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Silicon is produced for the chemical and electronics industries by the following reactions. Give the balanced equation for each reaction. a. \(\operatorname{SiO}_{2}(s)+\mathrm{C}(s) \frac{\text { Electric }}{\text { arc furnace }} \mathrm{Si}(s)+\mathrm{CO}(g).\) b. Liquid silicon tetrachloride is reacted with very pure solid magnesium, producing solid silicon and solid magnesium chloride. c. \(\mathrm{Na}_{2} \mathrm{SiF}_{6}(s)+\mathrm{Na}(s) \rightarrow \mathrm{Si}(s)+\mathrm{NaF}(s).\)

Short Answer

Expert verified
The short version of the balanced equations are: a. \( SiO_2(s) + C(s) \rightarrow Si(s) + CO(g) \) b. \( SiCl_4(l) + 2Mg(s) \rightarrow Si(s) + 2MgCl_2(s) \) c. \( 2Na_2SiF_6(s) + 4Na(s) \rightarrow Si(s) + 12NaF(s) \)

Step by step solution

01

Balancing Reaction (a)

Reaction (a): SiO2(s) + C(s) → Si(s) + CO(g) This reaction is already balanced. Each of the reactants and products has one Si atom, two O atoms, and one C atom.
02

Balancing Reaction (b)

Reaction (b): SiCl4(l) + Mg(s) → Si(s) + MgCl2(s) We have 4 Cl atoms on the reactant side and only 2 Cl atoms on the product side. To balance the Cl atoms, we can adjust the coefficients in the chemical equation. The balanced equation is: SiCl4(l) + 2Mg(s) → Si(s) + 2MgCl2(s)
03

Balancing Reaction (c)

Reaction (c): Na2SiF6(s) + Na(s) → Si(s) + NaF(s) First, let's balance the Si atoms: Na2SiF6(s) + Na(s) → Si(s) + 2NaF(s) (we added 2NaF to balance the amount of Si) Now we need to balance Na atoms: 2Na2SiF6(s) + 4Na(s) → Si(s) + 12NaF(s) (we multiplied each reactant and product by needed coefficients to balance the Na atoms) Finally, let's verify if the F atoms are balanced: 2Na2SiF6(s) + 4Na(s) → Si(s) + 12NaF(s) (Yes, there are 12 F atoms on both sides) So, the balanced equation for reaction (c) is: 2Na2SiF6(s) + 4Na(s) → Si(s) + 12NaF(s)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Equations
Chemical equations are symbolic representations of chemical reactions, displaying the reactants consumed and the products formed during the reaction. They also convey the conservation of mass through the equal number of atoms of each element on both sides of the equation. A properly written chemical equation will reflect the changes of a chemical process, indicating the states of matter of reactants and products as solid (s), liquid (l), gas (g), or aqueous (aq).

In the given exercise example, silicon production is described through a series of reactions. For instance, the reactions detail transforming silicon dioxide to silicon as well as converting silicon tetrachloride into solid silicon and magnesium chloride. Chemical equations play a critical role in understanding these transformations at a molecular level.
Stoichiometry
Stoichiometry is the quantitative relationship between reactants and products in a chemical reaction. It's based on the principle that matter cannot be created or destroyed in a chemical reaction—only rearranged. This concept forms the basis for calculations involving the mass of reactants and products, using molar masses and coefficients from the balanced chemical equations.

For example, the stoichiometry of the reaction involving silicon dioxide and carbon suggests that one mole of silicon dioxide reacts with one mole of carbon to produce one mole of silicon and one mole of carbon monoxide. Understanding these mole-to-mole ratios is crucial in determining how much reactant is needed, or how much product can be produced, in a given reaction.
Reaction Balancing
Balancing chemical reactions is the act of equalizing the number of each type of atom on both sides of the chemical equation. This ensures the law of conservation of mass is satisfied. When balancing reactions, one typically adjusts the coefficients, which are the numbers placed before the compounds in the equation.

For the given exercise, reactions b and c required balancing. By changing the coefficients, we can ensure that the number of atoms for each element is the same on both sides. This step is mandatory; without a balanced equation, any stoichiometric calculations based on the reaction would be incorrect. Mastering the skill of balancing reactions is essential for any student studying chemistry.

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Most popular questions from this chapter

A compound contains only carbon, hydrogen, nitrogen, and oxygen. Combustion of 0.157 g of the compound produced \(0.213 \mathrm{g} \mathrm{CO}_{2}\) and \(0.0310 \mathrm{g} \mathrm{H}_{2} \mathrm{O} .\) In another experiment, it is found that 0.103 g of the compound produces \(0.0230 \mathrm{g} \mathrm{NH}_{3}\) What is the empirical formula of the compound? Hint: Combustion involves reacting with excess \(\mathrm{O}_{2}\). Assume that all the carbon ends up in \(\mathrm{CO}_{2}\) and all the hydrogen ends up in \(\mathrm{H}_{2} \mathrm{O}\). Also assume that all the nitrogen ends up in the \(\mathrm{NH}_{3}\) in the second experiment.

The space shuttle environmental control system handles excess \(\mathrm{CO}_{2}\) (which the astronauts breathe out; it is \(4.0 \%\) by mass of exhaled air) by reacting it with lithium hydroxide, LiOH, pellets to form lithium carbonate, \(\mathrm{Li}_{2} \mathrm{CO}_{3}\), and water. If there are seven astronauts on board the shuttle, and each exhales 20. L of air per minute, how long could clean air be generated if there were 25,000 g of LiOH pellets available for each shuttle mission? Assume the density of air is 0.0010 g/mL.

Nitric acid is produced commercially by the Ostwald process, represented by the following equations: $$\begin{array}{c}4 \mathrm{NH}_{3}(g)+5 \mathrm{O}_{2}(g) \longrightarrow 4 \mathrm{NO}(g)+6 \mathrm{H}_{2} \mathrm{O}(g) \\\2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{NO}_{2}(g) \\\3 \mathrm{NO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 2 \mathrm{HNO}_{3}(a q)+\mathrm{NO}(g)\end{array}$$ What mass of \(\mathrm{NH}_{3}\) must be used to produce \(1.0 \times 10^{6} \mathrm{kg}\) \(\mathrm{HNO}_{3}\) by the Ostwald process? Assume \(100 \%\) yield in each reaction, and assume that the NO produced in the third step is not recycled.

Balance the following equations: a. \(\mathrm{Ca}(\mathrm{OH})_{2}(a q)+\mathrm{H}_{3} \mathrm{PO}_{4}(a q) \rightarrow \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}(s)\) b. \(\mathrm{Al}(\mathrm{OH})_{3}(s)+\mathrm{HCl}(a q) \rightarrow \mathrm{AlCl}_{3}(a q)+\mathrm{H}_{2} \mathrm{O}(l)\) c. \(A g N O_{3}(a q)+H_{2} S O_{4}(a q) \rightarrow A g_{2} S O_{4}(s)+H N O_{3}(a q)\)

Methane \(\left(\mathrm{CH}_{4}\right)\) is the main component of marsh gas. Heating methane in the presence of sulfur produces carbon disulfide and hydrogen sulfide as the only products. a. Write the balanced chemical equation for the reaction of methane and sulfur. b. Calculate the theoretical yield of carbon disulfide when 120. g of methane is reacted with an equal mass of sulfur.

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