Chapter 1: Problem 106
An 18 -karat gold necklace is \(75 \%\) gold by mass, \(16 \%\) silver, and \(9.0 \%\) copper. a. What is the mass, in grams, of the necklace if it contains \(0.24\) oz of silver? b. How many grams of copper are in the necklace? c. If 18 -karat gold has a density of \(15.5 \mathrm{~g} / \mathrm{cm}^{3}\), what is the volume in cubic centimeters?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
mass conversion
To convert between ounces and grams, use the conversion factor where 1 ounce equals 28.3495 grams. For example, if you have 0.24 oz of silver, you multiply by 28.3495 to get:
\(\text{0.24 oz} \times 28.3495 \text{ g/oz} = 6.80388 \text{ grams}\).
Understanding mass conversion helps ensure that measurements are consistent and accurate across different systems of measurement.
percentage by mass
For instance, if a necklace is 16% silver by mass, this means that silver makes up 16% of the total mass of the necklace.
In problems where percentages are given, you can use these to find unknown quantities. For example:
If the mass of silver is 6.80388 grams and it represents 16% of the total mass, you can find the total mass by the equation:
\(\text{Total Mass} = \frac{6.80388 \text{ g}}{0.16} ≈ 42.52 \text{ g}\).
Mastering percentage by mass calculations ensures you can accurately determine the composition of any mixture.
density calculations
\(\text{Density} = \frac{\text{Mass}}{\text{Volume}}\).
To find the volume based on mass and density, you rearrange the formula to:
\(\text{Volume} = \frac{\text{Mass}}{\text{Density}}\).
In our case of an 18-karat gold necklace, where the total mass is 42.52 grams and the density is 15.5 g/cm³:
\(\text{Volume} = \frac{42.52 \text{ g}}{15.5 \text{ g/cm}^3} = 2.74382 \text{ cm}^3\). This means the volume of the necklace is approximately 2.744 cm³.
Understanding density calculations allows you to determine the volume or mass based on the other two quantities, which is useful in many real-world applications.
unit conversions
For example, converting ounces to grams uses the factor 1 oz = 28.3495 g. In our problem, converting 0.24 oz of silver to grams involves:
\(\text{0.24 oz} \times 28.3495 \text{ g/oz} = 6.80388 \text{ g}\).
Converting volume to mass using density involves:
\(\text{Mass} = \text{Density} \times \text{Volume}\).
Practicing unit conversions develops the accuracy needed for precise measurements in scientific problems, ensuring correct and meaningful results.