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Which of the following statements concerning corrosion is(are) true? For the false statements, correct them. a. Corrosion is an example of an electrolytic process. b. Corrosion of steel involves the reduction of iron coupled with the oxidation of oxygen. c. Steel rusts more easily in the dry (arid) Southwest states than in the humid Midwest states. d. Salting roads in the winter has the added benefit of hindering the corrosion of steel. e. The key to cathodic protection is to connect via a wire a metal more easily oxidized than iron to the steel surface to be protected.

Short Answer

Expert verified
False statements and their corrections: a. Corrosion is an example of an electrolytic process. Correction: Corrosion is an example of a galvanic process. c. Steel rusts more easily in the dry (arid) Southwest states than in the humid Midwest states. Correction: Steel rusts more easily in the humid Midwest states than in the dry Southwest states. d. Salting roads in the winter has the added benefit of hindering the corrosion of steel. Correction: Salting roads in the winter accelerates the corrosion of steel. True statements: b. Corrosion of steel involves the reduction of iron coupled with the oxidation of oxygen. e. The key to cathodic protection is to connect via a wire a metal more easily oxidized than iron to the steel surface to be protected.

Step by step solution

01

Statement a

Corrosion is an example of an electrolytic process. False. Corrosion is an example of a galvanic process, not an electrolytic one. In an electrolytic process, an electric current is applied to drive a nonspontaneous redox reaction, while in a galvanic process, the redox reaction happens spontaneously.
02

Statement b

Corrosion of steel involves the reduction of iron coupled with the oxidation of oxygen. True. The corrosion of steel mainly consists of two half-reactions: the reduction of oxygen (O2) to form hydroxide ions (OH-) and the oxidation of iron (Fe) to form iron(II) ions (Fe²⁺). The hydroxide ions and iron(II) ions react with each other to form a hydrated complex of iron(III) oxide, also known as rust.
03

Statement c

Steel rusts more easily in the dry (arid) Southwest states than in the humid Midwest states. False. Steel rusts more easily in humid environments than in dry environments. The presence of moisture and oxygen is necessary for the corrosion process to occur. In the humid Midwest states, there is a higher amount of moisture in the air, which makes the corrosion process faster.
04

Statement d

Salting roads in the winter has the added benefit of hindering the corrosion of steel. False. Salting roads in the winter actually accelerates the corrosion of steel. The salt lowers the freezing point of water, allowing the presence of more liquid water. Additionally, dissolved salt increases the conductivity of the water, providing a more conducive environment for the electrochemical corrosion process to occur.
05

Statement e

The key to cathodic protection is to connect via a wire a metal more easily oxidized than iron to the steel surface to be protected. True. Cathodic protection is a method used to prevent corrosion by making the metal surface serve as the cathode in a galvanic cell. By connecting a more easily oxidized metal (known as the sacrificial anode) to the steel surface via a wire, the sacrificial anode gets oxidized instead of the iron, thus protecting the steel from corrosion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Galvanic Process
Corrosion of steel is often misunderstood as an electrolytic process, when in fact, it is an example of a galvanic process. Unlike electrolytic processes, a galvanic process does not require an external power source to drive the reaction. Instead, it occurs naturally when two different metals, or areas on a piece of metal that have dissimilar potentials, come into contact in the presence of an electrolyte, such as water containing dissolved oxygen and ions.

A simple example of a galvanic cell involves a piece of steel connected to a piece of a more noble metal like copper. In this cell, steel acts as the anode, corroding over time, while the copper acts as the cathode and remains protected. The electrolyte facilitates the movement of ions allowing the circuit to complete, while the electron flow from steel to copper is what drives the reaction forward. Understanding this spontaneous electrochemical process is crucial in creating prevention strategies for the corrosion of steel.
Cathodic Protection
Cathodic protection is a highly effective method to prevent steel corrosion. It involves transforming the steel into the cathode of an electrochemical cell. By attaching a more reactive metal, known as the sacrificial anode, to the steel, the anode will preferentially corrode instead of the steel. The steel is thus 'protected' as it now becomes the cathode.

Sacrificial Anodes

Common sacrificial anodes are made of zinc, magnesium, or aluminum, all of which are more anodic than iron. They will corrode, or 'sacrifice' themselves, to protect the steel. This technique is widely used in protecting pipelines, ship hulls, and water heaters. Proper monitoring and replacement of the sacrificial anodes are necessary to ensure ongoing protection, as they will eventually corrode completely.
Electrochemical Corrosion
Electrochemical corrosion is the gradual deterioration of metal as a result of chemical reactions between it and its environment. It is a natural occurrence where metal atoms lose electrons and form positive ions, often leading to rust in the case of iron or steel.

