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Identify the following as either chemical or physical properties of most transition metals: (a) can be oxidized. (b) have unpaired electrons (paramagnetism). (c) solids at \(25^{\circ} \mathrm{C}\) (d) metallic luster. (e) Compounds of the elements are often colored.

Short Answer

Expert verified
(a) chemical, (b) chemical, (c) physical, (d) physical, (e) chemical.

Step by step solution

01

Understanding Oxidation

Oxidation is a chemical process where an element loses electrons. If transition metals can be oxidized, this relates to their chemical property due to the change in electronic structure.
02

Paramagnetism and Unpaired Electrons

Paramagnetism occurs when atoms or molecules have unpaired electrons. This is a feature related to electron configuration and is a chemical property of transition metals.
03

Analyzing State at Room Temperature

Most transition metals are solids at room temperature (25°C). This is a physical property as it describes the physical state of the substance without involving a chemical change.
04

Identifying Metallic Luster

Metallic luster, or shininess, is a physical property of transition metals. It describes how they reflect light and is not associated with a chemical transformation.
05

Colored Compounds and Chemical Behavior

The fact that compounds of transition metals are often colored is related to their chemical properties. The colors arise from electronic transitions between different energy levels.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Properties
Transition metals exhibit a variety of fascinating chemical properties due to their unique ability to form different oxidation states. Oxidation is a key chemical property of transition metals. During oxidation, these metals lose electrons, leading to changes in their electronic structure. This ability to undergo chemical change is indicative of their reactivity. Transition metals can easily switch between different oxidation states due to the involvement of d-orbitals in bonding. This ability highlights their versatility and is an important reason for their use in chemical reactions, especially catalysis.
Additionally, compounds of transition metals are often vibrantly colored. The colors manifest from electronic transitions that involve the movement of electrons between different energy levels within the d-orbitals. Such transitions are characteristic of their chemical identity and influence many applications, including dyes, pigments, and indicators in various chemical processes.
Physical Properties
When examining the physical properties of transition metals, one can observe a set of characteristics common among these elements. Most transition metals are solid at room temperature, specifically at 25°C. This is a physical property as it refers to their state of matter without invoking any chemical reactions. Solid-state indicates strong metallic bonds that require high energy to break.
Another physical aspect is their metallic luster, which is the shiny appearance that they exhibit. This luster results from the interaction of light with the metal's surface. The electrons in the metal can reflect light efficiently, contributing to this lustrous characteristic. These solid and shiny nature underscore their use in construction and jewelry.
Paramagnetism
Paramagnetism is a property that arises in transition metals due to the presence of unpaired electrons in their electron configuration. When a metal contains unpaired electrons, it can become attracted to magnetic fields, displaying paramagnetic behavior. This magnetic characteristic is linked to the specific electron arrangements in partly filled d-orbitals.
Transition metals with unpaired electrons will be paramagnetic, while those without will show diamagnetic properties. The ability to exhibit paramagnetism has practical implications in the field of materials science, particularly where magnetic properties are essential. Understanding this concept can also be crucial for interpreting magnetic data and applications that require specific magnetization properties.
Oxidation
Oxidation reflects a significant chemical behavior of transition metals, where the loss of electrons results in various oxidation states. These metals have the remarkable ability to participate in redox reactions due to their flexible oxidation states. This flexibility is due to the valence electrons present in both the s- and d-orbitals.
Transition metals often exhibit multiple oxidation states, unlike the main group elements, which usually have a single stable state. For instance, iron can exhibit oxidation states of +2 and +3, and manganese ranges from +2 to +7. This diversity allows them to serve as catalysts in many industrial processes, facilitating a wide range of chemical transformations.
Electron Configuration
The electron configuration in transition metals is foundational to understanding their chemical and physical behavior. These metals are defined by having partially filled d-orbitals, giving rise to many of their unique properties. The d-block of the periodic table represents these metals, highlighting their significant role in the overarching structure of elements. As electrons fill the d-orbitals, various electron arrangements occur.
This arrangement allows for their typical multiple oxidation states and results in magnetic properties like paramagnetism. Understanding electron configuration is critical for predicting and explaining trends, reactivity, and bonding in transition metals.

