Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Calculate the amount of solution ( \(\mathrm{g}\) or \(\mathrm{mL}\) ) that contains each of the following amounts of solute: a. \(7.50 \mathrm{~g}\) of \(\mathrm{NaCl}\) from a \(2.0 \%(\mathrm{~m} / \mathrm{m}) \mathrm{NaCl}\) solution b. \(4.0 \mathrm{~g}\) of \(\mathrm{NaF}\) from a \(25 \%(\mathrm{~m} / \mathrm{v}) \mathrm{NaF}\) solution c. \(20.0 \mathrm{~g}\) of \(\mathrm{KBr}\) from an \(8.0 \%(\mathrm{~m} / \mathrm{m}) \mathrm{KBr}\) solution

Short Answer

Expert verified
a) 375 g b) 16 mL c) 250 g

Step by step solution

Achieve better grades quicker with Premium

  • Unlimited AI interaction
  • Study offline
  • Say goodbye to ads
  • Export flashcards

Over 22 million students worldwide already upgrade their learning with Vaia!

01

Understand the formula for mass/mass percentage

The mass/mass percentage concentration formula is given by: \[ \text{Mass percentage} = \frac{\text{mass of solute}}{\text{mass of solution}} \times 100 \ \text{For example, } 2.0\text{ % (m/m) } \text{NaCl}\] This means that 2 grams of NaCl are present in every 100 grams of solution.
02

Calculate the total mass of the solution for (a)

Given: \[7.50 \text{ g NaCl in a } 2.0\text{ % (m/m) } \text{NaCl solution} \] Rearrange the formula to solve for the mass of the solution: \[ \text{Mass of solution} = \frac{\text{mass of solute}}{\text{percentage}} \times 100 \ = \frac{7.50\text{ g}}{2.0} \times 100 \ = 375 \text{ g} \]
03

Understand the formula for mass/volume percentage

The mass/volume percentage concentration formula is given by: \[ \text{Mass/volume percentage} = \frac{\text{mass of solute}}{\text{volume of solution}} \times 100 \ \text{For example, } 25\text{ % (m/v) } \text{NaF}\] This means that 25 grams of NaF are present in every 100 mL of solution.
04

Calculate the solution volume for (b)

Given: \[4.0 \text{ g NaF in a } 25\text{ % (m/v) } \text{NaF solution} \] Rearrange the formula to solve for the volume of the solution: \[ \text{Volume of solution} = \frac{\text{mass of solute}}{\text{percentage}} \times 100 \ = \frac{4.0\text{ g}}{25} \times 100 \ = 16 \text{ mL} \]
05

Calculate the total mass of the solution for (c)

Given: \[20.0 \text{ g KBr in an } 8.0\text{ % (m/m) } \text{KBr solution} \] Rearrange the formula to solve for the mass of the solution: \[ \text{Mass of solution} = \frac{\text{mass of solute}}{\text{percentage}} \times 100 \ = \frac{20.0\text{ g}}{8.0} \times 100 \ = 250 \text{ g} \]

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

mass/mass percentage
Mass/mass percentage is an important concept in solution chemistry.
It tells us the concentration of a solute in a solution, expressed as a percentage of the total mass.
The formula for mass/mass percentage is given by:
\[ \text{Mass percentage} = \frac{\text{mass of solute}}{\text{mass of solution}} \times 100 \]

For example, if we have a 2.0% (m/m) NaCl solution, it means there are 2 grams of NaCl in every 100 grams of the solution. Understanding this concept helps to calculate the amount of solute or the total mass of the solution.

Let's see it in practice: Given 7.50 grams of NaCl in a 2.0% (m/m) NaCl solution, the mass of the solution is calculated as:
\[ \text{Mass of solution} = \frac{\text{mass of solute}}{\text{percentage}} \times 100 \text{Mass of solution} = \frac{7.50 \text{ g}}{2.0} \times 100 \text{Mass of solution} = 375 \text{ g} \]

So, we need 375 grams of the NaCl solution to get 7.50 grams of NaCl.
mass/volume percentage
Mass/volume percentage is another way to express solution concentration.
In this method, the mass of the solute is compared with the volume of the solution rather than its mass.

The formula for mass/volume percentage is:
\[ \text{Mass/volume percentage} = \frac{\text{mass of solute}}{\text{volume of solution}} \times 100 \]

For instance, if we have a 25% (m/v) NaF solution, it means there are 25 grams of NaF in every 100 mL of solution.

