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The following are actual student responses to the question: Why is it necessary to balance chemical equations? a. The chemicals will not react until you have added the correct mole ratios. b. The correct products will not be formed unless the right amount of reactants have been added. c. A certain number of products cannot be formed without a certain number of reactants. d. The balanced equation tells you how much reactant you need and allows you to predict how much product you'll make. e. A mole-to-mole ratio must be established for the reaction to occur as written. Justify the best choice, and for choices you did not pick, explain what is wrong with them.

Short Answer

Expert verified
The best choice is d. The balanced equation tells you how much reactant you need and allows you to predict how much product you'll make. This emphasizes the practical application of balanced equations, as they provide the correct stoichiometric relationship for a chemical reaction, enabling us to determine the reactant amounts and predict product quantities. The other choices do not adequately explain the necessity of balancing chemical equations or focus more on mole ratios rather than the practical applications.

Step by step solution

01

Analyze each response

Let's go through each response briefly: a. This statement implies that a reaction won't occur before meeting the right mole ratios. However, reactions can still happen without the perfect mole ratio, but they won't be very efficient, and some reactants may remain unreacted. So, this statement is not entirely correct. b. This statement suggests that correct products will not form without the right amount of reactants. Although the concept of stoichiometry requires proper ratios of reactants to ensure the optimal formation of products, the reaction can still proceed with an excess or deficiency of one reactant; however, the yield of products might not be ideal. c. This statement highlights the relationship between products and reactants, implying that we need a certain number of reactants to form specific products. It's a reasonable statement, but it lacks clarity in expressing the importance of balancing the reactions. d. This statement emphasizes the practical application of balanced equations in determining the required reactant quantities and predicting product formation. It correctly explains the importance of balancing chemical equations in practical situations. e. Although mole-to-mole relationships are crucial in determining reactants' and products' amounts, this statement does not concretely address the necessity of balancing the equations.
02

Select the best choice and explain why

Based on the analysis, the best choice is: d. The balanced equation tells you how much reactant you need and allows you to predict how much product you'll make. Balanced chemical equations are essential because they provide the correct stoichiometric relationship for a chemical reaction. This information enables us to determine the amounts of reactants necessary for a reaction and predict the quantities of products.
03

Explain why the other choices are incorrect or not the best choice

a. While mole ratios are essential, reactions can still happen without the perfect mole ratio, though they may be inefficient. Therefore, this statement is not entirely correct. b. Although stoichiometry requires proper ratios of reactants to ensure the optimal formation of products, the reaction can still proceed with non-ideal ratios, although the yield of products might not be ideal. This statement is somewhat correct, but it's not the best choice because it doesn't highlight the practical importance of balancing equations like option d. c. This statement has merit but lacks clarity in expressing the importance of balancing the reactions. It's not as direct as option d in explaining why balancing chemical equations is required. e. This statement does not address directly the necessity of balancing chemical equations. Moreover, it is not as insightful as option d, which emphasizes the practical applications of balanced equations in calculating reactants and predicting products.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoichiometry
Stoichiometry can be compared to a recipe for a chemical reaction: it tells us exactly how much of each ingredient (reactant) we need to mix together to create a certain amount of product. Understanding stoichiometry is foundational for anyone studying chemistry, as it not only involves the conservation of mass and the laws of definite proportions but also serves as a bridge between the molecular world and the real-world measurements that chemists must make.

For instance, if you’re baking a cake, the recipe might call for two eggs for every cup of flour. Similarly, a chemical equation provides the amounts of reactants needed to combine to form products, typically given in moles. The importance of stoichiometry lies in its ability to allow scientists to predict the outcomes of chemical reactions, making it an essential tool for chemists in both research and industrial settings. As in the example provided, option d best illustrates the utility of stoichiometry, showcasing its role in providing the quantities needed for a reaction and the yield of products one can expect.
Reactants and Products
Imagine building a model car; the parts that you start with are the reactants, and the completed model car is the product. In a chemical reaction, we start with certain substances, called reactants, which undergo a chemical change to become different substances, known as products.

