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(a) Explain how thiophene achieves a \(6 \pi\) -aromatic system. (b) What experimental evidence is there for the aromatic character of thiophene? (c) Does thiophene possess more or less aromatic character than furan? Rationalize your answer.

Short Answer

Expert verified
Thiophene is aromatic with a 6 \\(\pi\\) electron system confirmed by its substitution reaction preference and lower hydrogenation heat. It is more aromatic than furan due to better electron delocalization.

Step by step solution

01

Understanding Aromaticity

A compound is aromatic if it is cyclic, planar, completely conjugated, and contains a Huckel number of \(4n+2\) \(\pi\) electrons, where \(_n\) is a non-negative integer. A ring system that follows this rule has increased stability and unique properties due to delocalized \(\pi\) electrons.
02

Analyzing Thiophene

Thiophene is a five-membered ring containing one sulfur atom and four carbon atoms. Each carbon contributes one \(\pi\) electron, while the sulfur atom contributes two \(\pi\) electrons from one of its lone pairs, summing up to a total of six \(\pi\) electrons. This follows the \(4n+2\) rule with \(n=1\), making it aromatic.
03

Experimental Evidence of Aromaticity

The aromatic character of thiophene is supported by its resistance to addition reactions, instead favoring substitution reactions typical of aromatic compounds. Additionally, thiophene's heat of hydrogenation is lower than expected if it were non-aromatic, reflecting its stability due to aromaticity.
04

Comparing with Furan

Furan is another aromatic five-membered ring, similar to thiophene, but it contains an oxygen atom instead of sulfur. The oxygen in furan also provides two \(\pi\) electrons from its lone pair, maintaining \(6 \pi\) electrons in the system. However, sulfur is less electronegative than oxygen, which allows better \(\pi\) electron delocalization in thiophene, giving it more aromatic character compared to furan.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thiophene
Thiophene is a fascinating aromatic compound that stands out due to its unique structure. It is a five-membered heterocyclic ring, meaning it contains one atom other than carbon—specifically, a sulfur atom—connected in the ring. The remaining four positions in the ring are occupied by carbon atoms. Here's how thiophene achieves its aromatic nature:

The central criterion for aromaticity in thiophene is its conjugated \( \pi \) electron system. Each carbon atom in the ring contributes one electron to the \( \pi \) system, while the sulfur atom contributes two additional electrons from one of its lone pairs. This contribution results in a total of six \( \pi \) electrons, making it meet the conditions of Huckel's Rule, which is vital for a compound to be aromatic.
Aromaticity
Aromaticity is a concept that describes the enhanced stability and unique reactivity patterns found in certain cyclic compounds due to the presence of \( \pi \) electron delocalization across their structure.

To determine whether a compound is aromatic, it must satisfy certain conditions:
  • It should be cyclic—meaning the atoms form a closed loop.
  • The compound must be planar, allowing for the overlap of \( \pi \) orbitals across the cyclic system.
  • It should be fully conjugated, with overlapping \( \pi \) bonds throughout the cyclic structure.
  • Lastly, it needs to follow Huckel's Rule, containing \( 4n + 2 \) \( \pi \) electrons.
These rules ensure a compound has the kind of stable electron delocalization seen in benzene, a quintessential aromatic compound.
Huckel's Rule
One of the fundamental guidelines for determining aromaticity within a molecule is Huckel's Rule. This rule outlines the conditions colloquially summarized by the \( 4n+2 \) rule, where \( n \) is a non-negative integer. It predicts that a stable aromatic compound must have a specific number of \( \pi \) electrons that fit the formula. For example:
  • If \( n = 0 \), the compound must have \( 2 \pi \) electrons.
  • If \( n = 1 \), then \( 6 \pi \) electrons are required. This is the case with thiophene.
When thiophene is analyzed, it perfectly fits Huckel’s criteria with its six \( \pi \) electrons, thus imparting its aromatic characteristics.
Heat of hydrogenation
Heat of hydrogenation provides experimental evidence supporting the aromatic nature of a compound like thiophene. It is a measure of the energy released when hydrogen is added to unsaturated organic compounds, illustrating the molecule's stability.

For aromatic compounds, the heat of hydrogenation is notably lower than similar non-aromatic compounds. This is because the structure had already reached a highly stable state due to electron delocalization. Substituting reactions preferred over addition reactions further underline the molecule's stability. Thiophene, in comparison to less stable non-aromatic molecules, shows a smaller heat of hydrogenation, proving its aromatic stability. This makes thiophene resistant to addition reactions, a typical feature of aromatic compounds. In contrast, aromatic molecules like thiophene and even furan favor substitution, showcasing their stability and delocalized electron structure.

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Most popular questions from this chapter

Explain why nucleophilic substitution occurs more readily in 4-chloropyridine than in 3-chloropyridine.

Draw the structures of (a) pyridine, (b) indole, (c) the pyrylium cation and (d) imidazole.

Three isomeric chloro-derivatives of pyridine \((\mathbf{A}, \mathbf{B}\) and \(\mathbf{C}\) ) analyse as containing \(40.58 \%\) C \(, 2.04 \%\) H and \(9.46 \%\) N. The \(^{1}\) H NMR spectroscopic data for the compounds are as follows where \(\mathrm{d}=\) doublet, \(\mathrm{d} \mathrm{d}=\) doublet of doublets and \(\mathrm{t}=\) triplet: $$\begin{array}{ll} \hline \text { Compound } & ^{1} \mathbf{H} \text { NMR } \delta / \text { ppm } \\ \text { A } & 7.66(\mathrm{t}, J=7.6 \mathrm{Hz}) \\ & 7.31(\mathrm{d}, J=7.6 \mathrm{Hz}) \\ \text { B } & 8.64(\mathrm{d}, J=2.1 \mathrm{Hz}) \\ & 8.25(\mathrm{t}, J=2.1 \mathrm{Hz}) \\ \text { C } & 8.70(\mathrm{dd}, J=3.0 \text { and } 0.3 \mathrm{Hz}) \\ & 8.13(\mathrm{dd}, J=9.0 \text { and } 3.0 \mathrm{Hz}) \\ & 7.68(\mathrm{dd}, J=9.0 \text { and } 0.3 \mathrm{Hz}) \\ & \\ \hline \end{array}$$ In each isomer, \(\mathrm{Cl}\) atoms are in either the 2 - or \(3-\) position with respect to the \(\mathrm{N}\) atom. Suggest structures for \(\mathbf{A}, \mathbf{B}\) and \(\mathbf{C}\).

Draw the structures of (a) 4-methylpyridine, (b) 2 -chloropyrrole, (c) 1,4 -dihydropyridine, (d) tetrabromopyrrole, (e) nicotinic acid.

Propose mechanisms for the reaction of 2 -pyridone with a general electrophile, \(\mathrm{E}^{+},\) to give (a) the 3-substituted and (b) the 5-substituted products.

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