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A person accidentally swallows a drop of liquid oxygen, O2(l) which has a density of 1.149g/mL. Assuming the drop has a volume of 0.050mL, what volume of gas will be produced in the person's stomach at body temperature (37C) and a pressure of 1.0atm?

Short Answer

Expert verified
After converting the temperature to Kelvin (310.15 K) and calculating the moles of oxygen (0.00179625 mol), we can use the Ideal Gas Law equation to find the volume of gas produced in the person's stomach: V=nRTP. Substituting the values, we get: V=(0.00179625mol)(0.0821L·atm/mol·K)(310.15K)(1.0atm)0.04571L.

Step by step solution

01

To convert the temperature from Celsius to Kelvin, we add 273.15 to the given temperature in Celsius: T(K) = T(°C) + 273.15 T(K) = 37°C + 273.15 T(K) = 310.15 K #Step 2: Calculate the mass of liquid oxygen#

We are given the density (ρ) of liquid oxygen and the volume (V) of the swallowed drop. We can use the formula for density to determine the mass (m) of liquid oxygen: ρ=mV Rearranging the formula to find the mass, we get: m=ρV Substituting the values given, we get: m = (1.149 g/mL) * (0.050 mL) m = 0.05745 g #Step 3: Calculate the moles of oxygen#
02

To find the moles (n) of oxygen, we will use the formula: n = m / M where M is the molar mass of O2 (32 g/mol). Substituting the values, we get: n = 0.05745 g / 32 g/mol n = 0.00179625 mol #Step 4: Use Ideal Gas Law Equation to find volume of gas produced#

We are given the pressure (P = 1.0 atm) and know the temperature already in Kelvin. The Ideal Gas Law equation is: PV = nRT Rearranging the equation to solve for V, we get: V = nRT/P Substituting the values, we get: V = (0.00179625 mol) * (0.0821 L·atm/mol·K) * (310.15 K) / (1.0 atm) V = 0.04571 L Therefore, the volume of gas produced in the person's stomach is approximately 0.04571 L.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Liquid Oxygen
Liquid oxygen is simply oxygen that has been cooled to a liquid state. This occurs at extremely low temperatures, well below its boiling point of -183°C. At these temperatures, oxygen becomes a pale blue liquid and is useful for various industrial and medical applications.
It is important to note that when in liquid form, oxygen is denser than in its gaseous state. For example, the density of liquid oxygen is 1.149 g/mL. This means that a small volume of liquid oxygen can produce a large volume of gas when converted back.
  • Liquid oxygen is cryogenic, meaning it requires extremely low temperatures to remain in liquid form.
  • It is highly reactive due to its ability to support combustion.
  • Because of its high density, small volumes can unleash large amounts of gas when warmed.
Molar Mass
Molar mass is an important concept in chemistry that refers to the mass of one mole of a given substance. For molecules, such as oxygen ext { f{O}}_2, the molar mass is calculated by adding the atomic masses of the atoms that form the molecule. In this case, the molar mass of ext { f{O}}_2 is 32 g/mol, since each oxygen atom has an atomic mass of about 16 g/mol.
Understanding molar mass is crucial for converting mass into moles, a fundamental process in chemical calculations. For instance, to find the moles of oxygen swallowed, you would divide the mass of liquid oxygen by its molar mass.
  • Molar mass allows for conversions between grams and moles.
  • For oxygen gas, ext { f{O}}_2, the molar mass is 32 g/mol.
  • Molar mass is integral to the Ideal Gas Law for volume calculations.
Density Formula
The density formula is a simple yet powerful tool in science. It is defined as the mass of a substance per unit of volume and can be expressed as ext { f{Density}} ( ho) = rac{ ext{mass}}{ ext{volume}}. This formula is useful for calculating the mass of a material when its volume and density are known or vice versa. The exercise uses this formula to determine how much liquid oxygen was swallowed in terms of its mass. The density is set, and by knowing the volume, you find mass simply by multiplying the two.
  • Density is utilized to relate mass and volume.
  • It helps identify substances and their property characteristics.
  • In this case, density allows calculation of the mass of liquid oxygen swallowed.
Temperature Conversion
When working with temperatures in physical sciences, conversions between Celsius and Kelvin are often required. The Kelvin scale is preferred in calculations involving gas laws because it starts at absolute zero, the theoretically lowest temperature possible. To convert from Celsius to Kelvin, the formula used is ext { f{T(K)}} = ext { f{T(}^ ext { f{o}} ext{C)}} + 273.15. This was used in the exercise to convert body temperature from 37°C to 310.15 K for use in the Ideal Gas Law equation. The conversion is crucial as gas laws require temperatures in absolute terms to accurately predict behavior.
  • Kelvin is the SI unit for temperature and needed for gas law equations.
  • Conversion ensures calculations align with scientific standards.
  • A simple addition of 273.15 is all that's needed between Celsius and Kelvin.

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Most popular questions from this chapter

Cyclopropane, a gas that when mixed with oxygen is used as a general anesthetic, is composed of 85.7% C and 14.3% H by mass. If the density of cyclopropane is 1.88g/L at STP, what is the molecular formula of cyclopropane?

The total volume of hydrogen gas needed to fill the Hindenburg was 2.0×108L at 1.0 atm and 25C. Given that ΔHf for H2O(l) is 286kJ/mol, how much heat was evolved when the Hindenburg exploded, assuming all of the hydrogen reacted to form water?

Atmospheric scientists often use mixing ratios to express the concentrations of trace compounds in air. Mixing ratios are often expressed as ppmv (parts per million volume):  ppmv of X= vol of X at STP total vol of air at STP×106 On a certain November day, the concentration of carbon monoxide in the air in downtown Denver, Colorado, reached 3.0×102 ppmv. The atmospheric pressure at that time was 628 torr and the temperature was 0C a. What was the partial pressure of CO? b. What was the concentration of CO in molecules per cubic meter? c. What was the concentration of CO in molecules per cubic centimeter?

Which of the following statements is(are) true? a. If the number of moles of a gas is doubled, the volume will double, assuming the pressure and temperature of the gas remain constant. b. If the temperature of a gas increases from 25C to 50C the volume of the gas would double, assuming that the pressure and the number of moles of gas remain constant. c. The device that measures atmospheric pressure is called a barometer. d. If the volume of a gas decreases by one half, then the pressure would double, assuming that the number of moles and the temperature of the gas remain constant.

Sulfur trioxide, SO3, is produced in enormous quantities each year for use in the synthesis of sulfuric acid. S(s)+O2(g)SO2(g)\2SO2(g)+O2(g)2SO3(g) What volume of O2(g) at 350.C and a pressure of 5.25 atm is needed to completely convert 5.00g sulfur to sulfur trioxide?

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