electrostatic attraction which might be likened to the 'Velcro' of molecular interactions, grabbing onto any compatible, proximate hydrogen atom on a neighboring molecule.
Polar Molecules
Polar molecules are molecules in which there is an uneven distribution of electron density, resulting in regions of partial positive and negative charge. This polarity is often due to differences in electronegativity between atoms involved in chemical bonds.
In acetone, the carbonyl group (C=O) is quite polar; oxygen is much more electronegative than carbon, drawing electron density and creating a partial negative charge on the oxygen, and a partial positive charge on the carbon atom.
Water is also a polar molecule, with its oxygen atom holding a partial negative charge and the hydrogen atoms holding partial positive charges. This polarity means that water can engage in strong dipole-dipole interactions with other polar molecules, like acetone.
Because both acetone and water are polar, they can interact favorably, allowing acetone to dissolve readily in water—a classic case of "like dissolves like." This principle explains why polar molecules are generally soluble in polar solvents.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Dimethylglyoxime [DMG, (CH \(\left._{3} \mathrm{CNOH} \text { ) }_{2}\right]\) is used as a reagent to precipitate nickel ion. Assume that \(53.0 \mathrm{g}\) of DMG has been dissolved in \(525 \mathrm{g}\) of ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) (IMAGE CAN'T COPY) The red, insoluble compound formed between nickel(II) ion and dimethylglyoxime (DMG) is precipitated when DMG is added to a basic solution of \(\mathrm{Ni}^{2+}(\mathrm{aq})\) (a) What is the mole fraction of DMG? (b) What is the molality of the solution? (c) What is the vapor pressure of the ethanol over the solution at ethanol's normal boiling point of \(78.4^{\circ} \mathrm{C} ?\) (d) What is the boiling point of the solution? (DMG does not produce ions in solution.) \(\left(K_{\mathrm{bp}} \text { for ethanol }=\right.\) \(\left.+1.22^{\circ} \mathrm{C} / m\right)\)

Account for the fact that alcohols such as methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\) and ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) are quite miscible with water, whereas an alcohol with a long-carbon chain, such as octanol \(\left(\mathrm{C}_{8} \mathrm{H}_{17} \mathrm{OH}\right),\) is poorly soluble in water.

When salts of \(\mathrm{Mg}^{2+}, \mathrm{Ca}^{2+},\) and \(\mathrm{Be}^{2+}\) are placed in water, the positive ion is hydrated (as is the negative ion). Which of these three cations is most strongly hydrated? Which one is least strongly hydrated?

The Henry's law constant for \(\mathrm{O}_{2}\) in water at \(25^{\circ} \mathrm{C}\) is 1.66 \(\times 10^{-6} \mathrm{M} / \mathrm{mm}\) Hg. Which of the following is a reasonable constant when the temperature is \(50^{\circ} \mathrm{C}\) ? Explain the reason for your choice. (a) \(8.80 \times 10^{-7} \mathrm{M} / \mathrm{mm} \mathrm{Hg}\) (b) \(3.40 \times 10^{-6} \mathrm{M} / \mathrm{mm} \mathrm{Hg}\) (c) \(1.66 \times 10^{-6} \mathrm{M} / \mathrm{mm} \mathrm{Hg}\) (d) \(8.40 \times 10^{-5} \mathrm{M} / \mathrm{mm} \mathrm{Hg}\)

What mass of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) must you add to \(125 \mathrm{g}\) of water to prepare \(0.200 \mathrm{m} \mathrm{Na}_{2} \mathrm{CO}_{3} ?\) What is the mole fraction of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) in the resulting solution?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free