Question

Write an equation for the preparation of hexylbenzene from benzene and other appropriate reagents.

Short answer

Use a Friedel-Crafts alkylation reaction with benzene and n-hexyl chloride, catalyzed by \( AlCl_3 \).

Step-by-step solution

Identify the Target Compound

The target compound is hexylbenzene, which has a benzene ring bonded to a hexyl group (a six-carbon alkyl group). Hexylbenzene can be represented as \( C_6H_5C_6H_{13} \).

Start with Benzene

Begin with benzene as the starting material for the synthesis of hexylbenzene. Benzene serves as the aromatic ring to which the hexyl group will be attached.

Choose the Reagent for Alkylation

For this synthesis, choose n-hexyl chloride (\( C_6H_{13}Cl \)) as the alkylating reagent. This reagent will provide the hexyl group to attach to the benzene ring.

Use a Friedel-Crafts Alkylation Reaction

Perform a Friedel-Crafts alkylation, a reaction that adds an alkyl group to an aromatic ring. Use aluminum chloride (\( AlCl_3 \)) as the catalyst in this reaction to facilitate the attachment of the hexyl group to the benzene ring.

Write the Chemical Equation

Combine the reactants and catalyst to form the equation: \( C_6H_6 + C_6H_{13}Cl \xrightarrow{AlCl_3} C_6H_5C_6H_{13} + HCl \). This represents benzene reacting with n-hexyl chloride in the presence of aluminum chloride, producing hexylbenzene and hydrochloric acid as a byproduct.

Key concepts

Hexylbenzene Synthesis

Hexylbenzene synthesis is centered around the attachment of a hexyl group to a benzene ring, resulting in a novel organic compound called hexylbenzene. This process is commonly undertaken using Friedel-Crafts Alkylation, a classic method in organic chemistry.

• Start with benzene, which acts as the aromatic base for the synthesis.
• The hexyl group, a six-carbon chain, is introduced through an alkylating agent such as n-hexyl chloride (\( C_6H_{13}Cl \)).
• The reaction requires a catalyst to facilitate the attachment, which is commonly aluminum chloride (\( AlCl_3 \)).

Each step is crucial in ensuring the smooth transformation of benzene into hexylbenzene, a compound widely used in industrial applications. The synthesis must be carefully controlled to avoid side reactions and maximize yield.

Benzene Reactions

Benzene reactions are a cornerstone of organic chemistry due to benzene's stable aromatic structure. Benzene is known for its tendency to undergo electrophilic substitution rather than addition, preserving its aromaticity. In the context of synthesizing hexylbenzene:

• The reaction targets the substitution of a hydrogen atom on the benzene ring with an alkyl group.
• Electrophilic aromatic substitution reactions, like the Friedel-Crafts alkylation, are preferred due to benzene’s electron-rich ring.
• Benzene’s delocalized electrons in the form of a pie electron cloud make it a potent nucleophile appropriate for reacting with alkenes or chlorides.

Through these reactions, benzene serves as a key reactant in forming various aromatic compounds, expanding its utility beyond basic aromatic hydrocarbons.

Aromatic Alkylation

Aromatic alkylation involves adding an alkyl group to an aromatic ring, such as benzene, through chemical reactions like the Friedel-Crafts process. This mechanism is pivotal in the synthesis of various aromatic compounds.

• In the Friedel-Crafts alkylation, an alkyl halide serves as the source of the alkyl group. For hexylbenzene synthesis, n-hexyl chloride (\( C_6H_{13}Cl \)) is used.
• The presence of a catalyst, typically aluminum chloride (\( AlCl_3 \)), helps in generating a more reactive carbocation from the alkyl halide.
• This created carbocation is sufficiently electrophilic to substitute an aromatic hydrogen on the benzene ring.

Mastering aromatic alkylation opens paths to synthesizing both simple and complex organic molecules, providing essential skills for chemists.

Chemistry Equation Writing

Writing a correct chemical equation is essential in documenting chemical reactions. For the synthesis of hexylbenzene, the equation is:\[C_6H_6 + C_6H_{13}Cl \xrightarrow{AlCl_3} C_6H_5C_6H_{13} + HCl\]In this equation:

• The left side represents the reactants: benzene (\( C_6H_6 \)) and n-hexyl chloride (\( C_6H_{13}Cl \)).
• Aluminum chloride (\( AlCl_3 \)) acts as the catalyst, denoted above the reaction arrow.
• The right side presents the products: hexylbenzene (\( C_6H_5C_6H_{13} \)) and hydrogen chloride (\( HCl \)), forming as a byproduct.

This systematic representation ensures clarity and a deeper understanding of the reactants' conversion to the desired products. Chemistry equation writing is fundamental for students and professionals engaged in chemical research and application.