Rusting, the most common form of electrochemical corrosion, is accelerated by the presence of electrolytes such as saltwater, which increases the conductivity and enables the redox reaction to occur more readily. Factors such as pH, temperature, and environmental conditions like humidity also influence the rate of this corrosion.

Role of Environments

The higher humidity in areas like the Midwest of the United States creates a more conducive environment for rust to form than the dry Southwest. Similarly, salting roads in winter does not help to prevent rust; it actually lowers the freezing point of water, allows liquid brine to form, and significantly accelerates the electrochemical reaction that leads to steel corrosion.

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Most popular questions from this chapter

Three electrochemical cells were connected in series so that the same quantity of electrical current passes through all three cells. In the first cell, 1.15 g chromium metal was deposited from a chromium(III) nitrate solution. In the second cell, 3.15 g osmium was deposited from a solution made of \(\mathrm{Os}^{n+}\) and nitrate ions. What is the name of the salt? In the third cell, the electrical charge passed through a solution containing \(\mathrm{X}^{2+}\) ions caused deposition of \(2.11 \mathrm{g}\) metallic \(\mathrm{X}\). What is the electron configuration of X?

Sketch the galvanic cells based on the following half-reactions. Show the direction of electron flow, show the direction of ion migration through the salt bridge, and identify the cathode and anode. Give the overall balanced equation, and determine \(\mathscr{C}^{\circ}\) for the galvanic cells. Assume that all concentrations are \(1.0 M\) and that all partial pressures are 1.0 atm. a. \(\mathrm{H}_{2} \mathrm{O}_{2}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{H}_{2} \mathrm{O} \quad \mathscr{E}^{\circ}=1.78 \mathrm{V}\) \(\mathrm{O}_{2}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_{2} \mathrm{O}_{2} \quad \quad \mathscr{E}^{\circ}=0.68 \mathrm{V}\) b. \(\mathrm{Mn}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Mn} \quad \mathscr{E}^{\circ}=-1.18 \mathrm{V}\) \(\mathrm{Fe}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{Fe} \quad \mathscr{E}^{\circ}=-0.036 \mathrm{V}\)

Gold metal will not dissolve in either concentrated nitric acid or concentrated hydrochloric acid. It will dissolve, however, in aqua regia, a mixture of the two concentrated acids. The products of the reaction are the \(\mathrm{AuCl}_{4}^{-}\) ion and gaseous NO. Write a balanced equation for the dissolution of gold in aqua regia.

Copper can be plated onto a spoon by placing the spoon in an acidic solution of \(\mathrm{CuSO}_{4}(a q)\) and connecting it to a copper strip via a power source as illustrated below: a. Label the anode and cathode, and describe the direction of the electron flow. b. Write out the chemical equations for the reactions that occur at each electrode.

A galvanic cell is based on the following half-reactions: $$\begin{array}{cl} \mathrm{Ag}^{+}+\mathrm{e}^{-} \longrightarrow \mathrm{Ag}(s) & \mathscr{E}^{\circ}=0.80 \mathrm{V} \\ \mathrm{Cu}^{2+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Cu}(s) & \mathscr{E}^{\circ}=0.34 \mathrm{V} \end{array}$$ In this cell, the silver compartment contains a silver electrode and excess \(\mathrm{AgCl}(s)\left(K_{\mathrm{sp}}=1.6 \times 10^{-10}\right),\) and the copper compartment contains a copper electrode and \(\left[\mathrm{Cu}^{2+}\right]=2.0 \mathrm{M}\) a. Calculate the potential for this cell at \(25^{\circ} \mathrm{C}\) b. Assuming \(1.0 \mathrm{L}\) of \(2.0 \mathrm{M}\space \mathrm{Cu}^{2+}\) in the copper compartment, calculate the moles of \(\mathrm{NH}_{3}\) that would have to be added to give a cell potential of \(0.52 \mathrm{V}\) at \(25^{\circ} \mathrm{C}\) (assume no volume change on addition of \(\mathrm{NH}_{3}\) ). $$\begin{aligned} \mathrm{Cu}^{2+}(a q)+4 \mathrm{NH}_{3}(a q) & \rightleftharpoons \ \mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}^{2+}(a q) & K=1.0 \times 10^{13} \end{aligned}$$

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