Whether cooking or in the chemistry lab, the starting materials (reactants) are transformed into new compounds (products). The role of balancing chemical equations guarantees that we have accounted for all the reactants and can figure out how much product will be made. It's crucial to realize that while a chemical reaction may proceed even with different amounts of starting materials, as suggested in options b and c, the balanced equation represents the most efficient reaction pathway, where all reactants are used up completely, yielding the maximum amount of product, which is why option d, emphasizing the predictive power of a balanced equation, is the justified choice.
Mole-to-Mole Ratio
Understanding the mole-to-mole ratio is like understanding exchange rates in currency. Just as one may need to exchange a certain number of US dollars for euros, in chemistry, one needs to convert moles of one substance to moles of another based on the balanced chemical equation. This mole-to-mole ratio fulfills a crucial role in stoichiometry by specifying the proportions of reactants that react and products formed.

Statement e in the exercise touches on the importance of this ratio for reactions to occur as written, but it's crucial to emphasize that the 'mole-to-mole' ratio is derived from the balanced equation and is essential for practical applications like creating the right mixture for a reaction or determining the expected yield of product. Hence, while statement e recognizes the concept of mole ratios, statement d more accurately conveys the broader utility of balancing chemical equations, incorporating the idea that such balancing ensures the mole-to-mole ratios are correct for the reaction at hand.

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Most popular questions from this chapter

One of the components that make up common table sugar is fructose, a compound that contains only carbon, hydrogen, and oxygen. Complete combustion of \(1.50 \mathrm{g}\) of fructose produced \(2.20 \mathrm{g}\) of carbon dioxide and \(0.900 \mathrm{g}\) of water. What is the empirical formula of fructose?

Give the balanced equation for each of the following chemical reactions: a. Glucose \(\left(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\right)\) reacts with oxygen gas to produce gaseous carbon dioxide and water vapor. b. Solid iron(III) sulfide reacts with gaseous hydrogen chloride to form solid iron(III) chloride and hydrogen sulfide gas. c. Carbon disulfide liquid reacts with ammonia gas to produce hydrogen sulfide gas and solid ammonium thiocyanate \(\left(\mathrm{NH}_{4} \mathrm{SCN}\right).\)

Glass is a mixture of several compounds, but a major constituent of most glass is calcium silicate, \(\mathrm{CaSiO}_{3}\). Glass can be etched by treatment with hydrofluoric acid; HF attacks the calcium silicate of the glass, producing gaseous and water-soluble products (which can be removed by washing the glass). For example, the volumetric glassware in chemistry laboratories is often graduated by using this process. Balance the following equation for the reaction of hydrofluoric acid with calcium silicate. $$\mathrm{CaSiO}_{3}(s)+\mathrm{HF}(a q) \longrightarrow \mathrm{CaF}_{2}(a q)+\mathrm{SiF}_{4}(g)+\mathrm{H}_{2} \mathrm{O}(l)$$

The aspirin substitute. acetaminophen \(\left(\mathrm{C}_{8} \mathrm{H}_{9} \mathrm{O}_{2} \mathrm{N}\right),\) is produced by the following three-step synthesis: I. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}_{3} \mathrm{N}(s)+3 \mathrm{H}_{2}(g)+\mathrm{HCl}(a q) \longrightarrow\) \(\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{ONCl}(s)+2 \mathrm{H}_{2} \mathrm{O}(l)\) II. \(\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{ONCl}(s)+\mathrm{NaOH}(a q) \longrightarrow\) \(\mathrm{C}_{6} \mathrm{H}_{7} \mathrm{ON}(s)+\mathrm{H}_{2} \mathrm{O}(l)+\mathrm{NaCl}(a q)\) III. \(\mathrm{C}_{6} \mathrm{H}_{7} \mathrm{ON}(s)+\mathrm{C}_{4} \mathrm{H}_{6} \mathrm{O}_{3}(l) \longrightarrow\) \(\mathrm{C}_{8} \mathrm{H}_{9} \mathrm{O}_{2} \mathrm{N}(s)+\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}(l)\) The first two reactions have percent yields of \(87 \%\) and \(98 \%\) by mass, respectively. The overall reaction yields 3 moles of acetaminophen product for every 4 moles of \(C_{6} H_{5} O_{3} N\) reacted. a. What is the percent yield by mass for the overall process? b. What is the percent yield by mass of Step III?

When \(\mathrm{M}_{2} \mathrm{S}_{3}(s)\) is heated in air, it is converted to \(\mathrm{MO}_{2}(s) .\) A \(4.000-\mathrm{g}\) sample of \(\mathrm{M}_{2} \mathrm{S}_{3}(s)\) shows a decrease in mass of \(0.277 \mathrm{g}\) when it is heated in air. What is the average atomic mass of \(\mathrm{M} ?\)

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