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If you have any two gases in different containers that are the same size at the same pressure and same temperature, what is true about the moles of each gas? Why is this true?

Short Answer

Expert verified
Under the given conditions where both gases have the same pressure, temperature, and equal volume containers, the moles of both gases are equal (i.e., they have the same number of moles), according to the Ideal Gas Law. This is true due to the direct proportionality of pressure, volume, and temperature to the moles of an ideal gas.

Step by step solution

01

Ideal Gas Law Equation

The Ideal Gas Law is a mathematical equation relating the volume, temperature, pressure, and amount of substance (in moles) for an ideal gas. The Ideal Gas Law equation is as follows: \(PV = nRT\) Where: - P is the pressure of the gas, - V is the volume of the gas, - n is the number of moles of the gas, - R is the gas constant (8.314 J/(mol K)), - T is the temperature of the gas in Kelvin.
02

Apply the given conditions

In this exercise, we know that both gases are at the same pressure, same temperature, and in containers of the same size (equal volume). Let's denote the conditions on gas 1 as \(P_1\), \(V_1\), \(n_1\), \(T_1\) and the conditions on gas 2 as \(P_2\), \(V_2\), \(n_2\), \(T_2\). Given that \(P_1 = P_2\), \(V_1 = V_2\), and \(T_1 = T_2\), let's apply the Ideal Gas Law to both gases: Gas 1: \(P_1V_1 = n_1RT_1\) Gas 2: \(P_2V_2 = n_2RT_2\)
03

Comparing the moles of both gases

Since the pressure, volume, and temperature of both gases are equal, we can now compare the moles of both gases. Divide the equation for gas 1 by the equation for gas 2: \(\frac{P_1V_1}{P_2V_2} = \frac{n_1RT_1}{n_2RT_2}\) Since \(P_1 = P_2\), \(V_1 = V_2\), and \(T_1 = T_2\), this simplifies to: \(\frac{n_1}{n_2} = 1\) Which means: \(n_1 = n_2\)
04

Conclusion

Under the given conditions where both gases have the same pressure, temperature, and equal volume containers, the moles of both gases are equal (i.e., they have the same number of moles), according to the Ideal Gas Law. This is true due to the direct proportionality of pressure, volume, and temperature to the moles of an ideal gas.

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Most popular questions from this chapter

A steel cylinder contains \(150.0\) moles of argon gas at a temperature of \(25^{\circ} \mathrm{C}\) and a pressure of \(8.93 \mathrm{MPa}\). After some argon has been used, the pressure is \(2.00 \mathrm{MPa}\) at a temperature of \(19^{\circ} \mathrm{C}\). What mass of argon remains in the cylinder?

Calculate \(w\) and \(\Delta E\) when \(1\) mole of a liquid is vaporized at its boiling point \(\left(80 .^{\circ} \mathrm{C}\right)\) and \(1.00\) atm pressure. \(\Delta H\) for the vaporization of the liquid is \(30.7 \mathrm{kJ} / \mathrm{mol}\) at \(80 .^{\circ} \mathrm{C}\). Assume the volume of \(1\) mole of liquid is negligible as compared to the volume of \(1\) mole of gas at \(80 .^{\circ} \mathrm{C}\) and \(1.00\) atm.

Ethene is converted to ethane by the reaction $$\mathrm{C}_{2} \mathrm{H}_{4}(g)+\mathrm{H}_{2}(g) \stackrel{catalyst}{\longrightarrow} \mathrm{C}_{2} \mathrm{H}_{6}(g)$$ \(\mathrm{C}_{2} \mathrm{H}_{4}\) flows into a catalytic reactor at \(25.0\) atm and \(300 .^{\circ} \mathrm{C}\) with a flow rate of \(1000 .\) Umin. Hydrogen at \(25.0\) atm and \(300 .^{\circ} \mathrm{C}\) flows into the reactor at a flow rate of \(1500 .\) L/min. If \(15.0 \mathrm{kg}\) \(\mathrm{C}_{2} \mathrm{H}_{6}\) is collected per minute, what is the percent yield of the reaction?

Which of the following statements is(are) true? a. If the number of moles of a gas is doubled, the volume will double, assuming the pressure and temperature of the gas remain constant. b. If the temperature of a gas increases from \(25^{\circ} \mathrm{C}\) to \(50^{\circ} \mathrm{C}\) the volume of the gas would double, assuming that the pressure and the number of moles of gas remain constant. c. The device that measures atmospheric pressure is called a barometer. d. If the volume of a gas decreases by one half, then the pressure would double, assuming that the number of moles and the temperature of the gas remain constant.

An ideal gas is contained in a cylinder with a volume of \(5.0 \times 10^{2} \mathrm{mL}\) at a temperature of \(30 .^{\circ} \mathrm{C}\) and a pressure of \(710.\) torr. The gas is then compressed to a volume of \(25 \mathrm{mL}\) and the temperature is raised to \(820 .^{\circ} \mathrm{C}\). What is the new pressure of the gas?

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