Chapter 3: Problem 14
Why do we call \(\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}\) barium nitrate, but we call \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{2}\) iron(II) nitrate?
Chapter 3: Problem 14
Why do we call \(\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}\) barium nitrate, but we call \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{2}\) iron(II) nitrate?
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Get started for freeName each of the following compounds. Assume the acids are dissolved in water. a. \(\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\) b. \(\mathrm{NH}_{4} \mathrm{NO}_{2}\) c. \(\mathrm{Co}_{2} \mathrm{S}_{3}\) d. ICl e. \(\mathrm{Pb}_{3}\left(\mathrm{PO}_{4}\right)_{2}\) f. \(\mathrm{KClO}_{3}\) g. \(\mathrm{H}_{2} \mathrm{SO}_{4}\) \(\mathbf{h} . \mathrm{Sr}_{3} \mathrm{N}_{2}\) i. \(\quad \mathrm{Al}_{2}\left(\mathrm{SO}_{3}\right)_{3}\) J. \(\mathrm{SnO}_{2}\) \(\mathbf{k} . \mathrm{Na}_{2} \mathrm{CrO}_{4}\) I. \(\mathrm{HClO}\)
The major industrial source of hydrogen gas is by the following reaction: $$ \mathrm{CH}_{4}(g)+\mathrm{H}_{2} \mathrm{O}(g) \longrightarrow \mathrm{CO}(g)+3 \mathrm{H}_{2}(g) $$ Use bond energies to predict r this reaction.
Give the formula of a negative ion that would have the same number of electrons as each of the following positive ions. a. \(\mathrm{Na}^{+}\) b. \(\mathrm{Ca}^{2+}\) \(\mathbf{c} . \mathrm{Al}^{3+}\) d. \(\mathbf{R} \mathbf{b}^{+}\)
Use the following data formagnesium fluoride to estimate \(\Delta E\) for the reaction: $$\mathrm{Mg}(s)+\mathrm{F}_{2}(g) \longrightarrow \mathrm{MgF}_{2}(s) \quad \Delta E=?$$ Lattice energy First ionization energy of \(\mathrm{Mg}\) Second ionization energy of \(\mathbf{M g}\) Electron affinity of \(\mathbf{F}\) Bond energy of \(\mathrm{F}_{2}\) Energy of sublimation for \(\mathrm{Mg}\) \(-2913 \mathrm{kJ} / \mathrm{mol}\) \(735 \mathrm{kJ} / \mathrm{mol}\) \(1445 \mathrm{kJ} / \mathrm{mol}\) \(-328 \mathrm{kJ} / \mathrm{mol}\) \(154 \mathrm{kJ} / \mathrm{mol}\) 150\. kJ/mol
Rationalize the following lattice energy values: $$\begin{array}{|lc|} \hline & \text { Lattice Energy } \\ \text { Compound } & \text { (kj/mol) } \\ \hline \text { CaSe } & -2862 \\ \text { Na }_{2} \text { Se } & -2130 \\ \text { CaTe } & -2721 \\ \text { Na }_{2} \text { Te } & -2095 \\ \hline \end{array}$$
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