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Calcium chloride is a strong electrolyte and is used to "salt" streets in the winter to melt ice and snow. Write a reaction to show how this substance breaks apart when it dissolves in Water.

Short Answer

Expert verified
When calcium chloride (CaCl2) dissolves in water, it dissociates completely into its ions, forming a calcium ion (\(Ca^{2+}\)) and two chloride ions (\(2Cl^-\)). The balanced chemical equation for this reaction is: \(CaCl_2(s) \rightarrow Ca^{2+}(aq) + 2Cl^-(aq)\)

Step by step solution

01

Step 1. Writing the formula of Calcium chloride (CaCl2)

As given in the problem, calcium chloride has the chemical formula CaCl2.
02

Step 2. Identify the ions formed when it dissolves in water

When calcium chloride dissolves in water, it dissociates into two types of ions: 1. Calcium ion: \(Ca^{2+}\) 2. Chloride ions: \(Cl^-\) Note that calcium ion has a charge of +2, and chloride ion has a charge of -1.
03

Step 3. Write the balanced chemical equation for CaCl2 dissolving in water

Now we know the ions formed during the dissociation of calcium chloride, we can write the balanced chemical equation: \(CaCl_2(s) \rightarrow Ca^{2+}(aq) + 2Cl^-(aq)\) This equation shows that when solid calcium chloride (CaCl2) dissolves in water, it breaks apart into one calcium ion (\(Ca^{2+}\)) and two chloride ions (\(2Cl^-\)) in aqueous solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Strong Electrolytes
Understanding strong electrolytes is essential when studying substances like calcium chloride (CaCl2). A strong electrolyte is any compound that completely dissociates into its ions when dissolved in water. This means that when you add a substance like CaCl2 to water, it will separate into positively charged calcium ions (\(Ca^{2+}\)) and negatively charged chloride ions (\(Cl^-\)) without leaving any undissociated molecules behind.

Strong electrolytes tend to increase the electrical conductivity of water because they release a significant number of ions, which are charge carriers. Substances that are strong electrolytes include most salts, inorganic acids like hydrochloric acid (HCl), and bases such as sodium hydroxide (NaOH). In the context of this exercise, by knowing that calcium chloride is a strong electrolyte, we can predict that it will efficiently break apart into ions in a solution, which is why it's effective in melting ice and snow by disrupting the structure of ice through its ions.
Ionic Dissociation
Ionic dissociation is the process in which an ionic compound separates into its constituent ions when dissolved in a solvent, typically water. This concept is at the heart of understanding how calcium chloride behaves in aqueous solutions. As we look at CaCl2, which is composed of calcium ions and chloride ions held together by ionic bonds in a solid state, upon dissolving, these bonds are overcome by the interaction with water molecules.

The dissociation can be visualized as water molecules surrounding the CaCl2 unit and pulling the ions apart due to their attraction to the positive and negative charges of the water molecules (a polar solvent). This process is crucial for processes like de-icing, as the free ions in the solution work to disrupt the ice's crystalline structure. Remember, the extent of dissolution and dissociation is crucial in applications that require ions in free states, such as electrolyte solutions for batteries or physiological fluids.
Chemical Equations
) ions after dissolution, specifically one calcium ion and two chloride ions, which is reflected by the numbers in front of the chloride ions. The process described is a physical change rather than a chemical reaction since the ions are not chemically altered, only their physical state changes. Additionally, the equation shows the conservation of charge; the charge is balanced on both sides, which is an essential principle in chemistry. Being able to interpret and write chemical equations is a fundamental skill in chemistry that provides a clear and concise way of conveying the changes occurring during chemical processes.

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Most popular questions from this chapter

Write net ionic equations for the reaction, if any, that occurs when aqueous solutions of the following are mixed. a. chromium(III) chloride and sodium hydroxide b. silver nitrate and ammonium carbonate c. copper(II) sulfate and mercury(I) nitrate d. strontium nitrate and potassium iodide

A solution is prepared by dissolving \(10.8 \mathrm{g}\) ammonium sulfate in enough water to make \(100.0 \mathrm{mL}\) of stock solution. A \(10.00-\) mL sample of this stock solution is added to \(50.00 \mathrm{mL}\) of water. Calculate the concentration of ammonium ions and sulfate ions in the final solution.

What mass of \(\mathrm{Na}_{2} \mathrm{CrO}_{4}\) is required to precipitate all of the silver ions from \(75.0 \mathrm{mL}\) of a \(0.100-M\) solution of \(\mathrm{AgNO}_{3} ?\)

Write the balanced formula equation for the acid-base reactions that occur when the following are mixed. a. potassium hydroxide (aqueous) and nitric acid b. barium hydroxide (aqueous) and hydrochloric acid c. perchloric acid \(\left[\mathrm{HClO}_{4}(a q)\right]\) and solid iron(III) hydroxide d. solid silver hydroxide and hydrobromic acid e. aqueous strontium hydroxide and hydroiodic acid

The concentration of a certain sodium hydroxide solution was determined by using the solution to titrate a sample of potassium hydrogen phthalate (abbreviated as KHP). KHP is an acid with one acidic hydrogen and a molar mass of \(204.22 \mathrm{g} / \mathrm{mol}\). In the titration, \(34.67 \mathrm{mL}\) of the sodium hydroxide solution was required to react with 0.1082 g KHP. Calculate the molarity of the sodium hydroxide.

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