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Sketch a \(d\) -orbital energy diagram for the following. a. a linear complex ion with ligands on the \(x\) axis b. a linear complex ion with ligands on the \(y\) axis

Short Answer

Expert verified
For a linear complex ion with ligands on the x-axis, the energy diagram will have \(d_{zy}\) and \(d_{zx}\) at the same lower energy level, while \(d_{xy}\), \(d_{x^2 - y^2}\), and \(d_{z^2}\) will be at the same higher energy level. For a linear complex ion with ligands on the y-axis, the energy diagram will have \(d_{yz}\) and \(d_{xy}\) at the same lower energy level, while \(d_{xz}\), \(d_{x^2 - y^2}\), and \(d_{z^2}\) will be at the same higher energy level.

Step by step solution

01

Case a - Linear complex ion with ligands on the x-axis

In this case, we need to consider the energy levels of the d-orbitals with respect to the x-axis. The five d-orbitals are: 1. \(d_{xy}\) 2. \(d_{yz}\) 3. \(d_{xz}\) 4. \(d_{x^2 - y^2}\) 5. \(d_{z^2}\) When the complex has linear geometry and ligands on the x-axis, the splitting of the d-orbitals occurs as follows: 1. \(d_{zy}\) and \(d_{zx}\) remain non-bonding orbitals, as they contain no interaction with the ligands on the x-axis. 2. \(d_{xy}\), \(d_{x^2 - y^2}\), and \(d_{z^2}\) interact with the ligands on the x-axis and experience an increase in energy. Thus, the energy diagram for this complex will have the following arrangement: - \(d_{zy}\) and \(d_{zx}\) are at the same lower energy level. - \(d_{xy}\), \(d_{x^2 - y^2}\), and \(d_{z^2}\) are at the same higher energy level.
02

Case b - Linear complex ion with ligands on the y-axis

In this case, we need to consider the energy levels of the d-orbitals with respect to the y-axis. The five d-orbitals are the same as stated before. When the complex has linear geometry and ligands on the y-axis, the splitting of the d-orbitals occurs as follows: 1. \(d_{yz}\) and \(d_{xy}\) remain non-bonding orbitals, as they contain no interaction with the ligands on the y-axis. 2. \(d_{xz}\), \(d_{x^2 - y^2}\), and \(d_{z^2}\) interact with the ligands on the y-axis and experience an increase in energy. Thus, the energy diagram for this complex will have the following arrangement: - \(d_{yz}\) and \(d_{xy}\) are at the same lower energy level. - \(d_{xz}\), \(d_{x^2 - y^2}\), and \(d_{z^2}\) are at the same higher energy level.

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Most popular questions from this chapter

\(\mathrm{CoCl}_{4}^{2-}\) forms a tetrahedral complex ion and \(\mathrm{Co}(\mathrm{CN})_{6}^{3-}\) forms an octahedral complex ion. What is wrong about the following statements concerning each complex ion and the \(d\) orbital splitting diagrams? a. \(\mathrm{CoCl}_{4}^{2-}\) is an example of a strong-field case having two unpaired electrons. b. Because \(\mathrm{CN}^{-}\) is a weak-field ligand, \(\mathrm{Co}(\mathrm{CN})_{6}^{3-}\) will be a low-spin case having four unpaired electrons.

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