In the "Méthode Champenoise," grape juice is fermented in a wine bottle to
produce sparkling wine. The reaction is $$\mathrm{C}_{6} \mathrm{H}_{12}
\mathrm{O}_{6}(a q) \longrightarrow 2 \mathrm{C}_{2} \mathrm{H}_{5}
\mathrm{OH}(a q)+2 \mathrm{CO}_{2}(g)$$ Fermentation of \(750 .\) mL grape juice
(density \(=1.0 \mathrm{g} / \mathrm{cm}^{3}\) ) is allowed to take place in a
bottle with a total volume of \(825 \mathrm{mL}\) until \(12 \%\) by volume is
ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right) .\) Assuming
that the \(\mathrm{CO}_{2}\) is insoluble in \(\mathrm{H}_{2} \mathrm{O}\)
(actually, a wrong assumption), what would be the pressure of
\(\mathrm{CO}_{2}\) inside the wine bottle at \(25^{\circ} \mathrm{C} ?\) (The
density of ethanol is \(0.79 \mathrm{g} / \mathrm{cm}^{3} .\) )