Chapter 8: Problem 41
Which of the following molecules is(are) polar? For each polar molecule, indicate the direction of polarity-that is, which is the negative end, and which is the positive end of the molecule. (a) \(\mathrm{BeCl}_{2}\) (b) \(\mathrm{HBF}_{2}\) (c) \(\mathrm{CH}_{3} \mathrm{Cl}\) (d) \(\mathrm{SO}_{3}\)
Short Answer
Expert verified
\(\mathrm{HBF}_{2}\) and \(\mathrm{CH}_{3}\mathrm{Cl}\) are polar; negative ends are at \(\mathrm{F}\) and \(\mathrm{Cl}\), respectively.
Step by step solution
01
Determine Molecular Geometry
To assess the polarity of a molecule, we start by determining its molecular geometry, which can help us understand the distribution of electron density. For each molecule: - **(a) \(\mathrm{BeCl}_{2}\)**: Linear shape. - **(b) \(\mathrm{HBF}_{2}\)**: Trigonal planar shape. - **(c) \(\mathrm{CH}_{3}\text{Cl}\)**: Tetrahedral shape. - **(d) \(\mathrm{SO}_{3}\)**: Trigonal planar shape.
02
Assess Electronegativity Differences
Examine the electronegativity of atoms within each molecule to predict bond dipoles. - **Be-Cl bonds** in \(\mathrm{BeCl}_{2}\) have a small difference, making individual bonds slightly polar. - **H-B, B-F bonds** in \(\mathrm{HBF}_{2}\) have differences; the B-F bonds are more polar due to the larger electronegativity difference. - **C-H and C-Cl bonds** in \(\mathrm{CH}_{3} \mathrm{Cl}\); the C-Cl bond is significantly polar. - **S-O bonds** in \(\mathrm{SO}_{3}\) exhibit polarity, but are arranged symmetrically.
03
Determine Net Dipole Moment
To ascertain if molecules are polar or nonpolar, consider both bond polarities and geometry to identify the net dipole moment: - **(a) \(\mathrm{BeCl}_{2}\)**: Despite polar bonds, the linear shape results in dipoles canceling each other, making it nonpolar. - **(b) \(\mathrm{HBF}_{2}\)**: Asymmetric shape and bond dipoles result in a net dipole moment, making it polar, with the negative end at fluorine atoms. - **(c) \(\mathrm{CH}_{3}\mathrm{Cl}\)**: The tetrahedral shape with C-Cl bond dipole results in a net dipole moment, making it polar; the negative end is at the chlorine. - **(d) \(\mathrm{SO}_{3}\)**: Despite polar bonds, the symmetry of the molecule results in dipoles canceling, making it nonpolar.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molecular Geometry
Molecular geometry is the three-dimensional arrangement of atoms within a molecule. It's a crucial concept for understanding molecular polarity, as the spatial configuration affects how electron density is distributed. For example:
- Linear Geometry: Molecules like \(\mathrm{BeCl}_{2}\) have atoms aligned in a straight line. This symmetry often results in nonpolar molecules, as any dipole moments cancel each other out.
- Trigonal Planar Geometry: Seen in molecules like \(\mathrm{SO}_{3}\), this geometry allows for some symmetries. It means even if individual bonds are polar, the overall molecule may be nonpolar if the vectors cancel each other.
- Tetrahedral Geometry: Found in \(\mathrm{CH}_{3}\text{Cl}\), where atoms are arranged symmetrically around a central atom. Here, geometry does not cancel out all dipole moments, contributing to polarity.
Electronegativity
Electronegativity refers to an atom's ability to attract and hold onto electrons in a chemical bond. This property is essential when discussing molecular polarity. Here's why electronegativity matters:
- Electronegativity Differences: Atoms with higher electronegativity will pull electron density towards themselves, creating a polar bond. \(\ \mathrm{Cl}\) in \(\mathrm{CH}_{3}\mathrm{Cl} \) makes the chlorine atom partially negative, highlighting the bond's polar nature.
- Bond Polarity: In \(\mathrm{HBF}_{2}\), the \(\mathrm{B-F}\) bonds are polar because of substantial electronegativity differences. The same element, \(\mathrm{F}\), in the molecule contributes to an overall polar molecule due to its strong electronegativity.
Dipole Moment
A dipole moment is a vector quantity that results from asymmetric charge distribution in a molecule, indicating polarity. It's quantified by the product of charge separation and the distance between charges. Consider these points:
- Net Dipole Moment: In molecules like \(\mathrm{CH}_{3}\text{Cl}\), where asymmetrical distribution of polar bonds (like \(\mathrm{C-Cl}\)) leads to a net dipole moment, resulting in net polarity.
- Zero Dipole Moment: Molecules such as \(\mathrm{SO}_{3}\) and \(\mathrm{BeCl}_{2}\) display zero net dipole moment due to symmetrical geometry that cancels out any individual bond dipoles.
Covalent Bonds
Covalent bonds are formed when atoms share electrons. These can be either nonpolar or polar, depending on the sharing equality of the electrons. Key aspects of covalent bonds include:
- Polar Covalent Bonds: These occur when two different atoms share electrons unevenly. The \(\mathrm{C-Cl}\) bond in \(\mathrm{CH}_{3}\mathrm{Cl}\) is a classic example, where electrons are drawn more towards chlorine making it polar.
- Nonpolar Covalent Bonds: Occur in symmetric molecules such as \(\mathrm{BeCl}_{2}\) where atoms share electrons equally, and any polar nature in bonds is negated by the molecule's symmetry.