To see how it works: Given 4.0 grams of NaF in a 25% (m/v) NaF solution, the volume of the solution is calculated by rearranging the formula:
\[ \text{Volume of solution} = \frac{\text{mass of solute}}{\text{percentage}} \times 100 \text{Volume of solution} = \frac{4.0 \text{ g}}{25} \times 100 \text{Volume of solution} = 16 \text{ mL} \]

Therefore, we need 16 mL of the NaF solution to get 4.0 grams of NaF.
solution concentration formulas
Solution concentration formulas help us to determine the strength of a solution.
They quantify how much solute is present in a given amount of solution.

Two common concentration formulas are:
  • Mass/volume percentage
  • Mass/mass percentage

Each formula serves a different purpose and is used based on whether the problem provides mass or volume.

For example:
- Mass/mass percentage is used when both solute and solution are measured by mass. \[ \text{Mass percentage} = \frac{\text{mass of solute}}{\text{mass of solution}} \times 100 \]
- Mass/volume percentage is employed when the solute is given in mass and the solution in volume. \[ \text{Mass/volume percentage} = \frac{\text{mass of solute}}{\text{volume of solution}} \times 100 \]

Understanding how and when to use these formulas can make solving concentration problems less confusing.
solute and solution calculations
Solute and solution calculations are essential for determining the exact amounts of solute and solution required.

To master these calculations, always follow these steps:
  • Identify the given quantities (mass of solute, percentage concentration).
  • Determine the type of concentration (mass/mass or mass/volume).
  • Use the corresponding formula to solve for the unknown quantity.

For instance, with mass/mass percentage:
Given 20.0 grams of KBr in an 8.0% (m/m) KBr solution, we find the mass of the solution as:
\[ \text{Mass of solution} = \frac{\text{mass of solute}}{\text{percentage}} \times 100 \text{Mass of solution} = \frac{20.0 \text{ g}}{8.0} \times 100 \text{Mass of solution} = 250 \text{ g} \]

By understanding solute and solution calculations, you can effectively tackle chemistry problems involving various concentrations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Calculate the molarity of the solution when water is added to prepare each of the following: a. \(25.0 \mathrm{~mL}\) of a \(18.0 \mathrm{M} \mathrm{HCl}\) solution is diluted to \(500 . \mathrm{mL}\) b. \(50.0 \mathrm{~mL}\) of a \(1.50 \mathrm{M} \mathrm{NaCl}\) solution is diluted to \(125 \mathrm{~mL}\) c. \(4.50 \mathrm{~mL}\) of a \(8.50 \mathrm{M} \mathrm{KOH}\) solution is diluted to \(75.0 \mathrm{~mL}\)

A solution contains \(4.56 \mathrm{~g}\) of \(\mathrm{KCl}\) in \(175 \mathrm{~mL}\) of solution. If the density of the \(\mathrm{KCl}\) solution is \(1.12 \mathrm{~g} / \mathrm{mL}\), what are the mass percent \((\mathrm{m} / \mathrm{m})\) and molarity (M) for the potassium chloride solution?

Calculate the mass/volume percent \((\mathrm{m} / \mathrm{v})\) for the solute in each of the following solutions: a. \(75 \mathrm{~g}\) of \(\mathrm{Na}_{2} \mathrm{SO}_{4}\) in \(250 \mathrm{~mL}\) of \(\mathrm{Na}_{2} \mathrm{SO}_{4}\) solution b. \(39 \mathrm{~g}\) of sucrose in \(355 \mathrm{~mL}\) of a carbonated drink

A solution is prepared with \(70.0 \mathrm{~g}\) of \(\mathrm{HNO}_{3}\) and \(130.0 \mathrm{~g}\) of \(\mathrm{H}_{2} \mathrm{O}\). It has a density of \(1.21 \mathrm{~g} / \mathrm{mL}\). a. What is the mass percent \((\mathrm{m} / \mathrm{m})\) of the \(\mathrm{HNO}_{3}\) solution? b. What is the total volume of the solution? c. What is the mass/volume percent \((\mathrm{m} / \mathrm{v}) ?\) d. What is its molarity (M)?

State whether each of the following refers to a saturated or unsaturated solution: a. A crystal added to a solution does not change in size. b. A sugar cube completely dissolves when added to a cup of coffee.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free