Chapter 2: Problem 26
a. Hot compresses for a patient are prepared with water heated to \(145^{\circ} \mathrm{F}\). What is the temperature of the hot water in degrees Celsius? b. During extreme hypothermia, a boy's temperature dropped to \(20.6{ }^{\circ} \mathrm{C}\). What was his temperature on the Fahrenheit scale?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Fahrenheit to Celsius
Here's an example: to convert \(145^{\circ}F\) to Celsius, you plug in the value of Fahrenheit into the equation. So, \(145^{\circ}F\) becomes: \(C = \frac{5}{9} (145 - 32)\). This simplifies to: \(C = \frac{5}{9} (113) \).
When you perform the multiplication and division, you get \(C \approx 62.8^{\circ}C\).
Therefore, 145 degrees Fahrenheit is approximately 62.8 degrees Celsius. It's simple, just follow the steps and use the formula correctly.
Celsius to Fahrenheit
For instance, to convert \(20.6^{\circ}C\) to Fahrenheit, you plug the Celsius value into the equation. So, \(20.6^{\circ}C\) becomes: \(F = \frac{9}{5}(20.6) + 32 \).
This simplifies to \(F = 37 + 32 = 68.8^{\circ}F\). Hence, 20.6 degrees Celsius is 68.8 degrees Fahrenheit.
By following the same process, you can easily convert any temperature from Celsius to Fahrenheit.
Temperature Equations
For Fahrenheit to Celsius, remember: \(C = \frac{5}{9} (F - 32)\). Always subtract 32 from the Fahrenheit value and then multiply by \(\frac{5}{9}\).
For Celsius to Fahrenheit, the equation is: \(F = \frac{9}{5}C + 32\). Multiply the Celsius value by \(\frac{9}{5}\), then add 32 to the result.
These formulas are based on the linear relationship between the two temperature scales and offer a consistent method to switch between them.
Practice these equations by converting different temperatures to reinforce your understanding.