Chapter 3: Problem 66
Complete each of the statements a through d using 1,2, or \(3:\) 1\. decreases 2\. increases 3\. remains the same Going from left to right across Period 4 , a. the ionization energy b. the atomic size c. the metallic character d. the number of valence electrons
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ionization Energy
Remember, ionization energy is crucial in determining how easily an element forms ions. High ionization energies usually mean that the element is less likely to lose an electron and form a positive ion (cation).
Atomic Size
Even though more electrons are added to the outer shells, the increasing positive charge in the nucleus pulls these electrons closer. This results in a smaller atomic radius. Therefore, elements on the right side of Period 4 are smaller in size compared to those on the left.
Understanding this trend is important, as atomic size influences many properties of the element, such as bonding and reactivity.
Metallic Character
On the right side of the period, elements are more likely to gain electrons and form negative ions (anions), making them less metallic. Metals are usually shiny, good conductors of electricity and heat, and malleable. Nonmetals, on the other hand, are not as shiny, poorer conductors, and brittle.
So, understanding where an element lies in Period 4 can give you a good indication of its metallic properties.
Valence Electrons
For example, potassium (K) has one valence electron, while krypton (Kr), at the end of the period, has eight valence electrons. Understanding this trend is important because the number of valence electrons determines an element's reactivity and the types of bonds it can form.
Elements with similar numbers of valence electrons often have similar chemical properties. Knowing the number of valence electrons can help predict how an element will interact with other elements.