Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The highest recorded body temperature that a person has survived is \(46.5^{\circ} \mathrm{C}\). Calculate that temperature in degrees Fahrenheit and in kelvins.

Short Answer

Expert verified
46.5°C is equal to 115.7°F and 319.65 K.

Step by step solution

01

- Convert Celsius to Fahrenheit

Use the formula to convert Celsius to Fahrenheit: \[ F = \frac{9}{5}C + 32 \] Plug in \( 46.5 \) degrees Celsius: \[ F = \frac{9}{5}(46.5) + 32 \] Simplify the expression: \[ F = 83.7 + 32 = 115.7 \] So, \( 46.5^{\bullet}\text{C} \) is equal to \( 115.7^{\bullet}\text{F} \).
02

- Convert Celsius to Kelvin

Use the formula to convert Celsius to Kelvin: \[ K = C + 273.15 \] Plug in \( 46.5 \) degrees Celsius: \[ K = 46.5 + 273.15 \] Simplify the expression: \[ K = 319.65 \] So, \( 46.5^{\bullet}\text{C} \) is equal to \( 319.65 \text{K} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Celsius to Fahrenheit
When converting temperatures from Celsius to Fahrenheit, we use a formula based on the relationship between these two scales. The formula is: \[ F = \frac{9}{5}C + 32 \] Here, \( F \) represents degrees Fahrenheit and \( C \) represents degrees Celsius. This equation indicates that you multiply the Celsius temperature by \( \frac{9}{5} \), and then add 32 to the result. Let's break it down: - Start by multiplying the Celsius value (\( 46.5 \)) by 9. - Next, divide that product by 5, resulting in \( 83.7 \). - Finally, add 32 to \( 83.7 \), giving you \( 115.7 \) degrees Fahrenheit. Understanding this formula can be quite useful in contexts where temperatures need to be quickly converted, such as weather predictions or medical scenarios.
Celsius to Kelvin
To convert Celsius to Kelvin, we use a simpler formula due to the direct relationship between these two scales. The formula is: \[ K = C + 273.15 \] In this case, \( K \) stands for Kelvin and \( C \) stands for Celsius. This formula is straightforward because the Kelvin scale is an absolute temperature scale starting at absolute zero (-273.15 degrees Celsius), so: - To convert \( 46.5 \) degrees Celsius to Kelvin, you simply add \( 273.15 \) to the Celsius value. - Adding these, \( 46.5 + 273.15 = 319.65 \), giving our result as \( 319.65 \) Kelvin. The Kelvin scale is extensively used in scientific experiments and studies, particularly in the fields of physics and chemistry.
thermodynamics
Thermodynamics is the branch of physics that deals with the relationships between heat and other forms of energy. It describes how thermal energy is converted to and from other forms of energy and how it affects matter. Thermodynamics involves several key concepts that are crucial in understanding temperature conversions: - **First Law of Thermodynamics**: This defines the principle of conservation of energy, stating that energy cannot be created or destroyed, but it can change forms. - **Second Law of Thermodynamics**: This law introduces the concept of entropy, stating that in any energy exchange, if no energy enters or leaves the system, the potential energy of the state will always be less than that of the initial state. Thermodynamics is essential in many scientific and engineering fields, helping us understand everything from engines to biological systems. Conversion of temperature scales like Celsius to Kelvin directly ties into thermodynamics as it helps scientists measure and manage thermal energy more accurately.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free