Chapter 18: Problem 3
What information can you obtain from the following cell diagram? $$\begin{aligned} \mathrm{Pt}\left[\mathrm{H}_{2}(\mathrm{g}, 1 \mathrm{bar})\right] | 2 \mathrm{H}^{+}\left(\mathrm{aq}, 1.0 \mathrm{mol} \mathrm{dm}^{-3}\right) & \\\ & \vdots \mathrm{Ce}^{4+}(\mathrm{aq}), \mathrm{Ce}^{3+}(\mathrm{aq}) | \mathrm{Pt} \end{aligned}$$
Short Answer
Step by step solution
Understanding the Cell Diagram
Identifying the Anode and Cathode
Determining Anode Reaction
Determining Cathode Reaction
Net Cell Reaction
Potential Differences and Equilibrium
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cell Diagram
Furthermore, the diagram includes the electrode materials and the concentrations or pressures of substances in the reaction. For example, in the provided cell diagram, Pt is used as an inert electrode, and you can observe phase boundaries between gaseous, solid, and aqueous states. Understanding these representations are crucial for analyzing and predicting the electrochemical behavior of the system.
- The left side involves oxidation and is called the anode half-cell.
- The right side involves reduction and is called the cathode half-cell.
- Concentration and pressure details are included to give full reaction context.
Anode Reaction
The reaction at the anode can be described by the equation:\[H_2(g) \rightarrow 2H^+(aq) + 2e^-\]This depicts hydrogen molecules losing electrons, making the electrons available for the external circuit to transport. The free electrons travel from the anode through the external circuit to reach the cathode, thus making a continuous flow of electric current.
- Oxidation involves loss of electrons.
- This process contributes electrons to the circuit.
- It transforms molecules from their elemental state to ionic form.
Cathode Reaction
The reaction occurring at the cathode is represented as:\[Ce^{4+}(aq) + e^- \rightarrow Ce^{3+}(aq)\]During this reaction, cerium ions accept an electron from the external circuit, reducing its oxidation state by one unit. The flow of electrons means that the electric current is driving the chemical change at the cathode.
- Reduction involves gaining electrons.
- This reaction balances the electrons lost at the anode.
- It alters the oxidation state of ions.
Galvanic Cell
In our example, the galvanic cell involves two separate half-cells: one being the hydrogen-gas half-cell and the other containing cerium ions. These half-cells are connected by a wire and often a salt bridge which completes the circuit, allowing ions to flow and maintain charge balance.
The spontaneous reactions occurring in each half-cell result in a net flow of electrons from anode to cathode through the external circuit, providing useful electrical work. The cell's arrangement indicates the spontaneity and is an important concept in thermodynamics and electrochemistry.
- Galvanic cells consist of two half-cells.
- They spontaneously convert chemical to electrical energy.
- Useful in batteries and corrosion prevention.