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In the fermentation of glucose (wine making), \(780 \mathrm{~mL}\) of \(\mathrm{CO}_{2}\) gas was produced at \(37^{\circ} \mathrm{C}\) and \(1.00 \mathrm{~atm} .\) What is the volume (L) of the gas when measured at \(22{ }^{\circ} \mathrm{C}\) and \(675 \mathrm{mmHg}\) ?

Short Answer

Expert verified
0.835 L

Step by step solution

01

Identify the Known Variables

Before solving the problem, let's identify the known variables and convert them to appropriate units if needed. We have:Initial volume, \(V_1 = 780 \text{ mL} = 0.780 \text{ L}\)Initial temperature, \(T_1 = 37^{\text{o}}\text{C} = 37 + 273 = 310 \text{ K}\)Initial pressure, \(P_1 = 1.00 \text{ atm}\)Final temperature, \(T_2 = 22^{\text{o}}\text{C} = 22 + 273 = 295 \text{ K}\)Final pressure, \(P_2 = 675 \text{ mmHg} = \frac{675}{760} \text{ atm} = 0.888 \text{ atm}\)
02

Apply the Combined Gas Law

With the variables identified, use the Combined Gas Law:\[\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}\]Isolating \(V_2\):\[V_2 = \frac{P_1 V_1 T_2}{P_2 T_1}\]
03

Substitute the Known Values

Substitute the known values into the equation found in Step 2:\[V_2 = \frac{(1.00 \text{ atm})(0.780 \text{ L})(295 \text{ K})}{(0.888 \text{ atm})(310 \text{ K})}\]
04

Calculate the Result

Perform the calculation:\[V_2 \approx \frac{(1.00)(0.780)(295)}{(0.888)(310)} \approx \frac{229.8}{275.28} \approx 0.835 \text{ L}\]
05

Conclusion

The volume of the gas at the new conditions is approximately 0.835 L.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gas Laws
Gas laws describe how the volume, pressure, and temperature of a gas relate to each other. They provide mathematical relationships that help predict how a gas will behave under different conditions. The Combined Gas Law is one such relationship, combining Boyle's, Charles's, and Gay-Lussac's laws into one equation: \[\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}\] where:
  • \( P \) represents pressure
  • \( V \) represents volume
  • \( T \) represents temperature
The Combined Gas Law shows the inverse relationship between pressure and volume while indicating the direct relationship between volume and temperature.
Temperature and Pressure Conversions
Conversions ensure that the units for temperature and pressure are consistent when using gas laws. For temperature, you must convert degrees Celsius to Kelvin because gas law equations require absolute temperature. The conversion is simple: \[T_{\mathrm{K}} = T_{\mathrm{C}} + 273\] For pressure, units can vary (atm, mmHg, kPa, etc.), so it's essential to convert to the same unit. If you're given pressure in mmHg and need to convert to atm, use the following conversion: \[ 1 \: \mathrm{atm} = 760 \: \mathrm{mmHg} \] So, to convert from mmHg to atm: \[ P_{\mathrm{atm}} = \frac{P_{\mathrm{mmHg}}}{760}\] These conversions are crucial for accurate calculations in gas law problems.
Ideal Gas Behavior
Ideal gas behavior assumes that gas molecules do not attract or repel each other and occupy negligible volume. Real gases deviate from ideal behavior at high pressures and low temperatures. However, for most gas law calculations, we assume ideal gas behavior for simplicity. Using the ideal gas law, we can derive approximate solutions for real-world gas problems: \[PV = nRT\] where:
  • \( P \) is pressure
  • \( V \) is volume
  • \( n \) is the number of moles of gas
  • \( R \) is the universal gas constant
  • \( T \) is temperature in Kelvin
Understanding ideal gas behavior simplifies problem-solving and lets us use equations like the Combined Gas Law more effectively.
Problem-Solving in Chemistry
Effective problem-solving in chemistry involves understanding the core principles and applying them step by step. When tackling gas law problems:
  • Identify all known variables and convert to appropriate units
  • Choose the correct gas law based on the given data
  • Manipulate the equation to solve for the unknown variable
  • Substitute the known values into the equation
  • Perform the calculation carefully
For instance, in our initial problem, knowing how to convert temperature and pressure correctly and applying the Combined Gas Law allowed us to find the volume of CO₂ at new conditions. Remember to always double-check units and calculations for accuracy to avoid errors.

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Most popular questions from this chapter

A liquid is placed in a 25.0-L flask. At \(140{ }^{\circ} \mathrm{C}\), the liquid evaporates completely to give a pressure of \(0.900 \mathrm{~atm}\). If the flask can withstand pressures up to \(1.30 \mathrm{~atm}\), calculate the maximum temperature to which the gas can be heated without breaking the flask.

Use the words inspiration or expiration to describe the part of the breathing cycle that occurs as a result of each of the following: a. The diaphragm contracts (flattens out). b. The volume of the lungs decreases. c. The pressure within the lungs is less than that of the atmosphere.

Use the kinetic molecular theory of gases to explain each of the following: a. Gases move faster at higher temperatures. b. Gases can be compressed much more than liquids or solids.

As seen in Chapter 1, one teragram \((\mathrm{Tg})\) is equal to \(10^{12} \mathrm{~g} .\) In \(2000, \mathrm{CO}_{2}\) emissions from fuels used for transportation in the United States was \(1990 \mathrm{Tg}\). In 2020, it is estimated that \(\mathrm{CO}_{2}\) emissions from the fuels used for transportation in the United States will be \(2760 \mathrm{Tg}\). a. Calculate the number of kilograms of \(\mathrm{CO}_{2}\) emitted in the years 2000 and 2020 . b. Calculate the number of moles of \(\mathrm{CO}_{2}\) emitted in the years 2000 and \(2020 .\) c. What is the increase, in megagrams, for the \(\mathrm{CO}_{2}\) emissions between the years 2000 and \(2020 ?\)

Use the kinetic molecular theory of gases to explain each of the following: a. A container of nonstick cooking spray explodes when thrown into a fire. b. The air in a hot-air balloon is heated to make the balloon rise.

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