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The compound adrenaline contains \(56.79 \%\) C, \(6.56 \%\) H, \(28.37 \%\) O, and \(8.28 \%\) N by mass. What is the empirical formula for adrenaline?

Short Answer

Expert verified
The empirical formula for adrenaline is \(C_8H_{11}O_3N\).

Step by step solution

01

1. Convert mass percentages to moles

For each element (C, H, O, and N), we'll divide the given mass percentage by the element's molar mass to obtain the number of moles. Let us consider a 100g sample of adrenaline so that the mass percentages directly translate to mass in grams. Here are the molar masses of the elements: C = 12.01 g/mol, H = 1.01 g/mol, O = 16.00 g/mol, and N = 14.01 g/mol. For Carbon (C): Moles of C = (56.79 g) / (12.01 g/mol) = 4.732 moles For Hydrogen (H): Moles of H = (6.56 g) / (1.01 g/mol) = 6.495 moles For Oxygen (O): Moles of O = (28.37 g) / (16.00 g/mol) = 1.773 moles For Nitrogen (N): Moles of N = (8.28 g) / (14.01 g/mol) = 0.591 moles
02

2. Find the simplest whole-number ratio

To find the simplest whole-number ratio between the moles of each element, we will divide each mole value by the smallest value: For Carbon (C): 4.732 / 0.591 = 8.000 For Hydrogen (H): 6.495 / 0.591 = 10.997 ≈ 11 For Oxygen (O): 1.773 / 0.591 = 2.998 ≈ 3 For Nitrogen (N): 0.591 / 0.591 = 1 Now the simplest whole-number ratio is 8:11:3:1
03

3. Write the empirical formula

Based on the simplest whole-number ratio we found, the empirical formula for adrenaline is: \(C_8H_{11}O_3N_1\), or simply \(C_8H_{11}O_3N\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass
Understanding molar mass is the first step to determining the empirical formula of a compound like adrenaline. In essence, molar mass is the weight of one mole (6.02 x 1023 particles) of a given substance and is expressed in grams per mole (g/mol). It's like the currency exchange between atoms and grams — a way to translate between the microscopic world of atoms and the macroscopic world that we can measure.[br][br]For instance, the molar mass of carbon (C) is 12.01 g/mol. This means if you have one mole of carbon atoms, it would weigh 12.01 grams. Similarly, hydrogen (H), oxygen (O), and nitrogen (N) have molar masses of 1.01 g/mol, 16.00 g/mol, and 14.01 g/mol, respectively. Using these values, we convert the mass percentage of each element into moles, which is the starting point for finding the empirical formula.
Mass Percentage
Essentially, the mass percentage tells us how much of an element is present in a compound relative to the total mass. Think of it as a recipe; mass percentage gives you the proportions of each ingredient necessary to make the perfect dish.[br][br]For adrenaline, we were given its composition in these percentages right off the bat: 56.79% carbon, 6.56% hydrogen, 28.37% oxygen, and 8.28% nitrogen. If we consider a 100g sample, it means translating those percentages into grams is direct: 56.79g C, 6.56g H, 28.37g O, and 8.28g N. This direct conversion simplifies the process, allowing us to then compare the amount of each element present by converting these masses to moles using their respective molar masses.
Mole-to-Mole Ratio
The mole-to-mole ratio is the bridge that connects different elements within a compound. Once we have the number of moles of each element, we need to express their relationship through the simplest whole-number ratios to reach the empirical formula.[br][br]We do this by dividing the number of moles of each element by the smallest number of moles present among them, which in the case of adrenaline is nitrogen, with 0.591 moles. The results give us the relative numbers of atoms of each element that combine to form the simplest unit of the compound. These ratios are the essence of the compound's formula, reflecting the fundamental proportions in which the elements combine.
Chemical Composition
A compound's chemical composition is its identity card; it shows the specific elements and the number of each atom type that makes up the compound. The empirical formula derived from the mole ratio gives us the simplest, most reduced representation of this composition, revealing the basic building blocks of the molecular structure.[br][br]In adrenaline, for example, the mole-to-mole ratio resulted in an empirical formula of C8H11O3N. This formula indicates that in the most basic form of adrenaline, eight carbon atoms are combined with eleven hydrogen atoms, three oxygen atoms, and one nitrogen atom. This quintessential information allows chemists to understand, predict, and manipulate the compound's properties and reactions.

