Chapter 3: Problem 4
The bond energy for a \(\mathrm{C}-\mathrm{H}\) bond is about \(413 \mathrm{kJ} / \mathrm{mol}\) in \(\mathrm{CH}_{4}\) but \(380 \mathrm{kJ} / \mathrm{mol}\) in \(\mathrm{CHBr}_{3}\). Although these values are relatively close in magnitude, they are different. Explain why they are different. Does the fact that the bond energy is lower in CHBr \(_{3}\) make any sense? Why?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.