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For each of the following, give an answer with the correct number of decimal places: a. \(45.48 \mathrm{~cm}+8.057 \mathrm{~cm}\) b. \(23.45 \mathrm{~g}+104.1 \mathrm{~g}+0.025 \mathrm{~g}\) c. \(145.675 \mathrm{~mL}-24.2 \mathrm{~mL}\) d. \(1.08 \mathrm{~L}-0.585 \mathrm{~L}\)

Short Answer

Expert verified
a. 53.54 cm, b. 127.6 g, c. 121.5 mL, d. 0.495 L

Step by step solution

01

Identify the number of decimal places in the addends (a)

For the operands in part (a), identify the decimal places: 45.48 has two decimal places, and 8.057 has three decimal places. The result should match the smallest number of decimal places, which is two.
02

Add the numbers in (a)

Add 45.48 and 8.057: \[ 45.48 + 8.057 = 53.537 \] Since the result should have two decimal places, round 53.537 to 53.54.
03

Identify the number of decimal places in the addends (b)

For part (b), the operands have different decimal places: 23.45 has two decimal places, 104.1 has one decimal place, and 0.025 has three decimal places. The result should match the smallest number of decimal places, which is one.
04

Add the numbers in (b)

Add 23.45, 104.1, and 0.025: \[ 23.45 + 104.1 + 0.025 = 127.575 \] Since the result should have one decimal place, round 127.575 to 127.6.
05

Identify the number of decimal places in the subtractends (c)

For part (c), identify the decimal places: 145.675 has three decimal places, and 24.2 has one decimal place. The result should match the smallest number of decimal places, which is one.
06

Subtract the numbers in (c)

Subtract 24.2 from 145.675: \[ 145.675 - 24.2 = 121.475 \] Since the result should have one decimal place, round 121.475 to 121.5.
07

Identify the number of decimal places in the subtractends (d)

For part (d), identify the decimal places: 1.08 has two decimal places, and 0.585 has three decimal places. The result should match the smallest number of decimal places, which is two.
08

Subtract the numbers in (d)

Subtract 0.585 from 1.08: \[ 1.08 - 0.585 = 0.495 \] Since the result should have two decimal places, no rounding is needed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Decimal Places in Addition and Subtraction
When performing addition or subtraction in mathematics, it's crucial to consider the number of decimal places in each operand.
Let's break it down:
  • Identify the decimal places in each number being added or subtracted.
  • The result should match the operand with the smallest number of decimal places.
For instance, when adding 45.48 (two decimal places) and 8.057 (three decimal places), the result must have two decimal places, so we round 53.537 to 53.54.
This ensures precision and consistency in measurements and results.
Rounding Rules
Rounding is essential to obtain a result that reflects the precision of the measurements.
Here are simple rules to follow when rounding:
  • Identify which decimal place you need to round to.
  • If the digit immediately to the right is 5 or higher, round up.
  • If the digit immediately to the right is less than 5, round down.
For example, when adding 23.45, 104.1, and 0.025, the initial sum is 127.575. Since the least number of decimal places is one (from 104.1), 127.575 rounds to 127.6.
Precision in Mathematics
Precision refers to the detail in the measurement, i.e., how close the measurements are to each other.
Higher precision means more decimal places or significant figures. In calculations, match the precision of the final result with the least precise measurement.
For example, subtracting 24.2 from 145.675 yields 121.475. Since 24.2 has one decimal place, the result is rounded to 121.5.
This maintains the integrity of the measurement accuracy.
Measurement Accuracy
Accuracy in measurement is how close a measured value is to the actual (true) value.
It's crucial to maintain accuracy by appropriately managing significant figures and decimal places in calculations.
  • Always match the number of decimal places to the least accurate measurement when adding or subtracting.
  • This practice minimizes errors and ensures results are consistent with the original data's accuracy.
For instance, in the case of subtracting 0.585 from 1.08, the actual calculation gives 0.495, which already adheres to the two decimal places needed. This level of detail preserves the calculation's accuracy.

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Most popular questions from this chapter

In the manufacturing of computer chips, cylinders of silicon are cut into thin wafers that are \(3.00\) inches in diameter and have a mass of \(1.50 \mathrm{~g}\) of silicon. How thick \((\mathrm{mm})\) is each wafer if silicon has a density of \(2.33 \mathrm{~g} / \mathrm{cm}^{3} ?\) (The volume of a cylinder is \(\left.V=\pi r^{2} h .\right)\)

In which of the following pairs do both numbers contain the same number of significant figures? a. \(3.44 \times 10^{-3} \mathrm{~g}\) and \(0.0344 \mathrm{~g}\) b. \(0.0098 \mathrm{~s}\) and \(9.8 \times 10^{4} \mathrm{~s}\) c. \(6.8 \times 10^{3} \mathrm{~mm}\) and \(68000 \mathrm{~m}\) d. \(258.000 \mathrm{ng}\) and \(2.58 \times 10^{-2} \mathrm{~g}\)

What is the density (g/mL) of each of the following samples? a. A 20.0-mL sample of a salt solution that has a mass of \(24.0 \mathrm{~g}\). b. A solid object with a mass of \(1.65 \mathrm{lb}\) and a volume of \(170 \mathrm{~mL} .\) c. A gem has a mass of \(45.0 \mathrm{~g}\). When the gem is placed in a graduated cylinder containing \(20.0 \mathrm{~mL}\) of water, the water level rises to \(34.5 \mathrm{~mL}\). d. A lightweight head on the driver of a golf club is made of titanium. If the volume of a sample of titanium is \(114 \mathrm{~cm}^{3}\) and the mass is \(514.1 \mathrm{~g}\), what is the density of titanium?

Identify the measured number(s), if any, in each of the following pairs of numbers: a. 3 hamburgers and 6 oz of hamburger b. 1 table and 4 chairs c. \(0.75 \mathrm{lb}\) of grapes and \(350 \mathrm{~g}\) of butter d. \(60 \mathrm{~s}=1 \mathrm{~min}\)

Why can two conversion factors be written for the equality \(1 \mathrm{~m}=100 \mathrm{~cm} ?\)

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