Chapter 12: Problem 26
Which compound in each of the following pairs would be more soluble in water? Explain. b. propanone or 3 -hexanone c. butane or butanal
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Hydrogen Bonding
When a compound can form hydrogen bonds with water, it tends to be more soluble. This is because the attraction between water molecules and the solute molecules helps to stabilize the solute in the water.
For example, in the exercise, propanone can form hydrogen bonds because of its carbonyl group. The oxygen in the carbonyl group can interact with the hydrogen atoms from water molecules, aiding in the dissolution process.
Polar Groups
An example of a polar group is the carbonyl group (C=O). This group has a significant difference in electronegativity between the carbon and oxygen atoms. The oxygen atom is more electronegative and pulls electron density towards itself, creating a partial negative charge on the oxygen and a partial positive charge on the carbon.
In the case of the exercise, propanone, which has a shorter carbon chain compared to 3-hexanone, interacts better with water due to its polar carbonyl group. Similarly, butanal, with its carbonyl group, is more soluble in water than the non-polar butane.
Carbonyl Group
In the given exercise, the carbonyl group in propanone helps it to be more water-soluble than 3-hexanone. The shorter chain in propanone makes it easier for the polar carbonyl group to interact with water molecules.
Likewise, butanal, which contains a carbonyl group, is more soluble in water than butane. The presence of the carbonyl group in butanal allows it to form hydrogen bonds with water, increasing its water solubility significantly.