Chapter 8: Problem 16
At the same conditions of pressure and temperature, ammonia gas is less dense than air. Why is this true?
Chapter 8: Problem 16
At the same conditions of pressure and temperature, ammonia gas is less dense than air. Why is this true?
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Get started for freeThe total volume of hydrogen gas needed to fill the Hindenburg was \(2.0 \times 10^{8} \mathrm{L}\) at 1.0 atm and \(25^{\circ} \mathrm{C}\). Given that \(\Delta H_{\mathrm{f}}^{\circ}\) for \(\mathrm{H}_{2} \mathrm{O}(l)\) is \(-286 \mathrm{kJ} / \mathrm{mol},\) how much heat was evolved when the Hindenburg exploded, assuming all of the hydrogen reacted to form water?
A compound has the empirical formula \(\mathrm{CHCI}\) A \(256-\mathrm{mL}\) flask, at \(373 \mathrm{K}\) and \(750 .\) torr, contains \(0.800 \mathrm{g}\) of the gaseous compound. Give the molecular formula.
A large flask with a volume of \(936 \mathrm{mL}\) is evacuated and found to have a mass of \(134.66 \mathrm{g}\). It is then filled to a pressure of 0.967 atm at \(31^{\circ} \mathrm{C}\) with a gas of unknown molar mass and then reweighed to give a new mass of 135.87 g. What is the molar mass of this gas?
A \(2.747-\mathrm{g}\) sample of manganese metal is reacted with excess \(HCl\) gas to produce \(3.22 \mathrm{L} \mathrm{H}_{2}(g)\) at \(373 \mathrm{K}\) and 0.951 atm and a manganese chloride compound (MnCl_). What is the formula of the manganese chloride compound produced in the reaction?
A steel cylinder contains \(5.00\) moles of graphite (pure carbon) and \(5.00\) moles of \(\mathrm{O}_{2}\). The mixture is ignited and all the graphite reacts. Combustion produces a mixture of \(\mathrm{CO}\) gas and \(\mathrm{CO}_{2}\) gas. After the cylinder has cooled to its original temperature, it is found that the pressure of the cylinder has increased by \(17.0 \% .\) Calculate the mole fractions of \(\mathrm{CO}, \mathrm{CO}_{2},\) and \(\mathrm{O}_{2}\) in the final gaseous mixture.
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