Chapter 1: Problem 107
A graduated cylinder contains three liquids \(\mathrm{A}, \mathrm{B}\), and \(\mathrm{C}\), which have different densities and do not mix: mercury \((\mathrm{D}=13.6 \mathrm{~g} / \mathrm{mL})\), vegetable oil \((\mathrm{D}=0.92 \mathrm{~g} / \mathrm{mL})\), and water \((\mathrm{D}=1.00 \mathrm{~g} / \mathrm{mL}) .\) Identify the liquids \(\mathrm{A}, \mathrm{B}\), and \(\mathrm{C}\) in the cylinder.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
liquid density
The formula to calculate density is: \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \].
In the context of the given exercise, the ability of a liquid to float or sink in another liquid is determined by its density.
A liquid with a higher density will sink in a liquid with a lower density.
This is why in our example, mercury (with a density of 13.6 g/mL) sinks to the bottom of the graduated cylinder,
while vegetable oil (with a density of 0.92 g/mL) stays on top.
graduated cylinder
It is usually made of glass or plastic and has volume markings along its length.
The design of the graduated cylinder allows for precise measurements, which are essential in experiments where accuracy is critical.
When observing the layering of liquids in a graduated cylinder, one must note the volume each liquid occupies without mixing.
This makes it easier to determine which liquid corresponds to a specific volume marking based on their densities.
layering of liquids
The key principle here is that liquids with higher densities sink below those with lower densities.
In our exercise, the order from bottom to top is mercury, water, and vegetable oil, reflecting their respective densities.
- Mercury, at 13.6 g/mL, will be the bottommost layer.
- Water, at 1.00 g/mL, will sit in the middle.
- Vegetable oil, at 0.92 g/mL, will form the topmost layer.