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For each of the following tell whether the process is exothermic or endothermic. (No calculations are required.) (a) \(\mathrm{H}_{2} \mathrm{O}(\ell) \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{s})\) (b) \(2 \mathrm{H}_{2}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\) (c) \(\mathrm{H}_{2} \mathrm{O}\left(\ell, 25^{\circ} \mathrm{C}\right) \rightarrow \mathrm{H}_{2} \mathrm{O}\left(\ell, 15^{\circ} \mathrm{C}\right)\) (d) \(\mathrm{H}_{2} \mathrm{O}(\ell) \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\)

Short Answer

Expert verified
(a) Exothermic, (b) Exothermic, (c) Exothermic, (d) Endothermic.

Step by step solution

01

Understand the Process for (a)

The process described is \( \mathrm{H}_{2} \mathrm{O}(\ell) \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{s}) \). This is a transition from liquid water to solid water, or freezing. Freezing releases energy into the surroundings, making it an exothermic process.
02

Understand the Process for (b)

The reaction \(2 \mathrm{H}_{2}(\mathrm{g}) + \mathrm{O}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\) represents the formation of water from its gaseous elements. The formation of water releases heat, therefore it is an exothermic reaction.
03

Understand the Process for (c)

The process \( \mathrm{H}_{2} \mathrm{O}\left(\ell, 25^{\circ} \mathrm{C}\right) \rightarrow \mathrm{H}_{2} \mathrm{O}\left(\ell, 15^{\circ} \mathrm{C}\right) \) indicates cooling of liquid water from 25°C to 15°C. During cooling, water loses heat to the surroundings, so this is an exothermic process.
04

Understand the Process for (d)

The process \( \mathrm{H}_{2} \mathrm{O}(\ell) \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \) involves the conversion of liquid water to water vapor, or evaporation. This requires energy input, as energy is absorbed during the phase change from liquid to gas, making it an endothermic process.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exothermic Processes
Exothermic processes release energy into their surroundings. This usually happens in the form of heat, making the environment warmer.
In an exothermic reaction or process, energy is a by-product, typically because bonds are forming. Let's look at a few examples:
  • Freezing of water: When liquid water freezes to become ice, it gives off heat to the surroundings, making the process exothermic.
  • Formation of water from hydrogen and oxygen gas: This chemical reaction produces water vapor and releases energy, hence it is exothermic.
Exothermic processes are found everywhere in our daily lives, from the heat given off by burning candles to the warmth generated by your body's metabolism.
Endothermic Processes
Endothermic processes are those that absorb energy from their surroundings. This means they require energy input to proceed.
Energy absorption usually results in a decrease in temperature in the nearby environment. Here are some key examples:
  • Evaporation of water: Turning liquid water into vapor absorbs energy, making it an endothermic process. This is why sweating cools you down.
Understanding endothermic processes helps explain why certain reactions require heat or other energy sources to take place.
Phase Transitions
Phase transitions are changes in the state of matter of a substance. These changes can either absorb or release energy depending on the direction of the transition.
Here are some common transitions:
  • Freezing: Liquid to solid. This is exothermic as it releases energy.
  • Melting: Solid to liquid. This is endothermic because it requires energy.
  • Evaporation: Liquid to gas. Energy absorption makes this an endothermic process.
Each transition involves distinct energy dynamics which determine whether the process is exothermic or endothermic.
Chemical Reactions
Chemical reactions involve rearranging atoms to form new substances. This can involve breaking bonds, which absorbs energy, or forming new bonds, which releases energy.
Here are a few points to consider:
  • Exothermic reactions: In these, more energy is released in forming product bonds than is absorbed in breaking reactant bonds. For example, burning wood releases heat.
  • Endothermic reactions: These require more energy to break reactant bonds than is released in forming product bonds. Photosynthesis in plants is an example.
Understanding the energy dynamics helps in determining whether a reaction is exothermic or endothermic, which is key in fields like chemistry and engineering.

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Most popular questions from this chapter

You mix \(125 \mathrm{mL}\) of \(0.250 \mathrm{M}\) CsOH with \(50.0 \mathrm{mL}\) of 0.625 M HF in a coffee-cup calorimeter, and the temperature of both solutions rises from \(21.50^{\circ} \mathrm{C}\) before mixing to \(24.40^{\circ} \mathrm{C}\) after the reaction. $$ \mathrm{CsOH}(\mathrm{aq})+\mathrm{HF}(\mathrm{aq}) \rightarrow \mathrm{CsF}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) $$ What is the enthalpy of reaction per mole of CsOH? Assume the densities of the solutions are all \(1.00 \mathrm{g} / \mathrm{mL},\) and the specific heat capacities of the solutions are \(4.2 \mathrm{J} / \mathrm{g} \cdot \mathrm{K}\)

