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What is the theoretical yield for a reaction, and how does this quantity depend on the limiting reactant?

Short Answer

Expert verified
The theoretical yield is the maximum amount of product that can be formed in a chemical reaction based on the stoichiometric ratios of the reactants in the balanced chemical equation. This ideal value assumes complete conversion of reactants to products without side reactions or losses. The theoretical yield depends on the limiting reactant, which is the reactant that gets completely consumed and restricts the amount of product formed. To calculate the theoretical yield, write the balanced chemical equation, convert given masses of reactants into moles, determine the limiting reactant, calculate the moles of product formed using stoichiometry, and finally convert the moles of product formed into the desired unit using its molar mass.

Step by step solution

01

Define Theoretical Yield

The theoretical yield is the maximum amount of product that can be formed from a given set of reactants in a chemical reaction based on the stoichiometric ratios of the balanced chemical equation. It is an ideal value that assumes complete conversion of the reactants to the products without any side reactions or losses.
02

Explain Limiting Reactant

In a chemical reaction, the reactant that gets completely consumed and limits the amount of product that can be formed is called the limiting reactant. It is determined by comparing the mole ratios of the reactants to the balanced chemical equation. Whichever reactant runs out first limits the formation of the product, thus affecting the theoretical yield of the reaction.
03

Relationship between Theoretical Yield and Limiting Reactant

The theoretical yield of a reaction depends on the limiting reactant because it is the reactant that determines the maximum amount of the product that can be formed. If there were an excess of the limiting reactant, more product could have been formed. Hence, the theoretical yield is based on the amount of limiting reactant present in the reaction.
04

Calculating Theoretical Yield

To calculate the theoretical yield, follow these steps: 1. Write the balanced chemical equation for the reaction. 2. Convert the given masses (or moles) of each reactant into moles using their molar masses. 3. Determine the limiting reactant by comparing the mole ratios of the reactants based on the balanced chemical equation. 4. Calculate the moles of product formed using the stoichiometry from the balanced chemical equation with respect to the limiting reactant. 5. Convert the moles of product formed into the desired unit (grams or other units) using its molar mass. The theoretical yield can be reported as moles or mass, depending on the requirement.

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Most popular questions from this chapter

A compound contains only carbon, hydrogen, nitrogen, and oxygen. Combustion of 0.157 g of the compound produced \(0.213 \mathrm{g} \mathrm{CO}_{2}\) and \(0.0310 \mathrm{g} \mathrm{H}_{2} \mathrm{O} .\) In another experiment, it is found that 0.103 g of the compound produces \(0.0230 \mathrm{g} \mathrm{NH}_{3}\) What is the empirical formula of the compound? Hint: Combustion involves reacting with excess \(\mathrm{O}_{2}\). Assume that all the carbon ends up in \(\mathrm{CO}_{2}\) and all the hydrogen ends up in \(\mathrm{H}_{2} \mathrm{O}\). Also assume that all the nitrogen ends up in the \(\mathrm{NH}_{3}\) in the second experiment.

The reusable booster rockets of the U.S. space shuttle employ a mixture of aluminum and ammonium perchlorate for fuel. A possible equation for this reaction is $$\begin{aligned}3 \mathrm{Al}(s)+3 \mathrm{NH}_{4} \mathrm{ClO}_{4}(s) & \longrightarrow \\ \mathrm{Al}_{2} \mathrm{O}_{3}(s)+& \mathrm{AlCl}_{3}(s)+3 \mathrm{NO}(g)+6 \mathrm{H}_{2} \mathrm{O}(g)\end{aligned}$$ What mass of \(\mathrm{NH}_{4} \mathrm{ClO}_{4}\) should be used in the fuel mixture for every kilogram of Al?

An ionic compound \(\mathrm{MX}_{3}\) is prepared according to the following unbalanced chemical equation. $$\mathbf{M}+\mathbf{X}_{2} \longrightarrow \mathbf{M X}_{3}$$ A \(0.105-\mathrm{g}\) sample of \(\mathrm{X}_{2}\) contains \(8.92 \times 10^{20}\) molecules. The compound \(\mathrm{MX}_{3}\) consists of \(54.47 \%\) X by mass. What are the identities of \(\mathrm{M}\) and \(\mathrm{X}\), and what is the correct name for \(\mathrm{MX}_{3} ?\) Starting with 1.00 g each of \(M\) and \(X_{2}\), what mass of \(M X_{3}\) can be prepared?

Give the balanced equation for each of the following chemical reactions: a. Glucose \(\left(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\right)\) reacts with oxygen gas to produce gaseous carbon dioxide and water vapor. b. Solid iron(III) sulfide reacts with gaseous hydrogen chloride to form solid iron(III) chloride and hydrogen sulfide gas. c. Carbon disulfide liquid reacts with ammonia gas to produce hydrogen sulfide gas and solid ammonium thiocyanate \(\left(\mathrm{NH}_{4} \mathrm{SCN}\right).\)

Tetrodotoxin is a toxic chemical found in fugu pufferfish, a popular but rare delicacy in Japan. This compound has an LD\(_{50}\) (the amount of substance that is lethal to \(50 . \%\) of a population sample) of \(10 . \mu g\) per \(\mathrm{kg}\) of body mass. Tetrodotoxin is \(41.38 \%\) carbon by mass, \(13.16\%\) nitrogen by mass, and \(5.37\%\) hydrogen by mass, with the remaining amount consisting of oxygen. What is the empirical formula of tetrodotoxin? If three molecules of tetrodotoxin have a mass of \(1.59 \times 10^{-21} \mathrm{g},\) what is the molecular formula of tetrodotoxin? What number of molecules of tetrodotoxin would be the \(\mathrm{LD}_{50}\) dosage for a person weighing 165 lb?

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