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Ozone, \(\mathrm{O}_{3,}\) in the Earth's upper atmosphere decomposes according to the equation $$ 2 \mathrm{O}_{3}(\mathrm{g}) \rightarrow 3 \mathrm{O}_{2}(\mathrm{g}) $$ The mechanism of the reaction is thought to proceed through an initial fast, reversible step followed by a slow, second step. Step 1: Fast, reversible $$ \mathrm{O}_{3}(\mathrm{g}) \rightleftarrows \mathrm{O}_{2}(\mathrm{g})+\mathrm{O}(\mathrm{g}) $$ Step 2: Slow $$ \mathrm{O}_{3}(\mathrm{g})+\mathrm{O}(\mathrm{g}) \rightarrow 2 \mathrm{O}_{2}(\mathrm{g}) $$ (a) Which of the steps is rate-determining? (b) Write the rate equation for the rate-determining step.

Short Answer

Expert verified
Step 2 is the rate-determining step; rate equation: \(\text{Rate} = k[\mathrm{O}_{3}][\mathrm{O}]\).

Step by step solution

01

Identify the Rate-Determining Step

The rate-determining step is usually the slowest step in a reaction mechanism. Here, Step 2 is labeled as 'Slow.' Therefore, Step 2 is the rate-determining step.
02

Write the Rate Equation for the Slow Step

The rate equation can be derived from the rate-determining step. In Step 2, the reactants are \(\mathrm{O}_{3}(\mathrm{g})\) and \(\mathrm{O}(\mathrm{g})\). The rate law is based on these reactants, thus the rate equation is: \(\text{Rate} = k[\mathrm{O}_{3}][\mathrm{O}]\), where \(k\) is the rate constant.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Mechanism
A reaction mechanism is a sequence of elementary steps that leads to the overall chemical reaction. Each step represents a single transformation where bonds are broken and formed, involving a few molecules at a time. Understanding the mechanism helps us predict the rate of reaction and describe how the reactants transform into products.
In the exercise about ozone decomposition, the reaction mechanism consists of two steps:
  • Step 1: Fast and reversible; \(\mathrm{O}_{3}(g) \rightleftharpoons \mathrm{O}_{2}(g) + \mathrm{O}(g)\)
  • Step 2: Slow and irreversible; \(\mathrm{O}_{3}(g) + \mathrm{O}(g) \rightarrow 2\mathrm{O}_{2}(g)\)
The first step involves the formation of \(\mathrm{O}(g)\) and is quickly reversible, reaching a temporary equilibrium. In contrast, the second step consumes \(\mathrm{O}(g)\), producing oxygen molecules. Together, these steps describe how ozone decomposes in the upper atmosphere.
Rate-determining Step
In a multistep reaction, one step typically controls the reaction speed, called the rate-determining step. It's often the slowest step because it forms a bottleneck that dictates how quickly the overall reaction can proceed.
From the given reaction mechanism of ozone decomposition, the second step (\(\mathrm{O}_{3}(g) + \mathrm{O}(g) \rightarrow 2\mathrm{O}_{2}(g)\)) is labeled as 'Slow.' This indicates that it is the rate-determining step. Since it's the slowest step, it limits the speed at which the ozone decomposes into oxygen molecules.
Understanding which step is rate-determining allows chemists to focus on that part to control or optimize the reaction rate. If this step can be sped up, the entire reaction could potentially proceed faster.
Rate Equation
The rate equation quantifies the speed of a reaction, expressed usually in terms of the concentration of reactants for the rate-determining step. This mathematical representation allows us to calculate the reaction rate and understand how changes in concentration affect it.
For the ozone decomposition mechanism, the rate-determining step involves \(\mathrm{O}_{3}(g)\) and \(\mathrm{O}(g)\). Therefore, its rate equation is: \[\text{Rate} = k[\mathrm{O}_{3}][\mathrm{O}]\] Here:
  • \(k\) is the rate constant, a factor that includes the reaction's temperature sensitivity and other conditions.
  • The concentration terms \([\mathrm{O}_{3}]\) and \([\mathrm{O}]\) indicate that the rate depends on both ozone and atomic oxygen concentrations.
This equation is crucial for calculating the reaction rate and performing experiments that can validate the proposed mechanism or help discover unknown components affecting the reaction.

