Chapter 5: Problem 40
Indicate each of the following as an oxidation or a reduction: a. \(\mathrm{O}_{2}(g)+4 e^{-} \longrightarrow 2 \mathrm{O}^{2-}(a q)\) b. \(\mathrm{Al}(s) \longrightarrow \mathrm{Al}^{3+}(a q)+3 e^{-}\) c. \(\mathrm{Fe}^{3+}(a q)+e^{-} \longrightarrow \mathrm{Fe}^{2+}(a q)\) d. \(2 \mathrm{Br}^{-}(a q) \longrightarrow \mathrm{Br}_{2}(l)+2 e^{-}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electron Transfer
When an atom loses electrons, another atom must gain them. This movement is what drives oxidation and reduction reactions. Always remember:
- Loss of electrons = Oxidation
- Gain of electrons = Reduction
Understanding electron transfer helps you see the bigger picture of how oxidation and reduction are linked.
Oxidation
Consider the example \[\text{\text{Al}(s) \rightarrow \text{\text{Al}^{3+}(a q)} + 3 e^{-}} \]. Here, aluminum (Al) loses 3 electrons and transforms into \[\text{Al}^{3+}\]. This loss of electrons characterizes oxidation.
Remember, oxidation doesn’t always involve oxygen! It's all about the electrons being lost. Key points about oxidation:
- Losing electrons
- Increases oxidation state
- Common in metals like aluminum in the example above
Reduction
- The oxidation state decreases
- Electrons are gained
- Often seen in non-metals and ions
Remember this simple rule: Gain of electrons = Reduction. Focusing on the electron gain helps clearly see reduction moments in reactions.
Half-Reactions
Take the reaction \[\text{2 \text{\text{Br}^{-}}(a q) \rightarrow \text{\text{\text{Br}_{2}}(l)} + 2 e^{-}} \]. The half-reactions are:
- Oxidation: \[\text{2 \text{\text{Br}}^{-} \rightarrow \text{\text{Br}}_{2} + 2 e^{-}}\]
- Reduction is the corresponding process that would gain these electrons, not shown here