Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

What mass of NaOH is contained in \(250.0 \mathrm{mL}\) of a \(0.400 \mathrm{M}\) sodium hydroxide solution?

Short Answer

Expert verified
There are \(4.00\, \text{g}\) of NaOH contained in \(250.0\, \text{mL}\) of the \(0.400\, \text{M}\) sodium hydroxide solution.

Step by step solution

01

Identify the given values

We are given: - Volume of the solution: 250.0 mL - Molarity of the sodium hydroxide (NaOH) solution: 0.400 M
02

Convert the volume to liters

Before using the molarity formula, we need to convert the volume of the solution to liters. 1 L = 1000 mL, so we can use this conversion factor: Volume (L) = \(\frac{250.0\,\text{mL}}{1000\,\text{mL/L}} = 0.250\,\text{L}\)
03

Calculate the moles of NaOH

To find the moles of NaOH present in the solution, we need to use the molarity formula: Moles = Molarity x Volume Moles of NaOH = \(0.400\,\text{M}\) x \(0.250\,\text{L}\) = \(0.100\,\text{mol}\)
04

Calculate the molar mass of NaOH

We need to find the molar mass of NaOH to convert the moles to mass. To get the molar mass, find the atomic masses of the elements in NaOH using the periodic table: - Sodium (Na): 22.99 g/mol - Oxygen (O): 16.00 g/mol - Hydrogen (H): 1.008 g/mol Molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.008 g/mol = 40.00 g/mol
05

Convert moles to mass

Now we can convert moles of NaOH to mass using the molar mass calculated in step 4: Mass of NaOH = Moles x Molar mass Mass of NaOH = \(0.100\,\text{mol}\) x \(40.00\,\text{g/mol}\) = \(4.00\,\text{g}\) So, there are 4.00 g of NaOH contained in 250.0 mL of the 0.400 M sodium hydroxide solution.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mole Concept
Understanding the mole concept is fundamental to mastering chemistry, especially when dealing with chemical reactions and the quantification of substances. A mole is a unit of measurement that represents an immense quantity of particles, atoms, or molecules—specifically, Avogadro's number, which is approximately 6.022 x 10^23 entities.

When we calculate the number of moles, as shown in the exercise with sodium hydroxide (NaOH), we are essentially counting how many units of that substance we have. To grasp this, it may help to compare it to something more familiar, like a dozen. Just as a dozen represents 12 of something, a mole represents 6.022 x 10^23 of something.

To convert between moles and the number of particles, you can use Avogadro's constant. For example, if you have one mole of NaOH, you have 6.022 x 10^23 molecules of NaOH. This is crucial when you want to relate the macroscopic world that we can measure, like volume and mass, to the microscopic world of atoms and molecules that are too small to see or measure directly.
Concentration of Solution
The concentration of a solution is a measure of how much solute is dissolved in a given volume of solvent. Molarity, symbolized as M, is one of the most common units of concentration in chemistry. Molarity is defined as the number of moles of solute per liter of solution.

To calculate the concentration in terms of molarity, you divide the moles of solute by the volume of the solution in liters. For example, a 0.400 M NaOH solution contains 0.400 moles of sodium hydroxide per liter of solution. This becomes particular handy when you want to calculate the quantity of solute in a specific volume of solution, as you did with the exercise.

Improving Solution Concentration Understanding

When studying solutions, it's advisable to:
  • Practice converting measurements like milliliters to liters since molarity depends on the volume in liters.
  • Always associate molarity with the ratio moles/liter to solidify understanding.
  • Use real-world examples, such as comparing concentrated fruit juice vs. diluted juice, to visualize concentration differences.
By considering these points, you can deepen your understanding of solution concentration and how it relates to everyday life.
Molar Mass
Molar mass is a term used to indicate the mass of one mole of any given substance. It is usually expressed in grams per mole (g/mol) and can be found by summing the atomic masses of all the atoms in a molecule of that substance. For instance, the molar mass of NaOH was determined by adding the atomic masses of sodium, oxygen, and hydrogen.

The molar mass is an essential link between the mass of a material you can measure on a scale and the intrinsic mole concept for counting particles chemically. Once you know the molar mass, you can convert from mass to moles or vice versa, which is a frequent requirement in chemical calculations, like the ones demonstrated in the exercise.

Relating Molar Mass to Real Applications

To solidify the understanding of molar mass, remember to:
  • Get comfortable using the periodic table to find atomic weights.
  • Regularly practice calculations converting mass to moles and moles to mass using the molar mass.
  • Think of molar mass as the 'chemical bridge' that connects the tangible world (mass) with the theoretical world (moles).
With these tips, anyone can become proficient at using molar mass to navigate between the physical measurements and the chemical quantities required in various scientific and practical applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A mixture contains only \(\mathrm{NaCl}\) and \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{3} .\) A \(0.456-\mathrm{g}\) sample of the mixture is dissolved in water, and an excess of NaOH is added, producing a precipitate of \(\mathrm{Fe}(\mathrm{OH})_{3} .\) The precipitate is filtered, dried, and weighed. Its mass is 0.107 g. Calculate the following. a. the mass of iron in the sample b. the mass of \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{3}\) in the sample c. the mass percent of \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{3}\) in the sample

In most of its ionic compounds, cobalt is either Co(II) or Co(III). One such compound, containing chloride ion and waters of hydration, was analyzed, and the following results were obtained. A \(0.256-\mathrm{g}\) sample of the compound was dissolved in water, and excess silver nitrate was added. The silver chloride was filtered, dried, and weighed, and it had a mass of 0.308 g. A second sample of 0.416 g of the compound was dissolved in water, and an excess of sodium hydroxide was added. The hydroxide salt was filtered and heated in a flame, forming cobalt(III) oxide. The mass of cobalt(III) oxide formed was 0.145 g. a. What is the percent composition, by mass, of the compound? b. Assuming the compound contains one cobalt ion per formula unit, what is the formula? c. Write balanced equations for the three reactions described.

Three students were asked to find the identity of the metal in a particular sulfate salt. They dissolved a 0.1472 -g sample of the salt in water and treated it with excess barium chloride, resulting in the precipitation of barium sulfate. After the precipitate had been filtered and dried, it weighed 0.2327 g. Each student analyzed the data independently and came to different conclusions. Pat decided that the metal was titanium. Chris thought it was sodium. Randy reported that it was gallium. What formula did each student assign to the sulfate salt? Look for information on the sulfates of gallium, sodium, and titanium in this text and reference books such as the \(C R C\) Handbook of Chemistry and Physics. What further tests would you suggest to determine which student is most likely correct?

Calculate the concentration of all ions present in each of the following solutions of strong electrolytes. a. 0.100 mole of \(\mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}\) in \(100.0 \mathrm{mL}\) of solution b. 2.5 moles of \(\mathrm{Na}_{2} \mathrm{SO}_{4}\) in 1.25 L of solution c. \(5.00 \mathrm{g}\) of \(\mathrm{NH}_{4} \mathrm{Cl}\) in \(500.0 \mathrm{mL}\) of solution d. \(1.00 \mathrm{g} \mathrm{K}_{3} \mathrm{PO}_{4}\) in \(250.0 \mathrm{mL}\) of solution

Which of the following solutions of strong electrolytes contains the largest number of moles of chloride ions: \(100.0 \mathrm{mL}\) of \(0.30 \mathrm{M} \mathrm{AlCl}_{3}, 50.0 \mathrm{mL}\) of \(0.60 \mathrm{M} \mathrm{MgCl}_{2},\) or \(200.0 \mathrm{mL}\) of \(0.40 M\) NaCl?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free