Chapter 23: Problem 53
Draw structures of the product formed by oxidation of the following alcohols. Assume an excess of oxidizing agent is used in each case. (a) 2 -methyl-1-pentanol (b) 3-methyl-2-pentanol (c) \(\mathrm{HOCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) (d) \(\mathrm{H}_{2} \mathrm{NCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\)
Short Answer
Step by step solution
Identify the Alcohol Type for 2-methyl-1-pentanol
Determine Oxidation Product of Primary Alcohol
Identify the Alcohol Type for 3-methyl-2-pentanol
Determine Oxidation Product of Secondary Alcohol
Identify the Alcohol Type for HOCH2CH2CH2CH2OH
Determine Oxidation Product of Primary Diol
Identify Alcohol Type for H2NCH2CH2CH2OH
Determine Oxidation Product for Alcohol with Amine
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Primary Alcohol
- First, they form an aldehyde. This occurs when the -OH group and its adjacent hydrogen are removed.
- Next, the aldehyde can be further oxidized to form a carboxylic acid, where the former carbonyl carbon now bonds to an -OH group and a double-bonded oxygen (O=).
Secondary Alcohol
The reaction stops at the ketone stage because ketones are generally more stable and do not readily oxidize further under typical conditions. An example of this is 3-methyl-2-pentanol, a secondary alcohol. When it is oxidized, it forms 3-methyl-2-pentanone, a ketone.
Diol Oxidation
It's important to note that diol oxidation often necessitates conditions strong enough to manage two simultaneous oxidation processes, making it slightly more complex than oxidizing single alcohol units.
Oxidation Products
- Primary alcohols generally oxidize to form first an aldehyde, and with excess oxidizing agent, further to a carboxylic acid.
- Secondary alcohols convert into ketones, as they lack the structural context needed for further oxidation.
- In cases of diols, which can create diacids, each hydroxyl group transforms along primary alcohol oxidation patterns.