Chapter 6: Problem 16
The air in a 5.00-L tank has a pressure of \(1.20\) atm. What is the new pressure, in atm, when the air is placed in tanks that have the following volumes, if there is no change in temperature and amount of gas? a. \(1.00 \mathrm{~L}\) b. \(2500 . \mathrm{mL}\) c. \(750 . \mathrm{mL}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
gas laws
pressure-volume relationship
Let's look at the formula from Boyle's Law:
\( P_1 V_1 = P_2 V_2 \)
Here, \( P_1 \) and \( V_1 \) represent the initial pressure and volume, while \( P_2 \) and \( V_2 \) represent the new pressure and volume. By using this formula, you can calculate how changes in volume will affect the pressure of the gas.
ideal gas law
Here, \( P \) represents pressure, \( V \) is volume, \( n \) is the number of moles of gas, \( R \) is the ideal gas constant, and \( T \) is temperature in Kelvin. This law is useful for calculating the behavior of gases under a variety of conditions. Though we did not use the Ideal Gas Law directly in this exercise, understanding this foundational formula helps reinforce why Boyle's Law, a component of the Ideal Gas Law, holds true. The Ideal Gas Law assumes that gas particles do not attract or repel each other and that they occupy no volume themselves, which is often a good approximation for many gases under standard conditions.
inverse proportionality
\( P \propto \frac{1}{V} \)
This equation highlights how increasing the volume will reduce the pressure, and decreasing the volume will increase the pressure. Understanding inverse proportionality helps you predict how changes to your gas's volume will affect its pressure and vice versa, allowing for accurate problem-solving in related exercises.