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Consider the following reaction: $$ \mathrm{A}_{2}+\mathrm{B}_{2} \longrightarrow 2 \mathrm{AB} \quad \Delta E=-285 \mathrm{kJ} $$ The bond energy for \(A_{2}\) is one-half the amount of the AB bond energy. The bond energy of \(\mathbf{B}_{2}=432 \mathrm{kJ} / \mathrm{mol} .\) What is the bond energy of \(\mathrm{A}_{2} ?\)

Short Answer

Expert verified
The bond energy of A₂ is 49 kJ/mol.

Step by step solution

01

Write down the given information

Here are the information given in the problem: - A₂ + B₂ ⟶ 2AB, ∆E = -285 kJ - Bond energy of B₂ = 432 kJ/mol - Bond energy of A₂ = (1/2) × Bond energy of AB
02

Calculate the total bond energy of the products

Assuming that the bond energy of AB is x kJ/mol, the total bond energy of products, considering the stoichiometric coefficients, will be 2x kJ.
03

Calculate the total bond energy of the reactants

The bond energy of A₂ is (1/2) x, and the bond energy of B₂ is 432 kJ/mol. Therefore, the total bond energy of reactants is (1/2)x + 432 kJ.
04

Apply Hess's Law

Hess's law states that the energy change for the reaction (∆E) is equal to the total bond energy of products minus the total bond energy of reactants. In this case, we have: -285 kJ = (2x kJ) - [(1/2)x + 432 kJ]
05

Solve for x (bond energy of AB)

Rearrange the equation to solve for x: -285 kJ + 432 kJ = (2x kJ) - (1/2)x 147 kJ = (3/2)x x = 98 kJ/mol The bond energy of the AB molecule is 98 kJ/mol.
06

Find the bond energy of A₂

Using the relationship given, we can now find the bond energy of A₂: Bond energy of A₂ = (1/2) × Bond energy of AB Bond energy of A₂ = (1/2) × 98 kJ/mol Bond energy of A₂ = 49 kJ/mol So, the bond energy of A₂ is 49 kJ/mol.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hess's Law
Hess's Law is a fundamental principle in chemistry that helps us understand energy changes in chemical reactions. It states that the total enthalpy change for a reaction is the same, regardless of the pathway taken. In simpler terms, it doesn't matter how you get from reactants to products; the energy change is constant.

In the context of our reaction, Hess's Law allows us to simplify the calculation of bond energies. We can separate the reaction into the breaking and forming of bonds, which lets us calculate the overall reaction energy. This approach is very helpful because direct measurement of bond energies isn't always feasible.

By applying Hess's Law, we can compute the required bond energies by using known bond energies and reacting substances. This helps us unravel the total energy exchanges involved in the process, providing insight into reaction energetics.
Enthalpy Change
Enthalpy change, often represented as \( \Delta H \), is the amount of heat absorbed or released during a chemical reaction. It indicates whether a reaction is endothermic or exothermic.
  • If \( \Delta H \) is negative, the reaction releases heat (exothermic).
  • If \( \Delta H \) is positive, the reaction absorbs heat (endothermic).
In our reaction, the enthalpy change \( \Delta E = -285 \text{ kJ} \) shows that the reaction releases 285 kJ of energy, making it exothermic. This is a vital piece of information because it tells us that the energy required to break the bonds in the reactants is less than the energy released when new bonds form in the products.

By carefully analyzing the enthalpy change, we can understand the energy dynamics at play and predict how the reaction's energetics progress. This concept serves as a cornerstone for understanding not only this particular reaction but many others in energetics studies.
Chemical Reaction Energetics
Chemical reaction energetics focuses on understanding the energy changes that occur during a chemical reaction. Energetics involves examining how energy is conserved, transferred, and transformed in the course of a reaction.

The key to comprehending reaction energetics starts with the bonds themselves. Energy is needed to break chemical bonds (endothermic) and is released when new bonds form (exothermic). Knowing the bond energies enables us to calculate the net energy change in a reaction.
  • Calculate individual bond energies.
  • Assess how much energy is absorbed/released.
  • Determine whether the overall reaction is endothermic or exothermic.
The solution to our exercise employs these principles to determine the bond energy of \( \text{A}_2 \). By comparing the energy of products and reactants, we understand how chemical bonds influence the overall energetics of the reaction.
Understanding these energetic principles is essential for predicting reaction viability, selecting suitable reaction conditions, and designing effective industrial processes.

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Most popular questions from this chapter

Write Lewis structures that obey the octet rule for each of the following molecules and ions. (In each case the first atom listed is the central atom.) a. \(\mathrm{POCl}_{3}, \mathrm{SO}_{4}^{2-}, \mathrm{XeO}_{4}, \mathrm{PO}_{4}^{3-}, \mathrm{ClO}_{4}^{-}\) b. \(\mathrm{NF}_{3}, \mathrm{SO}_{3}^{2-}, \mathrm{PO}_{3}^{3-}, \mathrm{ClO}_{3}^{-}\) c. \(\mathrm{ClO}_{2}^{-}, \mathrm{SCl}_{2}, \mathrm{PCl}_{2}^{-}\) d. Considering your answers to parts a, b, and c, what conclusions can you draw concerning the structures of species containing the same number of atoms and the same number of valence electrons?

Write Lewis structures for the following. Show all resonancestructures where applicable.a. \(\mathrm{NO}_{2}^{-}, \mathrm{NO}_{3}^{-}, \mathrm{N}_{2} \mathrm{O}_{4}\left(\mathrm{N}_{2} \mathrm{O}_{4} \text { exists as } \mathrm{O}_{2} \mathrm{N}-\mathrm{NO}_{2} .\right)\) b. \(\mathrm{OCN}^{-}, \mathrm{SCN}^{-}, \mathrm{N}_{3}^{-}\) (Carbon is the central atom in \(\mathrm{OCN}^{-}\) and \(\mathrm{SCN}^{-} .\) )

Without using Fig. \(3-4,\) predict which bond in each of the following groups will be the most polar. a. \(C-F, S i-F, G e-F\) b. \(P-C\) or \(S-C\) \(\mathbf{c} . \mathbf{S}-\mathbf{F}, \mathbf{S}-\mathbf{C} \mathbf{l}, \mathbf{S}-\mathbf{B r}\) d. \(\mathrm{Ti}-\mathrm{Cl}, \mathrm{Si}-\mathrm{Cl}, \mathrm{Ge}-\mathrm{Cl}\)

Consider the following: $$\mathrm{Li}(s)+\frac{1}{2} \mathrm{I}_{2}(s) \longrightarrow \mathrm{LiI}(s) \quad \Delta E=-272 \mathrm{kJ} / \mathrm{mol}$$ LiI(s) has a lattice energy of -753 kJ/mol. The ionization energy of \(\mathrm{Li}(g)\) is \(520 . \mathrm{kJ} / \mathrm{mol},\) the bond energy of \(\mathrm{I}_{2}(g)\) is \(151 \mathrm{kJ} /\) mol, and the electron affinity of \(\mathrm{I}(g)\) is \(-295 \mathrm{kJ} / \mathrm{mol} .\) Use these data to determine the energy of sublimation of Li(s).

Look up the energies for the bonds in CO and \(\mathrm{N}_{2}\). Although the bond in CO is stronger, CO is considerably more reactive than \(\mathrm{N}_{2}\). Give a possible explanation.

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