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Most popular questions from this chapter

Radioactive gold- 198 is used in the diagnosis of liver problems. The half- life of this isotope is 2.7 days. If you begin with a 5.6 -mg sample of the isotope, how much of this sample remains after 1.0 day?

At temperatures below \(500 \mathrm{K}\), the reaction between carbon monoxide and nitrogen dioxide $$ \mathrm{CO}(\mathrm{g})+\mathrm{NO}_{2}(\mathrm{g}) \rightarrow \mathrm{CO}_{2}(\mathrm{g})+\mathrm{NO}(\mathrm{g}) $$ has the following rate equation: Rate \(=k\left[\mathrm{NO}_{2}\right]^{2}\) Which of the three mechanisms suggested here best agrees with the experimentally observed rate equation? Mechanism 1 \(\quad\) single, elementary step $$ \mathrm{NO}_{2}+\mathrm{CO} \rightarrow \mathrm{CO}_{2}+\mathrm{NO} $$ Mechanism \(2 \quad\) Two steps Slow $$ \mathrm{NO}_{2}+\mathrm{NO}_{2} \rightarrow \mathrm{NO}_{3}+\mathrm{NO} $$ Fast $$ \mathrm{NO}_{3}+\mathrm{CO} \rightarrow \mathrm{NO}_{2}+\mathrm{CO}_{2} $$ Mechanism 3 Two steps Slow $$ \mathrm{NO}_{2} \rightarrow \mathrm{NO}+\mathrm{O} $$ Fast $$ \mathrm{CO}+\mathrm{O} \rightarrow \mathrm{CO}_{2} $$

The following statements relate to the reaction for the formation of HI: $$ \mathrm{H}_{2}(\mathrm{g})+\mathrm{I}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{HI}(\mathrm{g}) \quad \text { Rate }=k\left[\mathrm{H}_{2}\right]\left|\mathrm{I}_{2}\right| $$ Determine which of the following statements are true. If a statement is false, indicate why it is incorrect. (a) The reaction must occur in a single step. (b) This is a second-order reaction overall. (c) Raising the temperature will cause the value of \(k\) to decrease. (d) Raising the temperature lowers the activation energy for this reaction. (e) If the concentrations of both reactants are doubled, the rate will double. (f) Adding a catalyst in the reaction will cause the initial rate to increase.

The decomposition of nitrogen dioxide at a high temperature $$ \mathrm{NO}_{2}(\mathrm{g}) \rightarrow \mathrm{NO}(\mathrm{g})+1 / 2 \mathrm{O}_{2}(\mathrm{g}) $$ is second-order in this reactant. The rate constant for this reaction is \(3.40 \mathrm{L} / \mathrm{mol} \cdot \mathrm{min} .\) Determine the time needed for the concentration of \(\mathrm{NO}_{2}\) to decrease from \(2.00 \mathrm{mol} / \mathrm{L}\) to \(1.50 \mathrm{mol} / \mathrm{L}\).

Many biochemical reactions are catalyzed by acids. A typical mechanism consistent with the experimental results (in which HA is the acid and X is the reactant) is Step \(1: \quad\) Fast, reversible: \(\quad \mathrm{HA} \rightleftarrows \mathrm{H}^{+}+\mathrm{A}^{-}\) Step \(2: \quad\) Fast, reversible: \(\quad \mathrm{X}+\mathrm{H}^{+} \rightleftharpoons \mathrm{XH}^{+}\) Step 3: Slow \(\mathrm{XH}^{+} \rightarrow\) products What rate law is derived from this mechanism? What is the order of the reaction with respect to HA? How would doubling the concentration of HA affect the reaction?

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