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Dimethylformamide (DMF) is a common solvent. In its \(^{13} \mathrm{C}\) NMR spectrum, signals are observed at \(\delta\) 162.4,36.2 and 31.1 ppm. Explain why there are three, and not two, signals.

Short Answer

Expert verified
DMF shows three NMR signals because it contains three distinct carbon environments: carbonyl carbon, and two different methyl groups attached to nitrogen.

Step by step solution

01

Understanding NMR Spectroscopy

Nuclear Magnetic Resonance (NMR) spectroscopy is a technique used to observe the magnetic properties of atomic nuclei. In a molecule, the NMR spectrum can show distinct signals that correspond to different types of carbon environments due to differences in their chemical surroundings.
02

Recognizing the Structure of DMF

Dimethylformamide (DMF) has the molecular structure HCON(CH₃)₂. It consists of three distinct groups or environments: the carbonyl carbon (C=O), the methine carbon (CH) of the methyl groups, and the carbon linked to nitrogen (CH₃).
03

Identifying Unique Carbons in DMF

In DMF, there are three unique carbon environments: the carbonyl carbon, the methyl carbons attached to nitrogen, and the central carbon attached to oxygen and nitrogen. Each of these has a distinct chemical environment.
04

Matching NMR Signals to Carbon Environments

The observed signals at  162.4 ppm typically correspond to the carbonyl carbon due to its downfield shift, which occurs because of the deshielding by oxygen. The signals at 36.2 ppm and 31.1 ppm correspond to the two different CH₃ groups attached to the nitrogen.
05

Explaining Three Signals Instead of Two

Even though the two CH₃ groups in DMF might seem equivalent, they are in different environments due to the structure's asymmetry. As a result, they appear as separate signals in the NMR spectrum.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

13C NMR
13C NMR spectroscopy is a powerful technique that focuses specifically on the carbon atoms within a molecule. Each carbon atom in a molecule can exhibit a distinct signal in the 13C NMR spectrum, depending on its environment. This is because the NMR technique detects the magnetic properties of carbon nuclei.

When a carbon atom is in a unique chemical environment, it will give rise to a unique signal in the 13C NMR spectrum. In Dimethylformamide (DMF), the presence of three distinct carbon environments leads to three separate signals, each representing a different type of carbon atom in the molecule.
  • The carbonyl carbon (C=O) produces a signal due to its unique bonding with oxygen, which significantly influences its chemical environment.
  • The two methyl groups (CH₃) connected to the nitrogen are observed separately because the nitrogen atom creates a distinct local environment for these carbons.
The 13C NMR spectrum serves as a fingerprint for a molecule, providing useful insights into its structure by distinguishing between different types of carbon atoms based on their electronic surroundings.
chemical shift
In NMR spectroscopy, chemical shift is an important concept that helps in identifying different types of carbon atoms in a molecule. It is measured in parts per million (ppm) and is influenced by the electronic environment surrounding the carbon atom.

The chemical shift provides insights into how shielded or deshielded a carbon atom is within the molecular structure.
  • A more deshielded carbon, often due to electronegative elements like oxygen, results in a higher (downfield) chemical shift value. This is typically the case for carbonyl carbons, like in DMF, making them appear at 162.4 ppm in the spectrum.
  • Conversely, carbon atoms that are more shielded by surrounding electron density tend to appear at lower (upfield) ppm values. This is seen in the methyl groups connected to nitrogen in DMF, which have shifts at 36.2 ppm and 31.1 ppm.
Understanding chemical shifts allows chemists to make educated guesses about the types of atoms connected to a particular carbon, assisting in the elucidation of molecular structures.
carbon environments
Carbon environments refer to the different atomic surroundings an individual carbon atom experiences in a molecule. In NMR spectroscopy, these environments are crucial, as each unique carbon environment can lead to a separate signal. In Dimethylformamide (DMF), there are three distinct carbon environments:

  • The carbonyl carbon (C=O) experiences a highly polar environment due to its double bond with oxygen, a highly electronegative atom. This makes it very distinct and responsible for a specific shift in the NMR spectrum.
  • The methyl groups attached to the nitrogen (CH₃-N) have their own unique environment. Though they might appear similar, the asymmetry in the molecule due to other attached atoms ensures that their environments are different enough to result in two separate NMR signals.
  • The centrality and connectivity of the carbon atom attached directly to both nitrogen and oxygen create yet another unique environment, adding to the distinct signals observed in the spectrum.
These varied environments explain the appearance of multiple signals in the 13C NMR spectrum, allowing chemists to piece together the full molecular structure.

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Most popular questions from this chapter

(a) Suggest how each of the following Grignard reagents in \(\mathrm{Et}_{2} \mathrm{O}\) would react with solid \(\mathrm{CO}_{2}\) followed by treatment with \(\mathrm{H}^{+}\). (b) Give a mechanism for one of the reactions.

(a) Suggest likely products from the reaction of acetaldehyde and butanal in the presence of \(\mathrm{NaOH}\) (b) Explain why benzaldehyde does not form an enolate. (c) Suggest a method for converting methyl propanoate to methyl 2-methylbutanoate.

Explain the following observations. (a) The \(^{1} \mathrm{H}\) NMR spectrum of a solution of hexanoic acid contains a signal at \(\delta 11.2 \mathrm{ppm}\) but the signal disappears when \(\mathrm{D}_{2} \mathrm{O}\) is added to the solution. (b) The \(^{13} \mathrm{C}\) NMR spectrum of octanoic acid contains seven signals in the region \(\delta 14.1\) to \(34.3 \mathrm{ppm},\) and one signal at \(\delta 181.1 \mathrm{ppm}\) (c) The \(^{1}\) H NMR spectrum of butanone exhibits a triplet at \(\delta 1.06 \mathrm{ppm},\) a singlet at \(\delta 2.14 \mathrm{ppm}\) and a quartet at \(\delta 2.45 \mathrm{ppm}\) (d) The \(^{1} \mathrm{H}\) NMR spectrum of methyl formate shows signals at \(\delta 8.08\) and 3.77 ppm.

Which of the following would undergo a haloform reaction when treated with \(\mathrm{Br}_{2}\) in the presence of NaOH: (a) pentan-3-one; (b) butanone; (c) propanone; (d) hexan-2-one; (e) hexan-3-one? Give the products in each case where you state the reaction will occur.

Give two synthetic methods by which carbon chains can be lengthened, illustrating your answer with reference to the conversion of 1-chloropentane to hexanoic acid.

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