A bomb calorimetric experiment was run to determine the enthalpy of combustion of ethanol. The reaction is $$ \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(\ell)+3 \mathrm{O}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{CO}_{2}(\mathrm{g})+3 \mathrm{H}_{2} \mathrm{O}(\ell) $$ The bomb had a heat capacity of \(550 \mathrm{J} / \mathrm{K},\) and the calorimeter contained \(650 \mathrm{g}\) of water. Burning \(4.20 \mathrm{g}\) of ethanol, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(\ell)\) resulted in a rise in temperature from \(18.5^{\circ} \mathrm{C}\) to \(22.3^{\circ} \mathrm{C}\). Calculate \(\Delta U\) for the combustion of ethanol, in \(\mathrm{kJ} / \mathrm{mol}\).

You drink \(350 \mathrm{mL}\) of diet soda that is at a temperature of \(5^{\circ} \mathrm{C}\) (a) How much energy will your body expend to raise the temperature of this liquid to body temperature \(\left(37^{\circ} \mathrm{C}\right) ?\) Assume that the density and specific heat capacity of diet soda are the same as for water. (b) Compare the value in part (a) with the caloric content of the beverage. (The label says that it has a caloric content of 1 Calorie.) What is the net energy change in your body resulting from drinking this beverage? (1 Calorie = \(1000 \mathrm{kcal}=4184 \mathrm{J} .)\) (c) Carry out a comparison similar to that in part (b) for a nondiet beverage whose label indicates a caloric content of 240 Calories.

Insoluble \(\mathrm{PbBr}_{2}(\mathrm{s})\) precipitates when solutions of \(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq})\) and \(\mathrm{NaBr}(\mathrm{aq})\) are mixed. $$\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq})+2 \mathrm{NaBr}(\mathrm{aq}) \rightarrow \mathrm{PbBr}_{2}(\mathrm{s})+2 \mathrm{NaNO}_{3}(\mathrm{aq})$$ To measure the enthalpy change, \(200 .\) mL of \(0.75 \mathrm{M} \mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq})\) and \(200 . \mathrm{mL}\) of \(1.5 \mathrm{M}\) NaBr(aq) are mixed in a coffee-cup calorimeter. The temperature of the mixture rises by \(2.44^{\circ} \mathrm{C}\) Calculate the enthalpy change for the precipitation of \(\mathrm{PbBr}_{2}(\mathrm{s}),\) in \(\mathrm{kJ} / \mathrm{mol}\). (Assume the density of the solution is \(1.0 \mathrm{g} / \mathrm{mI}_{7}\) and its specific heat capacity is \(4.2 \mathrm{J} / \mathrm{g} \cdot \mathrm{K} .)\)

A The standard molar enthalpy of formation of diborane, \(\mathrm{B}_{2} \mathrm{H}_{6}(\mathrm{g}),\) cannot be determined directly because the compound cannot be prepared by the reaction of boron and hydrogen. It can be calculated from other enthalpy changes, however. The following enthalpy changes can be measured. \(4 \mathrm{B}(\mathrm{s})+3 \mathrm{O}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{B}_{2} \mathrm{O}_{3}(\mathrm{s})\) \(\Delta_{1} H^{\circ}=-2543.8 \mathrm{kJ} / \mathrm{mol}-\mathrm{pxn}\) \(\mathrm{H}_{2}(\mathrm{g})+^{1 / 2} \mathrm{O}_{2}(\mathrm{g}) \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\) \(\Delta_{r} H^{\prime \prime}=-241.8 \mathrm{kJ} / \mathrm{mol}-\mathrm{rxn}\) \(\mathrm{B}_{2} \mathrm{H}_{6}(\mathrm{g})+3 \mathrm{O}_{2}(\mathrm{g}) \rightarrow \mathrm{B}_{2} \mathrm{O}_{3}(\mathrm{s})+3 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\) \(\Delta_{\tau} H^{\circ}=-2032.9 \mathrm{kJ} / \mathrm{mol}-\mathrm{rxn}\) (a) Show how these equations can be added together to give the equation for the formation of \(\mathrm{B}_{2} \mathrm{H}_{6}(\mathrm{g})\) from \(\mathrm{B}(\mathrm{s})\) and \(\mathrm{H}_{2}(\mathrm{g})\) in their standard states. Assign enthalpy changes to each reaction. (b) Calculate \(\Delta_{f} H^{\circ}\) for \(\mathrm{B}_{2} \mathrm{H}_{6}(\mathrm{g})\) (c) Draw an energy level diagram that shows how the various enthalpies in this problem are related. (d) Is the formation of \(\mathrm{B}_{2} \mathrm{H}_{6}(\mathrm{g})\) from its elements exo-or endothermic?

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