Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Some of the important properties of ionic compounds are as follows: i. Iow electrical conductivity as solids and high conductivity in solution or when molten ii. relatively high melting and boiling points iii. brittleness iv. solubility in polar solvents How does the concept of ionic bonding discussed in this chapter account for these properties?

Short Answer

Expert verified
Ionic compounds have low electrical conductivity in solid form due to the fixed positions of ions in a crystal lattice, but high conductivity when molten or in solution, as ions can move freely. The strong electrostatic forces between ions result in high melting and boiling points. Brittleness is due to the shifting of ions under stress, causing repulsion between ions of the same charge. Solubility in polar solvents is due to the interaction between solvent molecules and oppositely charged ions in the compound.

Step by step solution

01

i. Electrical Conductivity

The electrical conductivity of a substance is due to the presence of charged particles that can move freely within its structure. In ionic compounds, the ions are held together by strong electrostatic forces in a crystal lattice. When the compound is in solid form, these ions are not able to move freely, resulting in low electrical conductivity. However, when an ionic compound is dissolved in water (forming a solution) or melted, the ions can move around more freely. This allows ionic compounds to conduct electricity in solution or when molten.
02

ii. High Melting and Boiling Points

The melting and boiling points of a substance are influenced by the forces between its particles. Ionic compounds have high melting and boiling points due to the strong electrostatic forces between the ions in their crystal lattice. The energy required to break these forces and cause a change in phase (from solid to liquid or liquid to gas) is significant, resulting in high melting and boiling points for ionic compounds.
03

iii. Brittleness

Brittleness refers to the tendency of a material to break or fracture under stress. In an ionic compound, the crystal lattice is an ordered array of positively charged cations and negatively charged anions. The strength of this structure is due to the electrostatic attraction between oppositely charged ions. However, if an external force is applied, it can cause the ions in the lattice to shift. This may result in ions of the same charge being aligned, causing repulsion between the ions, and weakening the structure. Therefore, ionic compounds tend to be brittle, breaking or fracturing under stress.
04

iv. Solubility in Polar Solvents

Solubility in a solvent depends on the nature of both the solute and the solvent. Ionic compounds tend to be soluble in polar solvents, such as water. This is because the polar solvent molecules interact with the oppositely charged ions of the ionic compound, weakening the strong electrostatic forces that hold them together in the crystal lattice. The solvent molecules surround the ions, forming a stable solution with the ionic compound dissolved in it. Thus, the concept of ionic bonding explains the solubility of ionic compounds in polar solvents.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electrical Conductivity
Ionic compounds have interesting electrical conductivity properties. When these compounds are in solid form, their ionic lattice structure means ions are tightly packed and unable to move freely. This results in low electrical conductivity. However, once ionic compounds are either melted or dissolved in water, the rigid structure breaks down. This allows ions to move freely, enabling these compounds to conduct electricity.
  • Solid State: Ions are fixed in place, preventing electrical flow.
  • Molten or Dissolved: Ions are free, allowing for electric current to pass through.
In essence, the ability for ions to move is key to electrical conduction in ionic materials.
Melting and Boiling Points
Ionic compounds are known for their high melting and boiling points. This is due to the strong electrostatic forces holding the ions together in a crystal lattice. Breaking these forces requires substantial energy, making it difficult for these compounds to change from solid to liquid or liquid to gas.
  • High Energy Requirement: Strong ionic bonds need significant energy to break.
  • Solid Stability: Stable structure persists until high temperatures are reached.
The high melting and boiling points reflect the robust ionic bonding in these compounds.
Brittleness
The brittle nature of ionic compounds comes from their crystal lattice structure. This structure is rigid and ordered, comprised of alternating positive and negative ions. Under pressure or stress, if the lattice shifts, ions of the same charge may align. This can cause a repulsive force, fracturing the material.
  • Ordered Structure: Alternating charge sequence in a crystal lattice.
  • Fracturing Under Stress: Misalignment of ions leading to repulsion.
Thus, brittleness in ionic compounds is a direct consequence of their ionic lattice structure.
Solubility in Polar Solvents
Ionic compounds tend to dissolve well in polar solvents, such as water, due to the interaction between the solvent molecules and the ions. The polar nature of solvents, with positive and negative poles, allows them to effectively surround and interact with the separated ions, weakening the electrostatic forces in the crystal lattice.
  • Polar Interactions: Solvent molecules are attracted to ions, breaking the ionic bonds.
  • Solution Formation: Stable dissolution as ions are encapsulated by solvent molecules.
This behavior highlights the impact of ionic bonding on solubility, emphasizing the role of polar solvents in dissolving ionic compounds.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the following data formagnesium fluoride to estimate \(\Delta E\) for the reaction: $$\mathrm{Mg}(s)+\mathrm{F}_{2}(g) \longrightarrow \mathrm{MgF}_{2}(s) \quad \Delta E=?$$ Lattice energy First ionization energy of \(\mathrm{Mg}\) Second ionization energy of \(\mathbf{M g}\) Electron affinity of \(\mathbf{F}\) Bond energy of \(\mathrm{F}_{2}\) Energy of sublimation for \(\mathrm{Mg}\) \(-2913 \mathrm{kJ} / \mathrm{mol}\) \(735 \mathrm{kJ} / \mathrm{mol}\) \(1445 \mathrm{kJ} / \mathrm{mol}\) \(-328 \mathrm{kJ} / \mathrm{mol}\) \(154 \mathrm{kJ} / \mathrm{mol}\) 150\. kJ/mol

Look up the energies for the bonds in CO and \(\mathrm{N}_{2}\). Although the bond in CO is stronger, CO is considerably more reactive than \(\mathrm{N}_{2}\). Give a possible explanation.

Give three ions that are isoelectronic with neon. Place these ions in order of increasing size.

Nitrous oxide \(\left(\mathrm{N}_{2} \mathrm{O}\right)\) has three possible Lewis structures: $$\therefore N=N=O^{\cdot} \leftrightarrow: N \equiv N-\vec{O}: \longleftrightarrow: N-N \equiv 0$$ Given the following bond lengths, $$\begin{aligned} &\mathrm{N}-\mathrm{N} \quad 167 \mathrm{pm} \quad \mathrm{N}=\mathrm{O} \quad 115 \mathrm{pm}\\\ &\mathrm{N}=\mathrm{N} \quad 120 \mathrm{pm} \quad \mathrm{N}-\mathrm{O} \quad 147 \mathrm{pm}\\\ &\mathrm{N} \equiv \mathrm{N} \quad 110 \mathrm{pm} \end{aligned}$$ rationalize the observations that the \(\mathrm{N}-\mathrm{N}\) bond length in \(\mathrm{N}_{2} \mathrm{O}\) is \(112 \mathrm{pm}\) and that the \(\mathrm{N}-\mathrm{O}\) bond length is \(119 \mathrm{pm}\). Assign formal charges to the resonance structures for \(\mathrm{N}_{2} \mathrm{O}\). Can you eliminate any of the resonance structures on the basis of formal charges? Is this consistent with observation?

Give the formula of a negative ion that would have the same number of electrons as each of the following positive ions. a. \(\mathrm{Na}^{+}\) b. \(\mathrm{Ca}^{2+}\) \(\mathbf{c} . \mathrm{Al}^{3+}\) d. \(\mathbf{R} \mathbf{b}^{+}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free