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An oxygen tank contains oxygen \(\left(\mathrm{O}_{2}\right)\) at a pressure of \(2.00 \mathrm{~atm} .\) What is the pressure in the tank in terms of the following units? a. torr b. \(\mathrm{mmHg}\)

Short Answer

Expert verified
1520 \mathrm{~torr}; 1520 \mathrm{~mmHg}

Step by step solution

01

- Identify the given pressure

The pressure of oxygen \(\left(\mathrm{O}_{2}\right)\) in the tank is given as \(2.00 \mathrm{~atm}.\)
02

- Understand the conversions

Remember that \(1 \mathrm{~atm} = 760 \mathrm{~torr}\) and \(1 \mathrm{~torr} = 1 \mathrm{~mmHg}\).
03

- Convert atm to torr

Multiply the given pressure in \(\mathrm{~atm}\) by the conversion factor to get the pressure in \(\mathrm{~torr}\).\[2.00 ~\mathrm{~atm} \times 760 ~\mathrm{~torr/atm} = 1520 ~\mathrm{~torr} \]
04

- Convert atm to mmHg

Since \(1~\mathrm{~torr} = 1~\mathrm{~mmHg}\), the pressure in \(\mathrm{~mmHg}\) will be the same as in \(\mathrm{~torr}\). Therefore, the pressure is \1520 \mathrm{~mmHg}.\

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

atm to torr conversion
Atmosphere (abbreviated as atm) and torr are both units of pressure. In many scientific contexts, converting these units is necessary for precise calculations and comparisons.
One atmosphere is defined as equal to 760 torr.
So, if you need to convert a pressure value from atm to torr, you can do this by multiplying the pressure in atm by 760. This makes sense, because you are scaling up from a larger unit to a smaller unit. For example:
If you have a pressure of 2.00 atm and you want to convert it to torr, the calculation would be:
\[2.00 ~ atm \times 760 ~ \frac{torr}{atm} = 1520 ~ torr\]Now, it's clear: 2.00 atm is equal to 1520 torr.
atm to mmHg conversion
Understanding the relationship between atmospheres (atm) and millimeters of mercury (mmHg) is crucial in many fields, such as chemistry and medicine.
One atmosphere (atm) is defined as 760 mmHg. This unit comes from the historical use of mercury in pressure measurement instruments, like barometers.
Since the relationship between torr and mmHg is direct (1 torr = 1 mmHg), converting from atm to mmHg follows the same process as converting atm to torr.
For a given pressure of 2.00 atm, the conversion to mmHg would be:
\[2.00 ~ atm \times 760 ~ \frac{mmHg}{atm} = 1520 ~ mmHg\]Hence, 2.00 atm is equal to 1520 mmHg.
gas laws
Gas laws are fundamental in understanding the behavior of gases under different conditions of pressure, volume, and temperature.
Here are some key gas laws:
  • Boyle's Law: This law describes how the pressure of a gas tends to increase as the volume of the container decreases, provided the temperature and amount of gas remain constant. It can be represented as: \[ P_1V_1 = P_2V_2\]
  • Charles's Law: This law states that the volume of a gas is directly proportional to its temperature (in kelvin) when the pressure and amount of gas are constant: \[ \frac{V_1}{T_1} = \frac{V_2}{T_2}\]
  • Avogadro's Law: This principle explains that the volume of a gas is directly proportional to the amount of gas (in moles) when the pressure and temperature remain constant: \[ \frac{V_1}{n_1} = \frac{V_2}{n_2}\]
These laws are cornerstones for understanding more complex concepts like the Ideal Gas Law, which combines them into a single equation: \[ PV = nRT\]

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Most popular questions from this chapter

A 10.0-L balloon contains helium gas at a pressure of \(655 \mathrm{mmHg}\). What is the new pressure, in \(\mathrm{mmHg}\), of the helium gas at each of the following volumes, if there is no change in temperature or amount of gas? a. \(20.0 \mathrm{~L}\) b. \(2.50 \mathrm{~L}\) c. \(1500 . \mathrm{mL}\)

Use the kinetic molecular theory of gases to explain each of the following: a. Gases move faster at higher temperatures. b. Gases can be compressed much more than liquids or solids.

Solve for the new pressure, in torr, for each of the following, if \(n\) and \(V\) are constant: a. A gas with an initial pressure of 1200 torr at \(155^{\circ} \mathrm{C}\) is cooled to \(0{ }^{\circ} \mathrm{C}\). b. A gas in an aerosol can with an initial pressure of \(1.40\) atm at \(12^{\circ} \mathrm{C}\) is heated to \(35^{\circ} \mathrm{C}\).

Two flasks of equal volume and at the same temperature contain different gases. One flask contains \(1.00 \mathrm{~g}\) of \(\mathrm{Ne}\), and the other flask contains \(1.00 \mathrm{~g}\) of He. Which of the following statements are correct? Explain your answers. a. Both flasks contain the same number of atoms. b. The pressures in the flasks are the same. c. The flask that contains helium has a higher pressure than the flask that contains neon. d. The densities of the gases are the same.

A sample of nitrogen \(\left(\mathrm{N}_{2}\right)\) has a volume of \(50.0 \mathrm{~L}\) at a pressure of \(760 . \mathrm{mmHg}\). What is the volume, in liters, of the gas at each of the following pressures, if there is no change in temperature and amount of gas? a. \(1500 \mathrm{mmHg}\) b. \(4.00 \mathrm{~atm}\) c. \(0.500 \mathrm{~atm}\)

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