One of the chemical controversies of the nineteenth century concerned the
element beryllium (Be). Berzelius originally claimed that beryllium was a
trivalent element (forming \(\mathrm{Be}^{3+}\) ions) and that it gave an oxide
with the formula \(\mathrm{Be}_{2} \mathrm{O}_{3}\). This resulted in a
calculated atomic mass of \(13.5\) for beryllium. In formulating his periodic
table, Mendeleev proposed that beryllium was divalent (forming
\(\mathrm{Be}^{2+}\) ions) and that it gave an oxide with the formula BeO. This
assumption gives an atomic mass of \(9.0 .\) In \(1894,\) A. Combes (Comptes
Rendus 1894 p. 1221 ) reacted beryllium with the anion \(C_{5} \mathrm{H}_{7}
\mathrm{O}_{2}^{-}\) and measured the density of the gaseous product. Combes's
data for two different experiments are as follows:If beryllium is a divalent
metal, the molecular formula of the product will be
\(\mathrm{Be}\left(\mathrm{C}_{5} \mathrm{H}_{7} \mathrm{O}_{2}\right)_{2} ;\)
if it is trivalent, the formula will be \(\mathrm{Be}\left(\mathrm{C}_{5}
\mathrm{H}_{7} \mathrm{O}_{2}\right)_{3} .\) Show how Combes's data help to
confirm that beryllium is a divalent metal.