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Most popular questions from this chapter

Vitamin A has a molar mass of 286.4 g/mol and a general molecular formula of \(\mathrm{C}_{x} \mathrm{H}_{y} \mathrm{E},\) where \(\mathrm{E}\) is an unknown element. If vitamin \(A\) is \(83.86 \%\) C and \(10.56 \%\) H by mass, what is the molecular formula of vitamin A?

Balance each of the following chemical equations. a. \(\mathrm{KO}_{2}(s)+\mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{KOH}(a q)+\mathrm{O}_{2}(g)+\mathrm{H}_{2} \mathrm{O}_{2}(a q)\) b. \(\mathrm{Fe}_{2} \mathrm{O}_{3}(s)+\mathrm{HNO}_{3}(a q) \rightarrow \mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{3}(a q)+\mathrm{H}_{2} \mathrm{O}(l)\) c. \(\mathrm{NH}_{3}(g)+\mathrm{O}_{2}(g) \rightarrow \mathrm{NO}(g)+\mathrm{H}_{2} \mathrm{O}(g)\) d. \(\mathrm{PCl}_{5}(l)+\mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{H}_{3} \mathrm{PO}_{4}(a q)+\mathrm{HCl}(g)\) e. \(\mathrm{CaO}(s)+\mathrm{C}(s) \rightarrow \mathrm{CaC}_{2}(s)+\mathrm{CO}_{2}(g)\) f. \(\operatorname{MoS}_{2}(s)+\mathrm{O}_{2}(g) \rightarrow \operatorname{MoO}_{3}(s)+\mathrm{SO}_{2}(g)\) g. \(\mathrm{FeCO}_{3}(s)+\mathrm{H}_{2} \mathrm{CO}_{3}(a q) \rightarrow \mathrm{Fe}\left(\mathrm{HCO}_{3}\right)_{2}(a q)\)

Many cereals are made with high moisture content so that the cereal can be formed into various shapes before it is dried. A cereal product containing \(58 \% \mathrm{H}_{2} \mathrm{O}\) by mass is produced at the rate of \(1000 .\) kg/h. What mass of water must be evaporated per hour if the final product contains only \(20 . \%\) water?

Balance the following equations representing combustion reactions: c. \(C_{12} H_{22} O_{11}(s)+O_{2}(g) \rightarrow C O_{2}(g)+H_{2} O(g)\) d. \(\mathrm{Fe}(s)+\mathrm{O}_{2}(g) \rightarrow \mathrm{Fe}_{2} \mathrm{O}_{3}(s)\) e. \(\operatorname{FeO}(s)+\mathbf{O}_{2}(g) \rightarrow \operatorname{Fe}_{2} \mathbf{O}_{3}(s)\)

Aspartame is an artificial sweetener that is 160 times sweeter than sucrose (table sugar) when dissolved in water. It is marketed as NutraSweet. The molecular formula of aspartame is \(\mathrm{C}_{14} \mathrm{H}_{18} \mathrm{N}_{2} \mathrm{O}_{5}.\) a. Calculate the molar mass of aspartame. b. What amount (moles) of molecules are present in \(10.0 \mathrm{g}\) aspartame? c. Calculate the mass in grams of 1.56 mole of aspartame. d. What number of molecules are in \(5.0 \mathrm{mg}\) aspartame? e. What number of atoms of nitrogen are in \(1.2 \mathrm{g}\) aspartame? f. What is the mass in grams of \(1.0 \times 10^{9}\) molecules of aspartame? g. What is the mass in grams of one molecule of aspartame?

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