Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

You are given 0.10-g samples of \(\mathrm{K}, \mathrm{Mo}, \mathrm{Cr},\) and \(\mathrm{Al}\). List the samples in order of the amount (moles), from smallest to largest.

Short Answer

Expert verified
Mo, Cr, K, Al (from smallest to largest in moles).

Step by step solution

01

Finding the Molar Mass of Each Element

First, we need to find the molar mass of each of the given elements: Potassium (K), Molybdenum (Mo), Chromium (Cr), and Aluminum (Al). Based on the periodic table, the molar masses are approximately: \( K = 39.1 \, \text{g/mol} \), \( Mo = 95.95 \, \text{g/mol} \), \( Cr = 51.996 \, \text{g/mol} \), and \( Al = 26.98 \, \text{g/mol} \).
02

Calculating the Number of Moles for Each Element

Next, we need to calculate the number of moles for each 0.10-g sample using the formula: \( \text{moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \).- For \( K \): \( \frac{0.10 \, \text{g}}{39.1 \, \text{g/mol}} \approx 0.00256 \, \text{mol} \).- For \( Mo \): \( \frac{0.10 \, \text{g}}{95.95 \, \text{g/mol}} \approx 0.00104 \, \text{mol} \).- For \( Cr \): \( \frac{0.10 \, \text{g}}{51.996 \, \text{g/mol}} \approx 0.00192 \, \text{mol} \).- For \( Al \): \( \frac{0.10 \, \text{g}}{26.98 \, \text{g/mol}} \approx 0.00371 \, \text{mol} \).
03

Ordering the Elements by Moles

Now, arrange the calculated moles in ascending order:- Molybdenum (Mo): \( 0.00104 \, \text{mol} \)- Chromium (Cr): \( 0.00192 \, \text{mol} \)- Potassium (K): \( 0.00256 \, \text{mol} \)- Aluminum (Al): \( 0.00371 \, \text{mol} \)
04

Conclusion

Based on the calculations, the order from the smallest to largest amount of moles is: Molybdenum (Mo), Chromium (Cr), Potassium (K), Aluminum (Al).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass
When studying chemistry, understanding molar mass is crucial. Molar mass is essentially the weight of one mole of a given substance. It is expressed in grams per mole (g/mol). Each element has a unique molar mass, which can be found using the periodic table. To calculate the moles of a substance, we divide the mass of the sample by its molar mass. This is key for converting between grams and moles, helping us understand how much of a substance is present.

For instance, if you have a 1-gram sample of an element and its molar mass is 10 g/mol, you'd have 0.1 moles of that element. Understanding molar mass allows us to relate the mass of atoms and molecules to amounts we can see and measure, which is fundamental in chemical equations.
Periodic Table
The periodic table is like a map for chemists. It organizes all known chemical elements based on their properties and atomic number. Each element has a unique position on the table, which tells us a lot of important information.
  • Atomic Number: The number of protons in an element's nucleus.
  • Chemical Symbol: A one or two-letter abbreviation of the element's name.
  • Atomic Mass: Usually found under the symbol, used to calculate the molar mass.
The periodic table is essential because it helps us quickly find the molar mass of elements, aiding in the calculation of moles and balancing chemical equations with stoichiometry. This well-arranged tool is indispensable for anyone studying or working in scientific fields.
Chemical Elements
Chemical elements are pure substances consisting of only one type of atom. Each element has a unique set of properties that differentiate it from others. Elements are the basic building blocks of matter and are represented by chemical symbols, like Al for aluminum or Cr for chromium.

These elements can exist as single atoms, molecules, or ions and partake in chemical reactions to form compounds. Knowing about chemical elements is critical because it helps us predict how substances interact in nature and controlled environments alike. For students and scientists, mastering the properties of elements is fundamental for safely handling chemicals and understanding molecular interactions.
Stoichiometry
Stoichiometry is the heart of chemical equations, allowing scientists to predict the outcomes of reactions quantitatively. It involves calculations that relate the quantities of reactants and products in a chemical reaction.
  • Mole Ratio: Using coefficients from balanced chemical equations to convert between moles of different substances.
  • Mass-to-Mass Calculations: Converting given mass of one substance to another using molar mass.
By applying stoichiometry, one can determine the amount of each reactant needed to produce a desired amount of product. It ensures efficiency and safety in chemical processes, making it essential for both academic and professional chemistry settings.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider the two ionic compounds \(\mathrm{NaCl}\) and CaO. In which compound are the cation-anion attractive forces stronger? Explain your answer.

Cacodyl, a compound containing arsenic, was reported in 1842 by the German chemist Robert Wilhelm Bunsen. It has an almost intolerable garlic-like odor. Its molar mass is \(210 \mathrm{g} / \mathrm{mol}\), and it is \(22.88 \%\) C, \(5.76 \%\) H, and \(71.36 \%\) As. Determine its empirical and molecular formulas.

Give the formula for each of the following ionic compounds: (a) ammonium carbonate (b) calcium iodide (c) copper(II) bromide (d) aluminum phosphate (e) silver(I) acetate

Tin metal (Sn) and purple iodine (I_2) combine to form orange, solid tin iodide with an unknown formula. $$\text { Sn metal }+\text { solid } \mathrm{I}_{2} \rightarrow \text { solid } \mathrm{Sn}_{x} \mathrm{I}_{y}$$ Weighed quantities of Sn and \(\mathrm{I}_{2}\) are combined, where the quantity of Sn is more than is needed to react with all of the iodine. After \(\operatorname{Sn}_{x}\) I has been formed, it is isolated by filtration. The mass of excess tin is also determined. The following data were collected: Mass of tin (Sn) in the original mixture \(1.056 \mathrm{g}\) Mass of iodine \(\left(\mathrm{I}_{2}\right)\) in the original mixture \(1.947 \mathrm{g}\) Mass of tin (Sn) recovered after reaction \(0.601 \mathrm{g}\) What is the empirical formula of the tin iodide obtained?

To find the empirical formula of tin oxide, you first react tin metal with nitric acid in a porcelain crucible. The metal is converted to tin nitrate, but, on heating the nitrate strongly, brown nitrogen dioxide gas is evolved and tin oxide is formed. In the laboratory you collect the following data: Mass of crucible Mass of crucible plus tin \(14.710 \mathrm{g}\) Mass of crucible after heating \(15.048 \mathrm{g}\) What is the empirical formula of tin oxide?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free