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Give resonance structure(s) for the hydroxide ion \([\mathrm{OH}]^{-} .\) What description of the bonding in this ion does valence bond theory give?

Short Answer

Expert verified
\([ ext{OH}]^-\) has one resonance structure. Valence bond theory describes its bond with \( sp^3 \) hybridization and lone pairs on oxygen.

Step by step solution

01

Draw the Lewis Structure

The hydroxide ion \([ ext{OH}]^-\) consists of an oxygen atom bonded to a hydrogen atom, with an additional electron giving it a negative charge. To draw its Lewis structure: Oxygen (from group 16) has 6 valence electrons, and hydrogen has 1 valence electron. The additional electron (due to the negative charge) is added to oxygen. Thus, the structure is: \[:\overset{..}{O}:\text{---}\overset{..}{H}\] with the negative charge on oxygen.
02

Consider Possible Resonance Structures

Resonance structures are possible when there is more than one valid way to distribute the electrons around the atoms, typically involving double bonds or lone pairs. However, for \([ ext{OH}]^-\), there is only one valid arrangement of atoms without shifting those electrons to other bonds. Thus, the hydroxide ion has a single resonance structure.
03

Understanding Valence Bond Theory

According to Valence Bond Theory, the bonding in the hydroxide ion can be described as the overlap of orbitals. The \( \text{O} \) atom uses its \( sp^3 \) hybridized orbitals, one of which overlaps with the \( s \) orbital of hydrogen to form a sigma bond. The extra electron is accommodated as a lone pair on the oxygen atom, contributing to the ion's charge.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hydroxide Ion
The hydroxide ion, denoted as \([ ext{OH}]^-\), is an important chemical entity consisting of one oxygen atom bonded to one hydrogen atom. It bears a negative charge due to the presence of an extra electron. This negative charge gives the hydroxide ion its characteristic properties and reactivity. Understanding the hydroxide ion is crucial as it commonly appears in various chemical reactions, especially in acid-base chemistry.
  • The extra electron results in a complete octet for oxygen, making it more stable.
  • It acts as a base, meaning it can accept protons (H^+).
  • Key player in reactions such as neutralization, where it combines with protons to form water.
Recognizing the basic structure and behavior of the hydroxide ion can greatly aid in grasping broader chemical concepts.
Lewis Structure
A Lewis structure is a simple way to represent the electron arrangement in molecules and ions. For the hydroxide ion, this structure depicts the bonds between the atoms and the lone pairs of electrons, providing a visual representation of the molecule's electron distribution.
  • Oxygen, part of group 16 in the periodic table, has 6 valence electrons.
  • Hydrogen contributes 1 valence electron.
  • Due to the negative charge, an additional electron is added, giving the hydroxide ion a total of 8 electrons.
To draw the Lewis structure for the hydroxide ion: 1. Place the electrons around the oxygen to satisfy the octet rule. 2. Bond the lone hydrogen atom with oxygen via one of oxygen's available orbitals. 3. Represent lone pair electrons on oxygen for full electron accounting. The resulting structure shows an oxygen atom bonded to a hydrogen atom with three lone pairs on oxygen, highlighting its reactivity and stability.
Valence Bond Theory
Valence Bond Theory offers a detailed explanation of how atoms connect to form molecules, emphasizing the overlap of atomic orbitals. In the case of the hydroxide ion, this theory helps explain the nature of the bond between oxygen and hydrogen.
  • Oxygen is typically \(sp^3\) hybridized, meaning it forms four equivalent orbitals.
  • One \(sp^3\) orbital overlaps with hydrogen's \(s\) orbital, creating a sigma bond.
  • The remaining \(sp^3\) orbitals accommodate the lone pairs and the additional electron, balancing the charge and contributing to the ion's overall stability.
This overlap and hybridization are key to understanding molecular structure and reactivity, showing how the arrangement of orbitals and electrons influences chemical behavior.
Resonance Structures
Resonance structures are a concept used in chemistry to illustrate molecules or ions that cannot be represented by a single Lewis structure. They are alternative representations that account for the possible distribution of electrons. However, the hydroxide ion is unique in that it only has a single valid Lewis structure.Due to its simplicity and the way its electrons are arranged, there are no alternate structures for \([ ext{OH}]^-\) that maintain its stability and satisfy chemical rules. Generally,
  • Resonance structures usually occur in more complex ions or molecules where electrons can be delocalized across multiple bonds.
  • The hydroxide ion's electrons are constrained to a singular configuration without feasible alternatives.
Understanding why the hydroxide ion lacks resonance structures highlights the limitations of electron distribution in simpler ions, contrasting with the behavior of larger, more complex species.

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Most popular questions from this chapter

Write down five ions (cations or anions) that are isoelectronic with neon.

(a) The results of a theoretical study of HCl show that the energies of the valence \(\mathrm{Cl} 3 s\) and \(3 p\) atomic orbitals are -29 and \(-13 \mathrm{eV}\) respectively, and the \(\mathrm{H}\) \(1 s\) atomic orbital lies at \(-14 \mathrm{eV} .\) Using the data and an LCAO approach, construct an approximate MO diagram for the formation of HCl. (b) Use the MO diagram to find the bond order in HCl. Does the MO diagram indicate that HCl is diamagnetic or paramagnetic? (c) Do these last answers agree with conclusions drawn from a Lewis structure for HCl?

Assuming that you apply "isoelectronic' in its strictest sense, which of the following species form isoelectronic pairs? Not all species have a partner: \(\mathrm{Cl}_{2}, \mathrm{CO},\left[\mathrm{O}_{2}\right]^{2-},\left[\mathrm{S}_{2}\right]^{2-}, \mathrm{F}_{2}, \mathrm{Br}_{2}, \mathrm{N}_{2}, \mathrm{NO},\left[\mathrm{O}_{2}\right]^{+}, \mathrm{O}_{2}\)

(a) Is a dipole moment a scalar or vector property? (b) Which of the following gas phase molecules are polar: \(\mathrm{Cl}_{2}, \mathrm{HBr}, \mathrm{IF}, \mathrm{BrCl}, \mathrm{H}_{2} ?\) For those which are polar, draw a diagram that depicts the direction in which the dipole moment acts.

Explain whether or not the two species in each of the following pairs are isoelectronic with one another: (a) He and \(\mathrm{Li}^{+},(\mathrm{b})\left[\mathrm{Se}_{2}\right]^{2-}\) and \(\mathrm{Br}_{2} ;(\mathrm{c}) \mathrm{NO}\) and \(\left[\mathrm{O}_{2}\right]^{+}\) (d) \(\mathrm{F}_{2}\) and \(\mathrm{ClF}\) (e) \(\mathrm{N}_{2}\) and \(\mathrm{P}_{2} ;\) (f) \(\mathrm{P}^{3-}\) and \(\mathrm{Cl}^{-}\)

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