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Explain the difference between the probability density distribution for an orbital and its radial probability.

Short Answer

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The main difference between the probability density distribution for an orbital and its radial probability distribution lies in the dimensions they represent. The probability density distribution is a three-dimensional representation considering the electron's position in all three spatial coordinates (x, y, and z) and depends on quantum numbers n, l, and m. In contrast, the radial probability distribution is only concerned with the electron's distance from the nucleus (r), without considering the angular dependence, and depends on quantum numbers n and l. While the probability density distribution provides a complete three-dimensional representation of the electron distribution in an orbital, the radial probability distribution focuses only on the electron's distance from the nucleus, ignoring any angular dependence.

Step by step solution

01

Define Probability Density Distribution for an Orbital

The probability density distribution for an orbital, also known as the electron cloud, represents the probability of finding an electron in a particular region of space around an atom's nucleus. It is a three-dimensional representation that takes into account the electron's position in the x, y, and z coordinates. The probability density depends on the quantum numbers associated with the electron, including the principal quantum number (n), the azimuthal quantum number (l), and the magnetic quantum number (m).
02

Define Radial Probability Distribution

The radial probability distribution describes the probability of finding an electron at a particular distance (r) from the nucleus, without considering the angular dependence. It is represented as the product of the radial part of the wave function squared (R(r)^2) and the volume of the thin spherical shell (4πr^2). The radial probability distribution only depends on the principal quantum number (n) and the azimuthal quantum number (l).
03

Explain the Difference between the Two Concepts

The main difference between the probability density distribution for an orbital and its radial probability distribution lies in the dimensions they represent. The probability density distribution is a three-dimensional representation and considers the electron's position in all three spatial coordinates (x, y, and z). On the other hand, the radial probability distribution is only concerned with the electron's distance from the nucleus (r), ignoring any angular dependence.
04

Provide an Example

Let's consider the s orbitals as an example. The probability density distribution for a 1s orbital is a spherical electron cloud centered on the nucleus. In this case, the probability of finding an electron in different regions of space is represented by the whole electron cloud, taking into account the x, y, and z coordinates. The radial probability distribution for a 1s orbital, however, ignores the angular dependence and focuses only on the distance from the nucleus. For example, the radial probability distribution for a 1s orbital reaches a maximum value at a particular distance (r), where the electron is most likely to be found, and then decreases as the distance from the nucleus increases. In summary, while the probability density distribution provides a complete three-dimensional representation of the electron distribution in an orbital, the radial probability distribution focuses only on the electron's distance from the nucleus, ignoring any angular dependence.

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Most popular questions from this chapter

Answer the following questions, assuming that \(m_{s}\) could have three values rather than two and that the rules for \(n, \ell,\) and \(m_{\ell}\) are the normal ones. a. How many electrons would an orbital be able to hold? b. How many elements would the first and second periods in the periodic table contain? c. How many elements would be contained in the first transition metal series? d. How many electrons would the set of \(4 f\) orbitals be able to hold?

An unknown element is a nonmetal and has a valence electron configuration of \(n s^{2} n p^{4}\). a. How many valence electrons does this element have? b. What are some possible identities for this element? c. What is the formula of the compound this element would form with potassium? d. Would this element have a larger or smaller radius than barium? e. Would this element have a greater or smaller ionization energy than fluorine?

A carbon-oxygen double bond in a certain organic molecule absorbs radiation that has a frequency of \(6.0 \times 10^{13} \mathrm{s}^{-1}\). a. What is the wavelength of this radiation? b. To what region of the spectrum does this radiation belong? c. What is the energy of this radiation per photon? d. A carbon-oxygen bond in a different molecule absorbs radiation with frequency equal to \(5.4 \times 10^{13} \mathrm{s}^{-1} .\) Is this radiation more or less energetic?

For each of the following pairs of elements $$(\mathrm{Mg} \text { and } \mathrm{K}) \quad(\mathrm{F} \text { and } \mathrm{Cl})$$ pick the atom with a. more favorable (more negative) electron affinity. b. higher ionization energy. c. larger size.

Calculate the wavelength of light emitted when each of the following transitions occur in the hydrogen atom. What type of electromagnetic radiation is emitted in each transition? a. \(n=4 \rightarrow n=3\) b. \(n=5 \rightarrow n=4\) c. \(n=5 \rightarrow n=3\)

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