Chapter 9: Problem 56
Carbon dioxide \(\left(\mathrm{CO}_{2}\right),\) dinitrogen monoxide \(\left(\mathrm{N}_{2} \mathrm{O}\right),\) the azide ion \(\left(\mathrm{N}_{3}^{-}\right),\) and the cyanate ion (OCN \(^{-}\) ) have the same geometry and the same number of valence shell electrons. However, there are significant differences in their electronic structures. (a) What hybridization is assigned to the central atom in each species? Which orbitals overlap to form the bonds between atoms in each structure. (b) Evaluate the resonance structures of these four species. Which most closely describe the bonding in these species? Comment on the differences in bond lengths and bond orders that you expect to see based on the resonance structures.
Short Answer
Step by step solution
Determine Hybridization of Central Atoms
Identify Bond Formation in Each Species
Evaluate Resonance Structures
Analyze Bond Lengths and Bond Orders
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Hybridization
For example, in CO_2 , the carbon atom undergoes sp hybridization because it forms two double bonds in a linear structure. This mixing of one s and one p orbital creates two equivalent sp orbitals that align linearly.
Similarly, N_2O also uses sp hybridization at its central nitrogen due to its linear structure, despite being surrounded by another nitrogen and an oxygen atom. For the N_3^- , the central nitrogen also adopts sp hybridization, while in OCN^- the central carbon uses this hybridization for the linear arrangement of atoms. This consistency in hybridization highlights the challenging yet fascinating nature of predicting and understanding molecule geometries.
Orbital Overlap
In CO_2 , carbon's sp hybrid orbitals interact with the p orbitals of oxygen to form sigma bonds. Meanwhile, the unhybridized p orbitals of both carbon and oxygen create pi bonds. This dual bonding results in strong double bonds between carbon and oxygen.
In N_2O , the central nitrogen's sp hybrid orbitals overlap with the p orbitals of the adjacent nitrogen and oxygen atoms, forming sigma bonds, while remaining p orbitals engage in pi bonding.
For the N_3^- deficit ion, similar orbital interactions occur amongst the nitrogen atoms, establishing both sigma and pi bonds. In the cyanate ion (OCN ^- ), the carbon's sp hybrid orbitals overlap with oxygen’s and nitrogen’s p orbitals, forming robust sigma bonds along with pi bonds due to leftover p orbital interactions.
Understanding these overlaps provides insight into the robust nature and the geometry stability in these molecules.
Resonance Structures
In CO_2 , resonance is observed in different placements of double bonds between the carbon and oxygen atoms. Although they change positions in drawing, no molecule is exactly like any one structure; instead, the actual structure is a hybrid of all possible resonance structures.
Dinitrogen monoxide ( N_2O ) is similar, having resonance structures with various nitrogen-oxygen configurations, affecting electron distribution and bond characterization.
With the azide ion ( N_3^- ), resonance involves electron delocalization among nitrogen atoms, creating a balance in electron distribution.
In the cyanate ion (OCN ^- ), resonance structures show variations in electron placement between oxygen, carbon, and nitrogen, impacting their formal charges and bonding characteristics. These resonance structures offer clearer insights into the true, yet complex, electronic structure of molecules, emphasizing the flexibility and variability in electron assignment.
Bond Length
Resonance can often modify bond lengths by causing them to average out between extremes in differing structures. In CO_2 , for instance, resonance ensures that the bond lengths of the carbon-oxygen bonds remain equal and are consistent with a double-bond character.
For N_2O , the resonance causes a variety of bond lengths, potentially inducing a slightly longer bond with more single-bond character.
In N_3^- , resonance results in nearly equal bond lengths due to the delocalization of electrons over the nitrogen atoms, reflecting an intermediate bond order that balances single and double bond traits.
In OCN^- ion, the effect of resonance leads to shorter O-C bonds but longer C-N bond lengths than one would expect if looking at single, static structures. This equalization or variation in bond lengths illustrates how resonance contributes to the stability and structure of molecules.
Bond Order
In CO_2 , each carbon-oxygen bond has a bond order of approximately 2 due to the resonance between different positions of double bonds.
For N_2O , the presence of resonance means bond orders might be somewhat less defined but typically ranging below 2, indicative of more single-bond character on average, particularly in the N-O bonds.
Within the azide ion ( N_3^- ), the delocalization from resonance yields bond orders between 1 and 2, balancing the bonding situation among nitrogen atoms.
In OCN ^- , varied resonance structures modify bond orders from those expected for simple single or double bonds, usually indicating slightly reduced or enhanced bond strength depending on specific atom pairs. Understanding bond order is crucial as it correlates directly with the strength and stability of bonds, influencing molecular reactivity and interaction.