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Most popular questions from this chapter

A 0.213 -g sample of uranyl(VI) nitrate, \(\mathrm{UO}_{2}\left(\mathrm{NO}_{3}\right)_{2},\) is dissolved in \(20.0 \mathrm{mL}\) of \(1.0 \mathrm{M}\) \(\mathrm{H}_{2} \mathrm{SO}_{4}\) and shaken with Zn. The zinc reduces the uranyl ion, \(\mathrm{UO}_{2}^{2+},\) to a uranium ion, \(\mathrm{U}^{n+}\). To determine the value of \(n,\) this solution is titrated with \(\mathrm{KMnO}_{4} .\) Permanganate is reduced to \(\mathrm{Mn}^{2+}\) and \(\mathrm{U}^{n+}\) is oxidized back to \(\mathrm{UO}_{2}^{2+}\) (a) In the titration, \(12.47 \mathrm{mL}\) of \(0.0173 \mathrm{M} \mathrm{KMnO}_{4}\) was required to reach the equivalence point. Use this information to determine the charge on the ion \(\mathrm{U}^{n+}\). (b) With the identity of \(\mathrm{U}^{n+}\) now established, write a balanced net ionic equation for the reduction of \(\mathrm{UO}_{2}^{2+}\) by zinc (assume acidic conditions). (c) Write a balanced net ionic equation for the oxidation of \(\mathrm{U}^{n+}\) to \(\mathrm{UO}_{2}^{2+}\) by \(\mathrm{MnO}_{4}^{-}\) in acid.

In this question, we explore the differences between metal coordination by monodentate and bidentate ligands. Formation constants, \(K_{t}\), for \(\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}(\mathrm{aq})\) and \(\left[\mathrm{Ni}(\mathrm{en})_{3}\right]^{2+}(\mathrm{aq})\) are as follows: \(\mathrm{Ni}^{2+}(\mathrm{aq})+6 \mathrm{NH}_{3}(\mathrm{aq}) \longrightarrow\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}(\mathrm{aq}) \quad K_{\mathrm{f}}=10^{8}\) \(\mathrm{Ni}^{2+}(\mathrm{aq})+3 \mathrm{en}(\mathrm{aq}) \longrightarrow\left[\mathrm{Ni}(\mathrm{en})_{3}\right]^{2+}(\mathrm{aq})\) \(K_{f}=10^{18}\) The difference in \(K_{f}\) between these complexes indicates a higher thermodynamic stability for the chelated complex, caused by the chelate effect. Recall that \(K\) is related to the standard free energy of the reaction by \(\Delta_{r} G^{\circ}=-R T \ln K\) and \(\Delta_{r} G^{\circ}=\) \(\Delta_{r} H^{\circ}-T \Delta_{r} S^{\circ} .\) We know from experiment that \(\Delta_{t} H^{\circ}\) for the \(\mathrm{NH}_{3}\) reaction is \(-109 \mathrm{kJ} / \mathrm{mol}-\mathrm{rxn}\) and \(\Delta_{i} H^{\circ}\) for the ethylenediamine reaction is \(-117 \mathrm{kJ} / \mathrm{mol}-\mathrm{rxn} .\) Is the difference in \(\Delta_{r} H^{\circ}\) suffi- cient to account for the \(10^{10}\) difference in \(K_{f} ?\) Comment on the role of entropy in the second reaction.

From experiment, we know that \(\left[\mathrm{CoF}_{6}\right]^{3-}\) is paramagnetic and \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}\) is diamagnetic. Using the ligand field model, depict the electron configuration for each ion, and use this model to explain the magnetic property. What can you conclude about the effect of these ligands on the magnitude of \(\Delta_{0} ?\)

Match up the isoelectronic ions on the following list. $$\mathrm{Cu}^{+} \mathrm{Mn}^{2+} \mathrm{Fe}^{2+} \mathrm{Co}^{3+} \mathrm{Fe}^{3+} \mathrm{Zn}^{2+} \mathrm{Ti}^{2+} \mathrm{V}^{3+}$$

How many unpaired electrons are expected for high-spin and low-spin complexes of \(\mathrm{Fe}^{2+} ?\)

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