Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Five alkenes have the formula \(\mathrm{C}_{7} \mathrm{H}_{14}\) and a seven- carbon chain. Draw their structures and name them.

Short Answer

Expert verified
1-heptene, 2-heptene, 3-heptene, 4-methyl-1-hexene, and 3-methyl-1-hexene.

Step by step solution

01

Introduction to the problem

We need to identify five alkenes with the chemical formula \(\mathrm{C}_7\mathrm{H}_{14}\) that each have a seven-carbon chain. Since each has the same molecular formula, they are structural isomers differing in the position of the double bond.
02

Identify the first alkene: 1-Heptene

The simplest alkene is obtained by positioning the double bond at the beginning of the carbon chain. Structure: \(CH_2=CH(CH_2)_5CH_3\). The name for this compound is 1-heptene.
03

Identify the second alkene: 2-Heptene

Move the double bond one carbon inward. Structure: \(CH_3CH=CH(CH_2)_4CH_3\). The name for this compound is 2-heptene.
04

Identify the third alkene: 3-Heptene

Continue shifting the double bond. Structure: \(CH_3(CH_2)CH=CH(CH_2)_3CH_3\). The name for this compound is 3-heptene.
05

Identify the fourth alkene: 4-Methyl-1-hexene

Introduce a methyl group branching at the fourth carbon. Structure: \(CH_2=CH(CH_2)_3CH(CH_3)CH_3\). The compound name is 4-methyl-1-hexene.
06

Identify the fifth alkene: 3-Methyl-1-hexene

Place a methyl group at the third carbon from a terminal double bond. Structure: \(CH_2=CH(CH_2)_2CH(CH_3)CH_2CH_3\). The compound name is 3-methyl-1-hexene.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molecular Formula C7H14
A molecular formula provides essential information about the types and numbers of atoms present in a compound. In this problem, the molecular formula is \(\mathrm{C}_7\mathrm{H}_{14}\), which represents an alkene. Alkenes are a class of hydrocarbons characterized by a carbon-carbon double bond.

With \(7\) carbon atoms and \(14\) hydrogen atoms, this formula indicates the compound is not a saturated hydrocarbon. Saturated hydrocarbons, like alkanes, contain single bonds only. Adding a double bond leads to the general formula for alkenes, \(\mathrm{C}_n\mathrm{H}_{2n}\). Hence, knowing the formula \(\mathrm{C}_7\mathrm{H}_{14}\) helps us understand we're dealing with an unsaturated hydrocarbon.

This information sets the stage for exploring different structural forms, known as isomers, that can exist with this fixed formula.
Structural Isomers
Structural isomers are molecules that have the same molecular formula but differ in the arrangement of atoms. This difference can significantly alter their properties. With alkenes having the formula \(\mathrm{C}_7\mathrm{H}_{14}\), these isomers arise from varying the position of the double bond along the carbon chain.

For instance, 1-heptene features the double bond at the beginning of the seven-carbon chain, while 2-heptene moves it one carbon inward.
  • 1-heptene: introduces a double bond at the first carbon
  • 2-heptene: moves the double bond to the second carbon
  • 3-heptene: shifts the double bond to the third position

The formation of branched isomers like 4-methyl-1-hexene, where a methyl group is present, showcases an additional way to create structural isomers. This type of branching alters the main carbon chain, introducing more structural diversity without changing the overall molecular formula.
Organic Chemistry
Organic chemistry focuses on the study of carbon-containing compounds and their properties. Alkenes, a major functional group in organic chemistry, are characterized by a carbon-carbon double bond. This double bond is responsible for much of an alkene's reactivity and chemical behavior.

Understanding alkenes involves recognizing how the double bond influences molecular properties and how variants like structural isomers offer diverse physical and chemical characteristics. The versatility of organic compounds arises from their ability to form various isomeric forms, each with unique structural, physical, and chemical properties.

Organic chemists manipulate these structures to suit different needs, from industrial applications to pharmaceuticals, showcasing the expansive applications of these fundamental principles.
Double Bond Positioning
Double bond positioning is crucial in defining the characteristics and reactivity of an alkene. As seen in the structural isomers of \(\mathrm{C}_7\mathrm{H}_{14}\), altering the placement of this double bond can result in entirely different molecules. Each position offers unique properties and names to the resulting compounds.

Consider the alkenes:
  • 1-heptene: Located at the start of the chain, this position is straightforward and linear
  • 2-heptene: The shift towards the chain’s middle can affect the molecule’s stability and reactivity
  • 3-heptene: With the bond further inward, it provides yet another variation

These subtle changes in the position of a double bond illustrate the intricacies of organic chemistry. They underline why seemingly small modifications can lead to significant differences in molecular behavior and function, pivotal for deeply understanding and innovating within the field.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free