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What are transuranium elements and how are they synthesized?

Short Answer

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Transuranium elements are artificial elements with atomic numbers greater than 92 (uranium). They are synthesized through nuclear reactions involving the bombardment of a target nucleus with particles like neutrons, protons, or heavier nuclei to create larger nuclei with higher atomic numbers. The process involves choosing a suitable target nucleus and bombarding particles, accelerating the particles using a particle accelerator, causing the desired nuclear reaction, and finally detecting and identifying the newly created transuranium element through various detectors and spectroscopic techniques.

Step by step solution

01

Introduction to Transuranium Elements

Transuranium elements are chemical elements that have atomic numbers higher than the element uranium (atomic number 92). These elements do not occur naturally on Earth and are created artificially in laboratories through nuclear reactions.
02

Different Synthesis Methods

There are several methods to synthesize transuranium elements, including: 1. Neutron bombardment: Bombarding a target nucleus with neutrons to form a larger nucleus. 2. Proton bombardment: Bombarding a target nucleus with protons to increase its atomic number. 3. Heavy ion bombardment: Bombarding a target nucleus with heavy ions such as alpha particles or other nuclei. In all these methods, the basic idea is to combine the target nucleus with the bombarding particles in such a way that the resulting nucleus has a higher atomic number than the original target nucleus.
03

Selection of Target Nucleus and Bombarding Particles

First, we need to choose a target nucleus and appropriate bombarding particles to create a specific transuranium element. The choice depends on the desired synthetic route and the specific element that we want to synthesize.
04

Accelerating Bombarding Particles

The bombarding particles are accelerated to extremely high speeds to overcome the electrostatic repulsion between the positively charged particles and target nucleus. This is done using a particle accelerator, such as a cyclotron or a linear accelerator.
05

Nuclear Reaction

The accelerated particles collide with the target nucleus, and if the conditions are right, they will overcome the repulsion and combine with the target nucleus. The result is a new nucleus with a higher atomic number, creating a transuranium element. However, several different reactions might occur, so the desired reaction might not always be the most probable one.
06

Detection and Identification

After the nuclear reaction, the newly created nucleus may undergo radioactive decay, emitting various forms of radiation. These radiations can be detected and measured to determine the atomic number and other properties of the newly synthesized transuranium element. This is typically done using detectors and spectroscopic methods, such as gamma-ray spectroscopy or mass spectrometry. In conclusion, transuranium elements are artificially synthesized elements with atomic numbers greater than 92. They are created through various nuclear reactions, such as neutron, proton, or heavy-ion bombardment, followed by the detection and identification of the newly created nuclei.

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Most popular questions from this chapter

Consider the following information: i. The layer of dead skin on our bodies is sufficient to protect us from most \(\alpha\) -particle radiation. ii. Plutonium is an \(\alpha\) -particle producer. iii. The chemistry of \(\mathrm{Pu}^{4+}\) is similar to that of \(\mathrm{Fe}^{3+}\). iv. Pu oxidizes readily to \(\mathrm{Pu}^{4+}\) Why is plutonium one of the most toxic substances known?

When nuclei undergo nuclear transformations, \(\gamma\) rays of characteristic frequencies are observed. How does this fact, along with other information in the chapter on nuclear stability, suggest that a quantum mechanical model may apply to the nucleus?

Many elements have been synthesized by bombarding relatively heavy atoms with high-energy particles in particle accelerators. Complete the following nuclear equations, which have been used to synthesize elements. a. \(\quad+\frac{4}{2} H e \rightarrow 243 B k+\frac{1}{0} n\) b. \(^{238} \mathrm{U}+^{12}_{6} \mathrm{C} \rightarrow$$\quad$$+6_{0}^{1} n\) c. \(^{249} \mathrm{Cf}+$$\quad$$\rightarrow \frac{260}{105} D b+4 \frac{1}{6} n\) d. \(^{249} \mathrm{Cf}+^{10}_{5} \mathrm{B} \rightarrow \frac{257}{153} \mathrm{Lr}+\)__________

The most stable nucleus in terms of binding energy per nucleon is \(^{56} \mathrm{Fe}\). If the atomic mass of \(^{56} \mathrm{Fe}\) is \(55.9349 \mathrm{u},\) calculate the binding energy per nucleon for \(^{56} \mathrm{Fe}\).

The curie (Ci) is a commonly used unit for measuring nuclear radioactivity: 1 curie of radiation is equal to \(3.7 \times 10^{10}\) decay events per second (the number of decay events from 1 g radium in \(1 \mathrm{s}\) ). a. What mass of \(\mathrm{Na}_{2}^{38} \mathrm{SO}_{4}\) has an activity of \(10.0 \mathrm{mCi} ?\) Sulfur-38 has an atomic mass of 38.0 u and a half-life of \(2.87 \mathrm{h}\) b. How long does it take for \(99.99 \%\) of a sample of sulfur-38 to decay?

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