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Draw the structures of (a) 4-methylpyridine, (b) 2 -chloropyrrole, (c) 1,4 -dihydropyridine, (d) tetrabromopyrrole, (e) nicotinic acid.

Short Answer

Expert verified
The structures involve modifications of pyridine and pyrrole, with various substitutions such as methyl, chloro, bromo, hydrogens, and carboxyl groups at specified positions.

Step by step solution

01

Understand the Structure of Pyridine

Pyridine is a six-membered aromatic ring with one nitrogen atom. It is similar to benzene, but one CH group is replaced by a nitrogen atom.
02

Drawing 4-Methylpyridine

Start with the pyridine structure. Add a methyl group (CH₃) to the fourth position of the ring, counting the nitrogen atom as the first position.
03

Understand the Structure of Pyrrole

Pyrrole consists of a five-membered aromatic ring with four carbons and one nitrogen atom. Unlike pyridine, it contains two double bonds and the nitrogen is part of the ring in place of one carbon.
04

Drawing 2-Chloropyrrole

Start with a pyrrole ring. Add a chlorine atom (Cl) to the second position of the pyrrole ring, next to the nitrogen atom.
05

Drawing 1,4-Dihydropyridine

Start with the pyridine ring. Reduce it by adding two additional hydrogens, one at the nitrogen and one at the fourth position on the ring, resulting in single bonds at these positions.
06

Drawing Tetrabromopyrrole

Begin with a pyrrole ring. Add four bromine atoms (Br), which can replace hydrogen atoms in all available carbon positions on the pyrrole ring.
07

Nicotinic Acid Structure

Start with the pyridine structure. Add a carboxyl group (COOH) at the third position of the ring, which is known as nicotinic acid or niacin.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Aromatic Compounds
Aromatic compounds are a fascinating category in organic chemistry. These compounds are primarily known for their stable ring-like structures that follow a particular type of electron configuration. This configuration, known as "aromaticity," provides aromatic compounds with unique chemical properties. The most classic example is benzene, which has a six-membered carbon ring with delocalized electrons.

Pyridine and pyrrole are two critical examples of aromatic compounds that contain nitrogen within their rings, differentiating them from benzene.

  • Pyridine: It maintains a six-membered ring structure with one nitrogen atom replacing a CH group from the classic benzene.
  • Pyrrole: It features a five-membered ring that consists of four carbons and one nitrogen atom. The nitrogen in pyrrole is integral to the ring.
These modifications lead to different chemical behaviors and reactivity patterns of pyridine and pyrrole compared to benzene. Pyridine acts much like benzene but with altered electron density, impacting its chemical reactions, while pyrrole is more reactive due to its unique electron configuration.
Heterocyclic Compounds
Heterocyclic compounds feature prominently in organic chemistry because they include atoms other than carbon in their rings, often leading to diverse chemical properties.

Pyridine and pyrrole represent two types of heterocyclic compounds.

  • Pyridine: It is known for its basicity because the lone pair on the nitrogen atom is available, making it less reactive compared to pyrrole.
  • Pyrrole: This compound is relatively less basic than pyridine. The lone pair on nitrogen is part of the aromatic pi-electron system, reducing availability for bonding.
These structural variations impact where substituents like halogens or methyl groups are placed for various chemical syntheses, and they further influence the compound's reactivity and electronic properties. Understanding these aspects is crucial in predicting the behavior of these compounds in different chemical reactions.
Chemical Structure Drawing
Chemical structure drawing is a vital skill for visualizing and understanding the three-dimensional aspects of molecules. This skill involves depicting molecular structures correctly, recognizing how different atoms connect within a molecule.

In exercises like drawing 4-methylpyridine or 2-chloropyrrole, it's crucial first to identify the base structure, such as pyridine or pyrrole, and then to add additional groups at the correct positions.

  • Steps for drawing: Begin with the basic aromatic or heterocyclic ring. Carefully add any substituent groups, ensuring they are attached to the correctly numbered positions around the ring.
  • Recognizing functional groups: Identifying groups like methyl ( CH₃ ) or carboxyl ( COOH ) and their correct placement provides key details about the molecule's identity and chemical behavior.
Mastering chemical structure drawing helps in communicating molecular ideas effectively and laying the foundation for deeper insights into compound analysis and synthesis.

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Most popular questions from this chapter

(a) How many isomers of dimethylpyridine do you expect? Draw their structures and give each a systematic name. (b) Draw diagrams to show the dipole moments in furan and pyrrole.

(a) Explain how thiophene achieves a \(6 \pi\) -aromatic system. (b) What experimental evidence is there for the aromatic character of thiophene? (c) Does thiophene possess more or less aromatic character than furan? Rationalize your answer.

Three isomeric chloro-derivatives of pyridine \((\mathbf{A}, \mathbf{B}\) and \(\mathbf{C}\) ) analyse as containing \(40.58 \%\) C \(, 2.04 \%\) H and \(9.46 \%\) N. The \(^{1}\) H NMR spectroscopic data for the compounds are as follows where \(\mathrm{d}=\) doublet, \(\mathrm{d} \mathrm{d}=\) doublet of doublets and \(\mathrm{t}=\) triplet: $$\begin{array}{ll} \hline \text { Compound } & ^{1} \mathbf{H} \text { NMR } \delta / \text { ppm } \\ \text { A } & 7.66(\mathrm{t}, J=7.6 \mathrm{Hz}) \\ & 7.31(\mathrm{d}, J=7.6 \mathrm{Hz}) \\ \text { B } & 8.64(\mathrm{d}, J=2.1 \mathrm{Hz}) \\ & 8.25(\mathrm{t}, J=2.1 \mathrm{Hz}) \\ \text { C } & 8.70(\mathrm{dd}, J=3.0 \text { and } 0.3 \mathrm{Hz}) \\ & 8.13(\mathrm{dd}, J=9.0 \text { and } 3.0 \mathrm{Hz}) \\ & 7.68(\mathrm{dd}, J=9.0 \text { and } 0.3 \mathrm{Hz}) \\ & \\ \hline \end{array}$$ In each isomer, \(\mathrm{Cl}\) atoms are in either the 2 - or \(3-\) position with respect to the \(\mathrm{N}\) atom. Suggest structures for \(\mathbf{A}, \mathbf{B}\) and \(\mathbf{C}\).

Draw the structures of (a) pyridine, (b) indole, (c) the pyrylium cation and (d) imidazole.

Explain why nucleophilic substitution occurs more readily in 4-chloropyridine than in 3-chloropyridine.

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